Các bn ơi giúp mn câu này zới,gấp lắm
\(\frac{11.3^{2.2}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
Những câu hỏi liên quan
A = \(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\frac{11.3^{22}.3^7-9^{15}}{^{ }\left(2.3^{14}\right)^2}\)
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)=?
Tính
A=\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^2^2.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(B=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}.\left(11-3\right)}{4.3^{28}}=\frac{3^{29}.8}{4.3^{28}}=\frac{3.2.3^{28}.4}{4.3^{28}}=3.2=6\)
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\(A=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^{29}-\left(3^2\right)^{15}}{2^2.3^{14.2}}\)
\(=\frac{11.3^{29}-3.3^{29}}{2^2.3^{28}}\)
\(=\frac{\left(11-3\right).3^{29}}{2^2.3^{28}}\)
\(=\frac{8.3^{29}}{4.3^{28}}\)
\(=6\)
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\(\left(11.3^7.9^7-9^{15}\right):\left(2.3^{14}\right)^2\)
\(=\dfrac{11\cdot3^{21}-3^{30}}{2^2\cdot3^{28}}=\dfrac{3^{21}\left(11-3^7\right)}{2^2\cdot3^{28}}=\dfrac{-2176}{2^2\cdot3^7}=\dfrac{-2176}{8748}=\dfrac{-544}{2187}\)
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Tính :
A = \(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
A=\(\dfrac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\dfrac{11.3^{29}-3^{29}.3}{2^2.3^{28}}=\dfrac{3^{29}.\left(11-3\right)}{2^2.3^{28}}=\dfrac{3^{29}.2^3}{2^2.3^{28}}=3.2=6\)
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\(A=\dfrac{11\cdot3^{22}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}=\dfrac{11\cdot3^{29}-3^{30}}{2^2\cdot3^{28}}\)
\(=\dfrac{3^{29}\cdot2^3}{3^{28}\cdot2^2}=3\cdot2=6\)
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