\(4\cdot\left(5-x\right)-2^3=2^4\cdot3\)

\(\Rightarrow4\cdot\left(5-x\right)-2^3=16\cdot3\)

\(\Rightarrow4\cdot\left(5-x\right)-2^3=48\)

\(\Rightarrow4\cdot\left(5-x\right)=48+8\)

\(\Rightarrow4\cdot\left(5-x\right)=56\)

\(\Rightarrow5-x=56:4\)

\(\Rightarrow5-x=14\)

\(\Rightarrow x=5-14\)

\(\Rightarrow x=-9\)

\(4\left(x-5\right)-23=24\cdot3\)

\(4\left(x-5\right)-23=72\)

\(4\left(x-5\right)=72+23\)

\(4\left(x-5\right)=95\)

\(x-5=\dfrac{95}{4}\)

\(x=\dfrac{95}{4}+5\)

\(x=\dfrac{115}{4}\)

\(4(x–5)-23=24.3\)

\(4(x–5)-23=72\)

\(4(x–5)=72+23\)

\(4(x-5)=95\)

\(x-5=95:4\)

\(x-5=23,75\)

\(x=23,75+5\)

\(x=28,75\)

4 ( x - 5 ) - 23 = 24 . 3

=> 4(x-5)-23=72

=> 4(x-5)=72+23

=> 4(x-5)=95

=> x-5=95/4

=> x-5 = 23,75

=> x = 23,75 + 5

=>x = 28,75

Đáp án cần chọn là: C

\(4\left(x-5\right)-16=24\cdot3\)

\(\Rightarrow4\left(x-5\right)-16=72\)

\(\Rightarrow4\left(x-5\right)=72+16\)

\(\Rightarrow4\left(x-5\right)=88\)

\(\Rightarrow x-5=\dfrac{88}{4}\)

\(\Rightarrow x-5=22\)

\(\Rightarrow x=22+5\)

\(\Rightarrow x=27\)

\(4.\left(x-5\right)-16=24.3\)

\(4.\left(x-5\right)-16=72\)

\(4.\left(x-5\right)=72+16\)

\(4.x-5=88\)

\(x-5=88:4\)

\(x-5=22\)

\(x=22+5\)

\(x=27\)

$4.\left(x-5\right)-16=24.3$

$4.\left(x-5\right)-16=72$

$4.\left(x-5\right)=72+16$

$4.x-5=88$

$x-5=88:4$

$x-5=22$

$x=22+5$

$x=27$

240-[23+(13+24.3-x)]=132

240-[23+(13+168-x)]=132

240-[23+(181-x)]=132

|

x-8:4-(46-23.2+6.3)=0

\(x-8:4-\left(46-23.2+6.3\right)=0\)

\(x-2-\left(46-46+18\right)=0\)

\(x-2-18=0\)

\(x-2=0+18\)

\(x-2=18\)

\(x=18+2\)

\(x=20\)

\(240-\left[23+\left(13+24.3-x\right)\right]=132\)

\(240\left[23+\left(13+82-x\right)\right]=132\)

\(23+\left(95-x\right)=132:240\)

\(23+\left(95-x\right)=\frac{132}{240}=\frac{11}{30}\)

\(23+\left(95-x\right)=\frac{11}{30}\)

\(95-x=\frac{11}{30}-23\)

\(95-x=\frac{11}{30}-\frac{690}{30}\)

\(95-x=-\frac{679}{30}\)

\(x=95+\frac{679}{30}\)

\(x=\frac{2850}{30}+\frac{679}{30}\)

\(x=\frac{3529}{30}=\)tự rút gọn ( nếu có thể )

= [3^6.(3+24)]:3^4
= (3^6.27) : 3^4
= 3^9 : 3^4
= 3^5
= 243

em lá bin si ghss

Ta có: \(\left(-\dfrac{3}{2}\right)^3+\dfrac{-49}{24}\cdot\dfrac{3}{14}-\left(\dfrac{5}{8}-\dfrac{27}{8}\right)\)

\(=\dfrac{-27}{8}+\dfrac{-7}{2}\cdot\dfrac{1}{8}-\dfrac{-22}{8}\)

\(=\dfrac{-27+22}{8}+\dfrac{-7}{16}\)

\(=\dfrac{-5}{8}+\dfrac{-7}{16}\)

\(=\dfrac{-10}{16}+\dfrac{-7}{16}\)

\(=\dfrac{-17}{16}\)