a) x3 - x2 - 5x + 125
b) x3 + 2x2 - 6x - 27
c) 12x3 + 4x2 - 27x - 9
d) x4 - 25x2 + 20x - 4
e) x2. (x2 - 6) - x2 + 9
g) x4 - 4x3 + 8x2 - 16x + 16
h) (a + b + c)2 + (a - b + c)2 - 4b2
i) (x2 + 8x - 34)2 - (3x2 - 8x - 2)2
Phân tích đa thức thành nhân tử bằng cách nhóm hạng tử:
a. x2-xz-9y2+3yz
b.x3-x2-5x+125
c.x3+2x2-6x-27
d. 12x3+4x2-27x-9
e.x4-25x2+20x-4
f.x2(x2-6)-x2+9
a) x2-xz-9y2+3yz
=(x2-9y2)-(xz-3yz)
=(x-3y)(x+3y)-z(x-3y)
=(x-3y)(x+3y-z)
b)x3-x2-5x+125
=x3-6x2+25x+5x2-30x+125
=x(x2-6x+25)+5(x2-6x+25)
=(x+5)(x2-6x+25)
c.x3+2x2-6x-27
=x3+5x2+9x-3x2-15x-27
=x(x2+5x+9)-3(x2+5x+9)
=(x-3)(x2+5x+9)
d. 12x3+4x2-27x-9
=12x3+4x2-27x-9
=4x2(3x+1)-9(3x+1)
=(4x2-9)(3x+1)
=(2x-3)(2x+3)(3x+1)
e.x4-25x2+20x-4
=x4+5x3-2x2-5x2-25x+10+2x2+10x-4
=x2(x2+5x-2)-5(x2+5x-2)+2(x2+5x-2)
=(x2-5x+2)(x2+5x-2)
f.x2(x2-6)-x2+9
=x4+x3-3x2-x3-x2+3x-3x2-3x+9
=x2(x2+x-3)-x(x2+x-3)-3(x2+x-3)
=(x2-x-3)(x2+x-3)
a) x2 + 6x + 9 = x2 + 2 . x . 3 + 32 = (x + 3)2
b) 10x – 25 – x2 = -(-10x + 25 +x2) = -(25 – 10x + x2)
= -(52 – 2 . 5 . x – x2) = -(5 – x)2
c) 8x3 - 1/8 = (2x)3 – (1/2)3 = (2x - 1/2)[(2x)2 + 2x . 12 + (1/2)2]
= (2x - 1/2)(4x2 + x + 1/4)
d)1/25x2 – 64y2 = (1/5x)2(1/5x)2- (8y)2 = (1/5x + 8y)(1/5x - 8y)
Bài 2: Phân tích đa thức sau thành nhân tử:
1)x3+2x2-6x-27
2)12x3 +4x2 -27x-9
3)x4 -25x2 +20x -4
Bài 1: Phân tích đa thức sau thành nhân tử:
1)x3 + 2x2 - 6x - 27
2)12x3 + 4x2 - 27x - 9
3)x4 - 25x2 + 20x - 4
Bài 1: Phân tích các đa thức sau thành nhân tử
a. 1 - 4x2
b. 8 - 27x3
c. 27 + 27x + 9x 2 + x3
d. 2x3 + 4x2 + 2x
e. x2 - 5x - y2 + 5y
f. x2 - 6x + 9 - y2
g. 10x (x - y) - 6y(y - x)
h. x2 - 4x - 5
i. x4 - y4
Bài 2: Tìm x, biết
a. 5(x - 2) = x - 2
b. 3(x - 5) = 5 - x
c. (x +2)2 - (x+ 2) (x - 2) = 0
Bài 3: Tìm giá trị nhỏ nhất của biểu thức
a. A = x2 - 6x + 11
b. B = 4x2 - 20x + 101
c. C = -x2 - 4xy + 5y2 + 10x - 22y + 28
a.
\(1-4x^2=\left(1-2x\right)\left(1+2x\right)\)
b.
\(8-27x^3=\left(2\right)^3-\left(3x\right)^3=\left(2-3x\right)\left(4+6x+9x^2\right)\)
c.
\(27+27x+9x^2+x^3=x^3+3.x^2.3+3.3^2.x+3^3\)
\(=\left(x+3\right)^3\)
d.
\(2x^3+4x^2+2x=2x\left(x^2+2x+1\right)=2x\left(x+1\right)^2\)
e.
\(x^2-y^2-5x+5y=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(x+y-5\right)\)
f.
\(x^2-6x+9-y^2=\left(x-3\right)^2-y^2=\left(x-3-y\right)\left(x-3+y\right)\)
g. 10x(x-y)-6y(y-x)
=10x(x-y)+6y(x-y)
=(x-y)(10x+6y)
h.x2-4x-5
=(x-5)(x+1)
i.x4-y4 = (x2-y2)(x2+y2)
B2.
a.5(x-2)=x-2
⇔5(x-2)-(x-2)=0
⇔4(x-2)=0
⇔x=2
b.3(x-5)=5-x
⇔3(x-5)+(x-5)=0
⇔4(x-5)=0
⇔x=5
c.(x+2)2-(x+2)(x-2)=0
⇔(x+2)[(x+2)-(x-2)]=0
⇔4(x+2)=0
⇔x=-2
Phân tích đa thức thành nhân tử:
a) x 2 - 5x + 6; b) 3 x 2 + 9x - 30;
c) 3 x 2 - 5x - 2; d) x 2 -7xy + 10 y 2 ;
e) x 3 -7x-6; g) x 4 + 2 x 3 + 6x - 9;
h) x 2 -2x - y 2 +4y - 3.
a) (x - 2)(x - 3). b) 3(x - 2)(x + 5).
c) (x - 2)(3x + 1). d) (x-2y)(x - 5y).
e) (x + l)(x + 2)(x - 3). g) (x-1)(x + 3)( x 2 + 3).
h) (x + y - 3)(x - y + 1).
Bài 2: Phân tích các đa thức sau thành nhân tử
a) x2 – 9 b) 4x2 -1 c) x4 - 16
d) x2 – 4x + 4 e) x3 – 8 f) x3 + 3x2 + 3x + 1
a) x² - 9
= x² - 3²
= (x - 3)(x + 3)
b) 4x² - 1
= (2x)² - 1²
= (2x - 1)(2x + 1)
c) x⁴ - 16
= (x²)² - 4²
= (x² - 4)(x² + 4)
= (x² - 2²)(x² + 4)
= (x - 2)(x + 2)(x + 4)
d) x² - 4x + 4
= x² - 2.x.2 + 2²
= (x - 2)²
e) x³ - 8
= x³ - 2³
= (x - 2)(x² + 2x + 4)
f) x³ + 3x² + 3x + 1
= x³ + 3.x².1 + 3.x.1² + 1³
= (x + 1)³
A) X3-3x2+3x-1+2(x2-x)
B)12x3+4x2-27x-9
C)X4-25X2+20x-4
Phân tích các đa thức sau thành nhân tử:
a) x2 - 9 - x2 (x2 - 9) d) x2 + 5x + 6 h) a2 + b2 + 2a – 2b – 2ab
b) x2(x-y) + y2(y-x) e) 3x2 – 4x – 4 i) (x + 1)2 – 2(x + 1)(y – 3) + (y – 3)2
c) x3+27+(x+3)(x-9) g) x4 + 64y4 k) x2(x + 1) – 2x(x + 1) + x + 1
Mình đang cần gấp ạ
a: \(x^2-9-x^2\left(x^2-9\right)\)
\(=\left(x^2-9\right)-x^2\left(x^2-9\right)\)
\(=\left(x^2-9\right)\left(1-x^2\right)\)
\(=\left(1-x\right)\left(1+x\right)\left(x-3\right)\left(x+3\right)\)
b: \(x^2\left(x-y\right)+y^2\left(y-x\right)\)
\(=x^2\left(x-y\right)-y^2\left(x-y\right)\)
\(=\left(x-y\right)\left(x^2-y^2\right)\)
\(=\left(x-y\right)\left(x-y\right)\left(x+y\right)=\left(x-y\right)^2\cdot\left(x+y\right)\)
c: \(x^3+27+\left(x+3\right)\left(x-9\right)\)
\(=\left(x+3\right)\left(x^2-3x+9\right)+\left(x+3\right)\left(x-9\right)\)
\(=\left(x+3\right)\left(x^2-3x+9+x-9\right)\)
\(=\left(x+3\right)\left(x^2-2x\right)=x\left(x-2\right)\left(x+3\right)\)
d: \(x^2+5x+6\)
\(=x^2+2x+3x+6\)
\(=x\left(x+2\right)+3\left(x+2\right)=\left(x+2\right)\left(x+3\right)\)
e: \(3x^2-4x-4\)
\(=3x^2-6x+2x-4\)
\(=3x\left(x-2\right)+2\left(x-2\right)\)
\(=\left(x-2\right)\left(3x+2\right)\)
g: \(x^4+64y^4\)
\(=x^4+16x^2y^2+64y^4-16x^2y^2\)
\(=\left(x^2+8y^2\right)^2-\left(4xy\right)^2\)
\(=\left(x^2+8y^2-4xy\right)\left(x^2+8y^2+4xy\right)\)
h: \(a^2+b^2+2a-2b-2ab\)
\(=a^2-2ab+b^2+2a-2b\)
\(=\left(a-b\right)^2+2\left(a-b\right)=\left(a-b\right)\left(a-b+2\right)\)
i: \(\left(x+1\right)^2-2\left(x+1\right)\left(y-3\right)+\left(y-3\right)^2\)
\(=\left(x+1-y+3\right)^2\)
\(=\left(x-y+4\right)^2\)
k: \(x^2\left(x+1\right)-2x\left(x+1\right)+\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2-2x+1\right)\)
\(=\left(x+1\right)\left(x-1\right)^2\)
Bài 1: Phân tích các đa thức sau thành nhân tử
a)x2-y2-2x+2y e)x4+4y4
b)x2(x-1)+16(1-x) f)x4-13x2+36
c)x2+4x-y2+4 g) (x2+x)2+4x2+4x-12
d)x3-3x2-3x+1 h)x6+2x5+x4-2x3-2x2+1
a.
$x^2-y^2-2x+2y=(x^2-y^2)-(2x-2y)=(x-y)(x+y)-2(x-y)=(x-y)(x+y-2)$
b.
$x^2(x-1)+16(1-x)=x^2(x-1)-16(x-1)=(x-1)(x^2-16)=(x-1)(x-4)(x+4)$
c.
$x^2+4x-y^2+4=(x^2+4x+4)-y^2=(x+2)^2-y^2=(x+2-y)(x+2+y)$
d.
$x^3-3x^2-3x+1=(x^3+1)-(3x^2+3x)=(x+1)(x^2-x+1)-3x(x+1)$
$=(x+1)(x^2-4x+1)$
e.
$x^4+4y^4=(x^2)^2+(2y^2)^2+2.x^2.2y^2-4x^2y^2$
$=(x^2+2y^2)^2-(2xy)^2=(x^2+2y^2-2xy)(x^2+2y^2+2xy)$
f.
$x^4-13x^2+36=(x^4-4x^2)-(9x^2-36)$
$=x^2(x^2-4)-9(x^2-4)=(x^2-9)(x^2-4)=(x-3)(x+3)(x-2)(x+2)$
g.
$(x^2+x)^2+4x^2+4x-12=(x^2+x)^2+4(x^2+x)-12$
$=(x^2+x)^2-2(x^2+x)+6(x^2+x)-12$
$=(x^2+x)(x^2+x-2)+6(x^2+x-2)=(x^2+x-2)(x^2+x+6)$
$=[x(x-1)+2(x-1)](x^2+x+6)=(x-1)(x+2)(x^2+x+6)$
h.
$x^6+2x^5+x^4-2x^3-2x^2+1$
$=(x^6+2x^5+x^4)-(2x^3+2x^2)+1$
$=(x^3+x^2)^2-2(x^3+x^2)+1=(x^3+x^2-1)^2$
Ai biết phần nào thì giải giúp mink nhé! cảm ơn!
Phân tích đa thức thành nhân tử:
a, x4 + 2x2 + 1 - x2
b,x4 + x2 + 1
c,y4 + 64
d,4xy +3z - 12y - xz
e,x2 - 4xy + 4y2 - z2 + 6z - 9
g, x2 - 4xy + 5x + 4y2 - 10y
h, x2 - 7x + 6
i, x3 + 5x2 + 6x + 2
a, \(x^4+2x^2+1-x^2\)
= \(\left(x^2+1\right)^2-x^2\)
= \(\left(x^2+x+1\right)\left(x^2-x+1\right)\)
b, \(x^4+x^2+1\)
= \(x^4+2x^2+1-x^2\)
= .. ( như phần a )
c, \(y^4+64\)
= \(\left(y^2+8\right)\left(y^2-8\right)\)
d, \(4xy+3z-12y-xz\)
\(=4y\left(x-3\right)-z\left(x-3\right)\)
\(=\left(x-3\right)\left(4y-z\right)\)
e, \(x^2-4xy+4y^2-z^2+6z-9\)
\(=\left(x-2y\right)^2-\left(z-3\right)^2\)
g, \(x^2-4xy+5x+4y^2-10y\)
\(=\left(x^2-4xy+4y^2\right)+\left(5x-10y\right)\)
\(=\left(x-2y\right)^2+5\left(x-2y\right)\)
\(=\left(x-2y\right)\left(x-2y+5\right)\)
h, \(x^2-7x+6\)
\(=x^2-6x-x+6\)
\(=x\left(x-6\right)-\left(x-6\right)\)
\(=\left(x-6\right)\left(x-1\right)\)
i, \(x^3+5x^2+6x+2\)
\(=x^3+x^2+4x^2+4x+2x+2\)
\(=x^2\left(x+1\right)+4x\left(x+1\right)+2\left(x+1\right)\)
\(=\left(x+1\right)\left(x^2+4x+2\right)\)