\(15:\left(x+2\right)=3\)

\(\Rightarrow x+2=15:3=5\)

\(\Rightarrow x=5-2=3\)

15:(x+2)=3

nên x+2=5

hay x=3

`15  : (x+2) = 3`

`<=>x + 2 = 5`

`<=> x =3`

\(A=\dfrac{x}{\left(x+2022\right)^2}=\dfrac{x}{x^2+4044x+2022^2}=\dfrac{1}{x+4044+\dfrac{2022^2}{x}}=\dfrac{1}{\left(x+\dfrac{2022^2}{x}\right)+4044}\le\dfrac{1}{2.\sqrt{x}.\sqrt{\dfrac{2022^2}{x}}+4044}=\dfrac{1}{2..\sqrt{\dfrac{x.2022^2}{x}}+4044}=\dfrac{1}{4044+4044}=\dfrac{1}{8088}\)-\(A_{max}=\dfrac{1}{8088}\Leftrightarrow x=2022\)

\(A:29^{1023}=29^{6.170+3}=\left(29^6\right)^{170}.29^3\)

\(\equiv1^{170}.9\left(mod\text{ 10}\right)\)

\(\equiv9\)

Vậy chữ số tận cùng ...

\(B:117^{2046}=117^{4.511+2}=\left(117^4\right)^{511}.117^2\)

\(\equiv1^{511}.9\left(mod\text{ 10}\right)\)

\(\equiv9\)

\(C:2024^{2015}\)

\(\equiv4^{2015}\left(mod\text{ 10}\right)=4^{15.134+5}\)

\(\equiv4^{134}.4\left(mod10\right)=4^{15.9-1}.4\)

\(\equiv4^9\equiv4\left(mod10\right)\)

A=29¹⁰²³=29^2.511+1=29^2.511.29=(29²)⁵¹¹.29=A1⁵¹¹.29=C1.29=B9

B=117²⁰⁴⁶=117^4.511+2=(117⁴)⁵¹¹.117²=A1.B9=C9

C=2024²⁰¹⁵=2024^2.1007+2=(2024²)¹⁰⁰⁷.2024²=A6¹⁰⁰⁷.B6=C6.B6=E6

Ko hiểu thì nói mk nhak

\(\left|3x-2\right|-5\ge-5\forall x\)

Dấu '=' xảy ra khi x=2/3

a) 7x³ - 5x² 

= x²( 7x - 5 )

b) x² - 10x + 25

= x² - 2.5.x + 5²

= ( x - 5 )²

a, 7x³-5x²

=x²(7x-5)

b, x²-10x+25

=x²-2.x.5+5²

=(x-5)²

Ta có:\(7x^3-5x^2=x^2\left(7x-5\right)\)

          \(x^2-10x+25=\left(x-5\right)^2\)

Những từ Hán Việt là : Nhức nhối