\(\frac{121212+12121212-1212}{363636-36363636-3636}=\frac{12\left(111111+11111111-1111\right)}{36\left(111111+11111111-1111\right)}=\frac{12}{36}=\frac{1}{3}\)

1/3 nha

\(\frac{1}{3}\)

chúc ban hk tốt!!(k cho tui nhé)

\(\frac{121212+12121212-1212}{363636+36363636-3636}\)

\(=\frac{12.10101+12.1010101-12.101}{36.10101+36.1010101-36.101}\)

\(=\frac{12\left(10101+1010101-101\right)}{36\left(10101+1010101-101\right)}\)

\(=\frac{12}{12.3}\)

\(=\frac{1}{3}\)

Ta có: \(\frac{121212+12121212-1212}{363636+36363636-3636}\)

           =\(\frac{12\times\left(10101+1010101-101\right)}{36\times\left(10101+1010101-101\right)}\)

           =\(\frac{12}{36}\)

           =\(\frac{1}{3}\)

\(\frac{121212+12121212-1212}{363636+36363636-3636}\)

\(=\frac{121212+12121212-1212}{3\times121212+3\times12121212-3\times1212}\)

\(=\frac{121212+12121212-1212}{3\times\left(121212+12121212-1212\right)}\)

\(=\frac{1}{3}\)

_Chúc bạn học tốt_

a,\(\frac{2015.2016+2015-1}{2014+2015.2016}=\frac{2015.2016+2014}{2014+2015.2016}=1\)\(1\)

b,\(=1-\frac{1}{5}+\frac{1}{5}...-\frac{1}{2011}+\frac{1}{2011}-\frac{1}{2015}=1-\frac{1}{2015}=\frac{2014}{2015}\)

c,\(=\frac{12}{35}+\frac{12}{35}+\frac{12}{35}+\frac{12}{35}=\frac{12}{35}.4=\frac{48}{35}\)

48/35 nha

b>=1-1/5+1/5-1/9+...+1/2011-1/2015

 =1-1/2015

=2014/2015

c>=12/35+12/35+12/35+12/35

=12/35x4

=48/35

ai giúp mik với mai phải nộp rồi

\(\dfrac{12}{13}\)= \(\dfrac{12.101}{13.101}\)= \(\dfrac{1212}{1313}\) (1)

\(\dfrac{12}{13}\) = \(\dfrac{12.\left(-10101\right)}{13.\left(-10101\right)}\) = \(\dfrac{-121212}{-131313}\)(2)

Từ (1) và (2) => \(\dfrac{12}{13}=\dfrac{1212}{1313}=\dfrac{-121212}{-131313}\)

\(\dfrac{121212}{212121}\)     <       \(\dfrac{12121212}{21212121}\)

\(\dfrac{121212}{212121}< \dfrac{12121212}{21212121}\)

<

a: \(\dfrac{121212}{212121}=\dfrac{4}{7}\)

\(\dfrac{12121212}{21212121}=\dfrac{4}{7}\)

Do đó: \(\dfrac{121212}{212121}=\dfrac{12121212}{21212121}\)

b: \(2+\dfrac{1}{-50}=\dfrac{99}{50}=1.98>0>-\dfrac{82}{4}\)

a:\(\dfrac{12}{13}\)

b:\(\dfrac{12}{13}\)

c:\(\dfrac{121}{131}\)

Câu a: \(\dfrac{12}{13}\)

Câu b: \(\dfrac{12}{13}\)

Câu c: \(\dfrac{121}{121}\)

\(A=\frac{121212}{363636}+\frac{1212}{3636}\)

\(=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}\)

#)Giải :

\(\frac{121212}{363636}=\frac{121212:10101}{363636:10101}=\frac{12}{36}=\frac{1}{3}\)

\(\frac{1212}{3636}=\frac{1212:101}{3636:101}=\frac{12}{36}=\frac{1}{3}\)

\(\Rightarrow A=\frac{1}{3}+\frac{1}{3}=\frac{2}{3}\)