xin lỗi các bạn mình ko bết viết phân số nên viết thế này mọi người thông cảm và giải hộ mình nhé! CẢM ƠN MỌI NGƯỜI

\(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}\)

\(=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.5.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.7}\)

\(=\frac{2^{10}.3^8-2^{10}.3^9.5}{2^{10}.3^8+2^{10}.3^8.7}\)

\(=\frac{2^{10}.3^8\left(1-3.5\right)}{2^{10}.3^8\left(1+7\right)}=\frac{-14}{8}=-\frac{7}{4}\)

Vậy : \(\frac{4^5.9^4-10.6^9}{2^{10}.3^8+6^8.28}=-\frac{7}{4}\)

\(\frac{^{4^5.9^4-10.6^9}}{2^{10}.3^8+6^8.28}=\frac{2^{10}.3^8-5.2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.7}=\frac{2^{10}.3^8\left(1-15\right)}{2^{10}.3^8\left(1+7\right)}=\frac{-14}{8}\)

\(\dfrac{4^5\cdot9^4-2\cdot6^9}{2^{10}\cdot3^8+6^{10}}\)

\(=\dfrac{2^{10}\cdot3^8-2^{10}\cdot3^9}{2^{10}\cdot3^8+2^{10}\cdot3^{10}}\)

\(=\dfrac{2^{10}\cdot3^8\left(1-3\right)}{2^{10}\cdot3^8\left(1+3^2\right)}=-\dfrac{2}{10}=-\dfrac{1}{5}\)

\(\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^{10}}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^{10}}\)

\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^{10}.3^{10}}\)

\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8.\left(1+3^2\right)}\)

\(=\dfrac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.10}\)

\(=\dfrac{-2}{10}\)

\(=\dfrac{-1}{5}\)

Hơi khó đọc qué ah.

\(\frac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}=\frac{\left(2^2\right)^5.\left(3^2\right)^4-2.\left(2.3\right)^9}{2^{10}.3^8+\left(2.3\right)^8.2^2.5}\)

                            \(=\frac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)

                              \(=\frac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)

                                \(=\frac{2^{10}.3^8.\left(1-3\right)}{2^{10}.3^8.\left(1+5\right)}\)

                                 \(=\frac{-2}{6}=\frac{-1}{3}\)

tự làm cho giỏi

Đề bài yêu cầu gì?

\(A=\dfrac{4^5.9^4-2.6^9}{2^{10}.3^8+6^8.20}\)
\(=\dfrac{2^{10}.3^8-2.2^9.3^9}{2^{10}.3^8+2^8.3^8.2^2.5}\)
\(=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}\)
\(=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}\)
\(=-\dfrac{2}{6}=-\dfrac{1}{3}\)

\(=\dfrac{\left(2^2\right)^5.\left(3^2\right)^4-2.3^9.2^9}{2^{10}.3^8+2^8.3^8.2^2.5}=\dfrac{2^{10}.3^8-2^{10}.3^9}{2^{10}.3^8+2^{10}.3^8.5}=\dfrac{2^{10}.3^8\left(1-3\right)}{2^{10}.3^8\left(1+5\right)}=\dfrac{-2}{6}=-\dfrac{1}{3}\)

\(=\dfrac{2.3^9.2^9-\left(2^2\right)^5.\left(3^2\right)^4}{2^{10}.3^7+3^7.2^7.2^3.5}\\ =\dfrac{2^{10}.3^9-2^{10}.3^8}{2^{10}.3^7+3^7.2^{10}.5}\\ =\dfrac{2^{10}.3^8\left(3-1\right)}{2^{10}.3^7\left(1+5\right)}\\ =\dfrac{3.2}{6}=\dfrac{6}{6}=1\)

Dễ ợt bằng 2 phần 3

\(\frac{2}{3}\) đúng luôn