\(\frac{11.3^{2.2}.3^7-9^{15}}{\left(2.3^{14}\right)^2}\)
\(=\frac{11.3^4.3^7-\left(3^2\right)^{15}}{2^2.3^{28}}\)
\(=\frac{11.3^{11}-3^{30}}{2^2.3^{28}}\)
\(=\frac{3^{11}.\left(11-3^{19}\right)}{2^2.3^{28}}\)
\(=\frac{11-3^{19}}{2^2.3^{17}}\)
Bạn Châu làm đúng rồi !
Tuy nhiên bạn My lại đề bài nhé!
Tham khảo đề và bài làm:
\(\frac{11.3^{22}.3^7-9^{15}}{\left(2.3^{14}\right)^2}=\frac{11.3^{22+7}-\left(3^2\right)^{15}}{2^2.3^{14.2}}\)
\(=\frac{11.3^{29}-3^{30}}{2^2.3^{28}}=\frac{3^{29}\left(11-3\right)}{2^2.3^{28}}=\frac{3.8}{2^2}=6\)
\(\frac{11\cdot3^{2\cdot2}\cdot3^7-9^{15}}{\left(2\cdot3^{14}\right)^2}\)
\(=\frac{11\cdot3^4\cdot3^7-9^{15}}{2^2\cdot3^{28}}\)
\(=\frac{11\cdot3^{11}-3^{30}}{2^2\cdot3^{28}}\)
\(=\frac{3^{11}\cdot\left(11-3^{19}\right)}{2^2\cdot3^{28}}\)
\(=\frac{11-3^{19}}{2^2\cdot3^{17}}\)
\(=\frac{11-1162261467}{4\cdot129140163}\)
\(=\frac{-1162261456}{516560652}\)
\(=-2,2499979\)
kt lại đề đi bạn
