thu gọn các tổng :
A=2^100 - 2^99 +2^98 - 2^97 +...+ 2^2 - 2
B= 3^100 - 3^99 + 3^98 - 3^97 +...+ 3^2 - 3 +1
Những câu hỏi liên quan
Thu gọn tổng sau:
a) A=1+3+3^2+...+3^100
b) B=2^100-2^99+2^98-2^97+...+2^2-2
c) C=3^100-3^99+3^98-3^97+...+3^2-3+1
a) A =1+3+32+33+...+3100
3A = 3 + 32+33+...+3101
3A-A=( 3 + 32+33+...+3101)-(1+3+32+33+...+3100)
2A = 3101-1
A = \(\frac{3^{101}-1}{2}\)
Thùy An làm sai rùi
Đúng 0
Bình luận (0)
a) A=1+3+3^2+...+3^100
3A=3+3^2+....+3^101
3A-A=1+3^101
A=(1+3^101)/2
Đúng 0
Bình luận (0)
a) A=1+3+32+...+3100
3A= 3+32+...+3100+3101
3A-A=3101-1
2A=3101-1
A=(3101-1):2
Đúng 0
Bình luận (0)
Thu gọn tổng sau :
a) \(A=1+3+3^2+3^3+...+3^{100}\)
b) \(B=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
c) \(C=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3+1\)
bn nào bt lm lm giúp mk vs
Lời giải:
a) \(A=1+3+3^2+3^3+...+3^{100}\)
\(\Rightarrow 3A=3+3^2+3^3+...+3^{101}\)
Trừ theo vế:
\(\Rightarrow 3A-A=(3+3^2+3^3+..+3^{101})-(1+3+3^2+...+3^{100})\)
\(2A=3^{101}-1\Rightarrow A=\frac{3^{101}-1}{2}\)
b) \(B=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
\(\Rightarrow 2B=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2\)
Cộng theo vế:
\(\Rightarrow B+2B=2^{201}-2\)
\(\Rightarrow B=\frac{2^{101}-2}{3}\)
Đúng 0
Bình luận (0)
c) Ta có:
\(C=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3+1\)
\(\Rightarrow 3C=3^{101}-3^{100}+3^{99}-3^{98}+...+3^3-3^2+3\)
Cộng theo vế:
\(C+3C=(3^{100}-3^{99}+3^{98}-....+3^2-3+1)+(3^{101}-3^{100}+3^{99}-....+3^3-3^2+3)\)
\(4C=3^{101}+1\Rightarrow C=\frac{3^{101}+1}{4}\)
Đúng 0
Bình luận (0)
Thu gọn tổng sau :
a) \(A=1+3+3^2+3^3+...+3^{100}\)
b) \(B=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
c) \(C=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3+1\)
bn nào bt lm lm giúp mk vs
a: \(3A=3+3^2+...+3^{101}\)
\(\Leftrightarrow2A=3^{101}-1\)
hay \(A=\dfrac{3^{101}-1}{2}\)
b: \(2B=2^{101}-2^{100}+...+2^3-2^2\)
\(\Leftrightarrow3B=2^{101}-2\)
hay \(B=\dfrac{2^{101}-2}{3}\)
c: \(3C=3^{101}-3^{100}+....+3^3-3^2+3\)
=>\(4C=3^{101}+1\)
hay \(C=\dfrac{3^{101}+1}{4}\)
Đúng 0
Bình luận (0)
Rút gọn biểu thức
b) B=2^100-2^99+2^98-2^97+...+2^2-2
c) C=3^100-3^99+3^98-3^97+...+3^2-3+1
b) B = 2100 - 299 + 298 - 297 + ...+ 22 - 2
=> B x 2 = 2101 - 2100 + 299 - 298 + ...23 - 22
=> B x 2 + B = (2101 - 2100 + 299 - 298 + ...23 - 22 ) + (2100 - 299 + 298 - 297 + ...+ 22 - 2)
<=> B x 3 = 2101 - 2 = 2. ( 299 - 1)
=> B = \(\frac{2.\left(2^{99}-1\right)}{3}\)
Phần c) Làm tương tự Lấy C x 3 rồi + với C.
Đúng 2
Bình luận (0)
Rút gọn:
a/ A=2^100-2^99+2^98-2^97+............+2^2-2
b/ B=3^100-3^99+3^98-3^97+..............+3^2-3+1
Ai nhanh nhất là đúng nhất mk tick cho
\(A=2^{100}-2^{99}+2^{98}-2^{97}+....+2^2-2\)
\(2A=2^{101}-2^{100}+2^{99}-2^{98}+....+2^3-2^2\)
\(2A+A=2^{101}-2\)
\(A=\frac{2^{101}-2}{3}\)
b) tương tự
\(B=\frac{3^{101}+1}{4}\)
Đúng 0
Bình luận (0)
Rút gọn:
a) \(A=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
b) \(B=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3+1\)
A = 2100 - 299 + 298 - 297 + ... + 22 - 2
= ( 2100 + 298 + ... + 22 ) - ( 299 + 297 + ... + 2 )
= ( 2100 + 298 + ... + 22 ) - 2( 299 + 297 + ... + 2 ) + ( 299 + 297 + ... + 2 )
= 299 + 297 + ... + 2
=> 4A = 2103 + 299 + ... + 23
=> 3A = 2103 - 2
=> A = \(\frac{2^{103}-2}{3}\)
Đúng 0
Bình luận (0)
1.Rút gọn:
\(A=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
\(B=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3\)
a) \(A=2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
\(2A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2\)
\(\Rightarrow A+2A=2^{101}-2\)
\(A\left(1+2\right)=2^{101}-2\)
\(A.3=2^{101}-2\)
\(A=\frac{2^{101}-2}{3}\)
b) \(B=3^{100}-3^{99}+3^{98}-3^{97}+...+3^2-3\)
\(3B=3^{101}-3^{100}+3^{99}-3^{98}+...+3^3-3^2\)
\(\Rightarrow B+3B=3^{101}-3\)
\(B\left(1+3\right)=3^{101}-3\)
\(4B=3^{101}-3\)
\(B=\frac{3^{101}-3}{4}\)
Đúng 1
Bình luận (0)
Rút gọn :
\(A=2^{100}-2^{99}+2^{98}-2^{97}.............+2^2-2\)
\(B=3^{100}-3^{99}+3^{98}-3^{97}.........+3^2-3+1\)
a, \(A=...\)
=>\(2A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2\)
=>\(2A+A=2^{101}-2^{100}+2^{99}-2^{98}+...+2^3-2^2+2^{100}-2^{99}+2^{98}-2^{97}+...+2^2-2\)
=>\(3A=2^{101}-2\)
=>\(A=\frac{2^{101}-2}{3}\)
b, tương tự a \(B=\frac{3^{101}+1}{4}\)
Đúng 0
Bình luận (0)
2^100-2^99+2^98-2^97+...+2^2-2
3^100-3^99+3^98-3^97+...+3^2-3+1
Giúp với các bạn ơi!!!
