a) 125.3+125.125.6

=125.3+125.750

=125.(3+750)

=125.753

=94125

b) (245.99+245)-(145.101-145)

=(245.(99+1))-(145.(101-1))

=245.100-145.100

=(245-145).100

=100.100

=10000

c) 154.(28+52)-45.(26+54)

=154.80-45.80

=(154-45).80

=109.80

=8720

a) 125x3+125+125x6

=125x(3+1+6)

=125x10

=1250

b) (245x99+245)-(145x101-145)

=(245x99+245)-(145x100)

=(245x100)-14500

=24500-14500

10000

c) 154x80-45x80

=80x(145-45)

=80x100

=8000

a, 125 x 3 + 125 x 125 x 6

=125 x 3 + 125 x 750

=125 x( 3+750)

=125 x753

=94125

b, ( 245 x 99 + 245 ) - ( 145 x 101 - 145 )

=[245 x ( 99+1 )] - [145 x ( 101-1 )]

=( 245 x 100 ) - ( 145 x 100 )

=24500 - 14500

=10 000

c, 154 x ( 28 + 52 ) - 45 x ( 26 + 54 )

=154 x 80 - 45 x 80

=(154-45)x80

=109 x80

=8720

a,[120-12*5]:6

    =[120-60]:6

    =60:6

     =10

b,494-[75+35:5]*2

=494-[75+7]*2

=494-82*2

=494-164

=330

c,1/4+[3/4:1/2]*5/6

=1/4+3/2*5/6

=1/4+5/4

=3/3

d,[360-15*6]:5

=[360-90]:5

=270:5

=54

a) (120-12*5):6= (120-60):6=60:6=10

b) 494-(75+35:5)*2= 494-(75+7)*2=494-82*2=494-164=330

c)1/4+(3/4:1/2)*5/6=1/4+3/2*5/6=1/4+5/4=6/4=3/2

d)(360-15*6):5=(360-90):5=270:5=54

a) ( 120 - 12 x 5 ) : 6

= ( 120 - 60 ) : 6

= 60 : 6

= 10

b) 494 - ( 75 + 35 : 5 ) x 2

= 494 - ( 75 + 7 ) x 2

= 494 - 82 x 2

= 494 - 164

= 330

c) 1/4 + ( 3/4 : 1/2 ) x 5/6

= 1/4 + 3/2 x 5/6

= 1/4 + 5/4

= 6/4 = 3/2

d) ( 360 - 15 x 6 ) : 5

= ( 360 - 90 ) : 5

= 270 : 5

= 54

a) 40 - x = 54

x = 40 - 54

x = -14

b) 36 - x = -11

x = 36 - (-11)

x = 47

c) 2.x - 3 = -14

2x = -14 + 3

2x = -11

x = -11/2

Có A = 1998 x 2002

         = (2000 - 2) x (2000 + 2)

         = 2000² - 2²

         = 2000² - 4

Mà B = 2000 x 2000 = 2000² ; 2000² - 4 < 2000²

=> A < B

Có B = 35 x 53 - 18

         = (34 + 1) x 53 - 18

         = 34 x 53 + 53 - 18

         = 34 x 53 + 35

=> B = D

câu này dễ mà  bạn

re thi lam di chi gioi noi thoi

Pham minh quang : quá giỏi ns 

a) \(=x^2+6x+9\)

b) \(=4x^2+4x+1-4x^2+9=4x+10\)

a) \(\left(x+3\right)^2=x^2+6x+9\)

b) \(\left(2x+1\right)^2-\left(2x+3\right)\left(2x-3\right)=4x^2+4x+1-4x^2+9\)

\(=4x+10\)

168 x 168 - 168 x 58 : 110

= 168 x ( 168 - 58 ) : 110

= 168 x 110 : 110

= 168 x 1

= 168

Sao bài tập của bạn giống của nguyễn diệp anh thế.

giup mk nha cac ban

a, 568 + 568 x 135 - 568 x 36

= 568 x ( 1 + 135 - 36)

= 568 x 100

56 800

b, 17 x 49 + 49 x 37 + 54 x 26 + 54 x 25

=  49 x ( 17 + 37) + 54 x ( 26 + 25 )

= 49 x 54 + 54 x 51

= 54 x ( 49 + 51)

= 54 x 100

= 5 400

c,   14 x 35 x 5 + 10 x 25 x 7 + 20 x 70

 =    ( 2 x 35) x ( 7 x 5)  + ( 10 x 7) x 25 + 20 x 70

= 70 x 35 + 70 x 25 + 20 x 70

= 70 x ( 35 + 25 + 20)

= 70 x 80

= 5 600 

a) 568 + 568 x 135 - 568 x 36

= 568 x ( 1+1+135-1-36 )

=568 x 100

=5680

b) 17 x 49 + 49 x 37 + 54 x 26 + 54 x 25

= 49 x ( 17 + 37 ) + 54 x ( 26 + 25 )

= 49 x 54 + 54 x 51

= 54 x ( 49 + 51 )

= 54 x 100

= 5400

c) 14 x 35 x 5 + 10 x 25 x 7 + 20 x 70

= 70 x 35 + 10 x 25 x 7+ 20 x 70

= 70 x 35 + 250 x 7 + 20 x 70

= 70 x 35 + 70 x 25 + 20 x 70

= 70 x (35+25+20)

= 70 x 80

= 5600

a) => \(\left(\frac{1}{3}-\frac{5}{6}x\right)^3=\frac{5}{6}-\frac{21}{54}=\frac{24}{54}=\frac{4}{9}\)

=> \(\frac{1}{3}-\frac{5}{6}x=\sqrt[3]{\frac{4}{9}}\) => \(\frac{5}{6}x=\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\) => \(x=\frac{6}{5}.\left(\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\right)\)

b) \(\frac{1}{3}\left(\frac{1}{2}x-1\right)^4=\frac{1}{12}-\frac{1}{16}=\frac{1}{48}\) => \(\left(\frac{1}{2}x-1\right)^4=\frac{3}{48}=\frac{1}{16}\)

=> \(\frac{1}{2}x-1=\frac{1}{2}\) hoặc  \(\frac{1}{2}x-1=-\frac{1}{2}\)

=> \(\frac{1}{2}x=\frac{3}{2}\) hoặc \(\frac{1}{2}x=\frac{1}{2}\) => x = 3 hoặc x = 1

c) \(\left(1+5\right).\left(\frac{3}{5}\right)^{x-1}=\frac{54}{25}\) => \(\left(\frac{3}{5}\right)^{x-1}=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)

=> x - 1= 2 => x = 3

d) \(\left(1+\left(\frac{2}{3}\right)^2\right).\left(\frac{2}{3}\right)^x=\frac{101}{243}\) => \(\frac{13}{9}.\left(\frac{2}{3}\right)^x=\frac{101}{243}\)

=> \(\left(\frac{2}{3}\right)^x=\frac{101}{243}:\frac{13}{9}=\frac{101}{351}\) (có lẽ đề sai)

2) \(\frac{1}{27^{11}}=\frac{1}{\left(3^3\right)^{11}}=\frac{1}{3^{33}}\); \(\frac{1}{81^8}=\frac{1}{\left(3^4\right)^8}=\frac{1}{3^{32}}\)

Vì 3³³ > 3³² => \(\frac{1}{3^{33}}\) < \(\frac{1}{3^{32}}\) => \(\frac{1}{27^{11}}\) < \(\frac{1}{81^8}\)

b) \(\frac{1}{3^{99}}=\frac{1}{\left(3^3\right)^{33}}=\frac{1}{27^{33}}