13246 / x = 1352
Những câu hỏi liên quan
tim x thuocZ :-150(1352-41) / (1352-41)(150-15) < x < (2400:48)-250 / 350-(3600-12)
\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}< x< \frac{2400:48-250}{350-3600:12}\)
tìm x thuộc Z
a, -150(1352-41) / (1352-41)(150-15) <x< (2400:48)-250 / 350 - (3600:12)
b, 10,07 - [ 3,927 - ( 3,63 - 3/20) ] < hoặc bằng x < hoặc bằng 1,5. (9,2-2/5) + (3,2-3,12) (41/10 -2,85 )
Đề là gì vậy bạn, x còn thêm điều kiện gì không như x ∈ Z,...v.v.
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\(\frac{-150.\left(1352-41\right)}{\left(1352-41\right).\left(150-15\right)}< x< \frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
tinh nhanh
2002 x 8648 + 2003 x 1352 - 352
2002 x 8648 + 2002 x 1352 + (1352-352)
=2002 x (8648+1352) + 1000
= 2002 x 10000 +1000
=20020000+1000
=20021000
Nha bạn
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2002 x 8648 + 2003 x 1352 - 352
= 2002 x 8648 + ( 2002 + 1 ) x 1352 - 352
= 2002 x 8648 + 2002 x 1352 + 1352 - 352
= 2002 x ( 8648 + 1352 ) + 1000
= 2002 x 10000 + 1000
= 20020000 + 1000
= 20021000
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2002.8648+2003.1352-352=2002.8648+(2002+1).1352-352=2002.8648+2002.1352+(2002-352)=2002(8648+1352)+1650=2002.10000+1650=20020000+1650=20021650
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1.(x+14)^3-(x+12)^3=1352
2.(x-1)^4+(x+3)^4=32
3.(x+3)×(x+4)×(x+5)=x
3: Đặt x+3=a
Ta có: (x+3)(x+4)(x+5)=x
⇔a(a+1)(a+2)=a-3
⇔\(a^3+3a^2+2a-a+3=0\)
\(\Leftrightarrow a^3+3a^2+a+3=0\)
\(\Leftrightarrow a^2\left(a+3\right)+\left(a+3\right)=0\)
\(\Leftrightarrow\left(a+3\right)\left(a^2+1\right)=0\)(1)
Ta có: \(a^2\ge0\forall a\)
\(\Rightarrow a^2+1\ge1>0\forall a\)(2)
Từ (1) và (2) suy ra a+3=0
hay \(x+6=0\)
⇔x=-6
Vậy: x=-6
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Cần gấp ạ
Tính hợp lý:
A) 420 - ( 71+420)
b) ( 35 - 120 ) + ( 120+410-35)
c) (320 - 15 + 49) - ( 85 - 51)
d) -(312 + 59) - (41 + 400 + 88)
e) (430 - 731) - ( -731 + 430 - 56)
f) (1352 - 47) - ( 53 -1000+ 1352)
h) (-42) - (370 + 58) - ( 120 -370)
a) $420-(71+420)$
$=420-71-420$
$=-71$
b) $(35-120)+(120+410-35)$
$=35-120+120+410-35$
$=(35-35)+(-120+120)+410$
$=410$
c) $(320-15+49)-(85-51)$
$=320-15+49-85+51$
$=320+(-15-85)+(49+51)$
$=320+(-100)+100$
$=320$
d) $-(312+59)-(41+400+88)$
$=-312-59-41-400-88$
$=(-312-88)+(-59-41)-400$
$=-400+(-100)-400$
$=-500-400$
$=-900$
e) $(430-731)-(-731+430-56)$
$=430-731+731-430+56$
$=(430-430)+(-731+731)+56$
$=56$
f) $(1352-47)-(53-1000+1352)$
$=1352-47-53+1000-1352$
$=(1352-1352)+(-47-53)+1000$
$=(-100)+1000$
$=1000-100$
$=900$
h) $(-42)-(370+58)-(120-370)$
$=-42-370-58-120+370$
$=(-42-58)+(-370+370)-120$
$=-100-120$
$=-220$
$Toru$
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Xem thêm câu trả lời
Tìm số nguyên x biết:a)frac{-150left(1352-41right)}{left(1352-41right)left(50-45right)}xfrac{left(2400:48right)-250}{350-left(3600:12right)}b)10,07-[3,927-(3,63-frac{3}{20})lexle1,5 left(9,2-frac{2}{5}right)+(3,2-3,12).(4frac{1}{10}-2,25)
Đọc tiếp
Tìm số nguyên x biết:
a)\(\frac{-150\left(1352-41\right)}{\left(1352-41\right)\left(50-45\right)}\)<x<\(\frac{\left(2400:48\right)-250}{350-\left(3600:12\right)}\)
b)10,07-[3,927-(3,63-\(\frac{3}{20}\))\(\le\)x\(\le\)1,5 \(\left(9,2-\frac{2}{5}\right)\)+(3,2-3,12).(\(4\frac{1}{10}\)-2,25)
Rút gọn:
a,\(\frac{15.\left(1352-41\right)}{\left(1352-41\right)\left(150-15\right)}\)
b,\(\frac{2^{10}.6^{15}+3^{14}.15.4^{13}}{2^{18}.18^7.3^3+3^{15}.2^{25}}\)