tìm x, y biết
(y -3)2014 + |2x +1|2015 =0
tim x, y biết
(y -3) 2014 + | 2x +1|2015 =0
Tìm x ; y biết : ( y - 3 )\(^{2014}\) + |2x + 1|\(^{2015}\) = 0
Ta có:\(\hept{\begin{cases}\left(y-3\right)^{2014}\ge0\\\left|2x+1\right|^{2015}\ge0\end{cases}}\)\(\Rightarrow\left(y-3\right)^{2014}+\left|2x+1\right|^{2015}\ge0\)
Dấu "=" xảy ra khi \(\hept{\begin{cases}\left(y-3\right)^{2014}=0\\\left|2x+1\right|^{2015}=0\end{cases}}\)
\(\Rightarrow\hept{\begin{cases}y-3=0\\2x+1=0\end{cases}}\)\(\Rightarrow\hept{\begin{cases}y=3\\x=-\frac{1}{2}\end{cases}}\)
Ta có: (y-3)2014 \(\ge\)0 và |2x+1|2015 \(\ge\)0
Mà (y-3)2014 + |2x+1|2015 = 0 => (y-3)2014 = 0 và |2x+1|2015 = 0
=> y - 3 = 0 và 2x + 1 = 0
=> y = 3 và 2x = -1
=> y = 3 và x = -1/2.
Vậy y = 3 và x = -1/2.
Vì (y-3)2014lớn hơn hoặc =0 với mọi y
|2x+1|2015 lớn hơn hoặc =0 với mọi x
=> (y-3)2014+|2x+1|2015 lớn hơn hoặc =0 với mọi x,y
Mà (y-3)2014+|2x+1|2015=0
=> (y-3)2014=0 và |2x+1|2015=0
<=> y-3=0 và |2x+1|=0
<=>y=3 và 2x+1=0
<=>y=3 và 2x=-1
<=>y=3 và x=-1/2
Vậy y=3; x=-1/2
Tìm x ; y biết : |x+1|3 + (y+2015)2014=0
Tìm x biết: a) (2x-3)2012+(y-\(\frac{2}{5}\))2014+|x+y-z|=0
b) 2015-|x-2015|=x
c) 5-|3-x|=2x+9
d) |x-999|+|1998-2x|=0
e) |x-1004|+|2008-2x|=0
a: \(\left(2x-3\right)^{2012}+\left(y-\dfrac{2}{5}\right)^{2014}+\left|x+y-z\right|=0\)
\(\Leftrightarrow\left\{{}\begin{matrix}2x-3=0\\y-\dfrac{2}{5}=0\\x+y-z=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=\dfrac{3}{2}\\y=\dfrac{2}{5}\\z=\dfrac{19}{10}\end{matrix}\right.\)
b: 2015-|x-2015|=x
=>|x-2015|=2015-x
=>x-2015<=0
hay x<=2015
d: |x-999|+|1998-2x|=0
=>x-999=0
hay x=999
tìm x ; y biết |x-3|^2014+|6+2y|2015<=0
Ta có:/x-3/^2014>=0;/6+2y/^2015>=0
=>/x-3/^2014+/6+2y/^2015>=0
mà theo đề bài, /x-3/^2014+/6+2y/^2015<=0
=>/x-3/^2014=/6+2y/^2015=0
=>/x-3/=0; /6+2y/=0
=>x-3=0 =>6+2y=0
=>x=3 =>2y=-6=>y=-3
vậy x=3; y=-3
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Tìm x;y biết |x-3|^2014+| 6+2y|^2015<0
Tìm các gtrị x,y thoả mãn |2x-3y|^2015+(x+y-5)^2014=0
a) Tìm x,y biết : I x+y-2I + I x-y-2I < hoặc = 0
b) Tìm x,y,z biết: z-15y/3 =15x-3z/8 =3y-8x/15 và 2x-y+z =13
c) Tìm số nguyên x, biết: x+ (x+1) +(x+2) +...+ 2017 =0. Biết vế trái là tổng các số nguyên liên tiếp
e) Tìm x biết: x-1/2017 + x-2/2016 - x-3/2015 = x-4/2014
f) Tìm x nguyên để
\(\sqrt{x+1}\) chia hết cho \(\sqrt{x-3}\)
f)
\(A=\sqrt{\frac{\left(x+1\right)}{x-3}}=\sqrt{1+\frac{4}{x-3}}\)
x-3={-4)=> x=-1
Tìm x;y biết
/x-3/ ^ 2014 + /6+2y/^2015 lớn hơn hoặc bằng 0