\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(1+x\right)\)

\(=4x^2\left(x+1\right)\left(x-1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=\left(x+1\right)4\left[x^2\left(x-1\right)-4\right]\)

Nguyễn Văn Tuấn AnhNs r, không biết thì not làm

\(4x^4-16-4x^2-16x\)

\(=4x^2\left(x^2-1\right)-16\left(x+1\right)\)

\(=4x^2\left(x-1\right)\left(x+1\right)-16\left(x+1\right)\)

\(=\left(x+1\right)\left[4x^2\left(x-1\right)-16\right]\)

\(=4\left(x+1\right)\left[x^2\left(x-1\right)-4\right]\)

\(=4\left(x+1\right)\left[x^3-x^2-4\right]\)

\(=4\left(x+1\right)\left[x^3+x^2+2x-2x^2-2x-4\right]\)

\(=4\left(x+1\right)\left[x\left(x^2+x+2\right)-2\left(x^2+x+2\right)\right]\)

\(=4\left(x+1\right)\left(x-2\right)\left(x^2+x+2\right)\)

๖ۣۜMαɾαƙαĭ ⁹⁀ᶦᵈᵒᶫ  bạn đừng ns thế người ta không biết làm nhưng vẫn cố gắng giúp 

nếu bạn ấy làm sai thì vẫn có những người như bạn sửa

\(4x^2-y^2+8x-16\)

\(=\left(2x\right)^2-\left(y-4\right)^2=\left(2x-y+4\right)\left(2x+y-4\right)\)

4x² - y² + 8y - 16

= 4x² - (y² - 8y + 16)

= (2x)² - (y - 4)²

= [2x - (y - 4)][2x + (y - 4)]

= (2x - y +4)(2x + y - 4)

\(4x^2-4x+1=\left(2x\right)^2-2.2x.1+1^2=\left(2x-1\right)^2\\ ---\\ 4x^2-4x-3\\ =4x^2-4x+1-4\\ =\left(2x-1\right)^2-2^2=\left(2x-1-2\right)\left(2x-1+2\right)\\ =\left(2x-3\right)\left(2x+1\right)\)

1: =(2x)^2-2*2x*1+1^2

=(2x-1)^2

2: =4x^2-6x+2x-3

=2x(2x-3)+(2x-3)

=(2x-3)(2x+1)

= 4 ( x² +4x+4) = 4(x+2)²

bạn ơi 4x^2 là j ạ

\(4xy-4x^2-y^2+16\)

\(=16-\left(4x^2-4xy+y^2\right)\)

\(=16-\left(2x-y\right)^2\)

\(=\left(4+2x-y\right)\left(4-2x+y\right)\)

4x²-y²+4x+1

=(4x²+4x+1)-y²

=(2x+1)²-y²

=(2x+1-y)(2x+1+y)

bài này tớ cũng ko chắc:

\(4x^2-y^2+4x+1=\left(4x+4x^2+1\right)-y^2= \left(2x+1\right)^2-y^2\)

\(=\left(2x+1\right)\left(2x+1\right)-y^2=\left(2x+1-y\right)\left(2x+1+y\right)\)

C1:        \(4x^2-4x+1=\left(2x-1\right)^2\)       (Hằng đẳng thức bạn ạ)

C2:        \(4x^2-4x+1\)

           =\(4x^2-2x-2x+1\)

            =\(2x\left(2x-1\right)-\left(2x-1\right)\) 

             =\(\left(2x-1\right)\left(2x-1\right)\)

               =\(\left(2x-1\right)^2\) 

Mình chắc 100% đó .     **** mình bạn na !!!

\(x^3+4x^2+4x+1\)

\(=x^3+3x^2+x+x^2+3x+1\)

\(=x\left(x^2+3x+1\right)+\left(x^2+3x+1\right)\)

\(=\left(x+1\right)\left(x^2+3x+1\right)\)

 = ( x - y)^2 - z^2 

= ( x - y -z)(x - y + z) 

= (4x² + 4x+ 1) - y²

=(4x² + 4x +1) -y²

=[(2x)²  + 2.2x.1 +1] - y²

=(2x +1)² - y²

=[(2x +1) -y].[(2x +1) +y]

=(2x +1 -y).(2x +1 +y)

4x^2-y^2+4x+1

=(2x+1)^2-y^2

=(2x+1-y)(2x+1+y)

Sửa đề:

\(4x^2-4x-15\)

\(=4x^2-10x+6x-15\)

\(=\left(2x+3\right)\left(2x-5\right)\)