Sửa đề: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)Ta có: \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)

\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)

\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)

\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)

mà \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}>0\)

nên 100-x=0

hay x=100

Vậy: S={100}

Ta có : \(\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}=-5\)

\(\Leftrightarrow\dfrac{74-x}{26}+\dfrac{75-x}{25}+\dfrac{76-x}{24}+\dfrac{77-x}{23}+\dfrac{78-x}{22}+5=0\)

\(\Leftrightarrow\dfrac{74-x}{26}+1+\dfrac{75-x}{25}+1+\dfrac{76-x}{24}+1+\dfrac{77-x}{23}+1+\dfrac{78-x}{22}+1=0\)

\(\Leftrightarrow\dfrac{100-x}{26}+\dfrac{100-x}{25}+\dfrac{100-x}{24}+\dfrac{100-x}{23}+\dfrac{100-x}{22}=0\)

\(\Leftrightarrow\left(100-x\right)\left(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\right)=0\)

Thấy : \(\dfrac{1}{26}+\dfrac{1}{25}+\dfrac{1}{24}+\dfrac{1}{23}+\dfrac{1}{22}\ne0\)

\(\Rightarrow100-x=0\)

\(\Leftrightarrow x=100\)

Vậy ...

=-5 nha

\(\frac{74-x}{26}+\frac{75-x}{25}+\frac{76-x}{24}+\frac{77-x}{23}+\frac{78-x}{22}=-5\)

\(\frac{74-x}{26}+1+\frac{75-x}{25}+1+\frac{76-x}{24}+1+\frac{77-x}{23}+1+\frac{78-x}{22}=-5+5\)

\(\frac{74-x}{26}+\frac{26}{26}+\frac{75-x}{25}+\frac{25}{25}+\frac{76-x}{24}+\frac{24}{24}+\frac{77-x}{23}+\frac{23}{23}+\frac{78-x}{22}+\frac{22}{22}=0\)

\(\frac{100-x}{26}+\frac{100-x}{25}+\frac{100-x}{24}+\frac{100-x}{23}+\frac{100-x}{22}=0\)

\(\left(100-x\right)\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)=0\)

=>100-x=0    ( \(\left(\frac{1}{26}+\frac{1}{25}+\frac{1}{24}+\frac{1}{23}+\frac{1}{22}\right)\ne0\))

x=100

hahaha

Cộng 1 vào mỗi hạng tử trong vế trái là dc

\(\frac{2^{76}-2^{74}}{2^{78}-2^{76}}=\frac{2^{74}\left(2^2-1\right)}{2^{76}\left(2^2-1\right)}=\frac{1}{2^2}=\frac{1}{4}\)

 36 x 76 - 24 x 39 

=2736 - 936 

=1800 

  1992 -(992+95)

= 1992 - 1087 

=903

920 - [24 - (5-3)² ]

=920 -[ 24- 4]

=920 20

=900

5x - 3 = 2002

5x      = 2002 +3

5x      = 2005 

  x      = 2005 : 5 

  x = 401

10 + 2x = 4⁵ : 4³ 

10 + 2x = 4²

       2x  = 16 - 10 

      2x   = 6

       x     = 6:2

      x     = 3

1, (1/4:y-3/8)x3/4=5/4

(1/4:y-3/8)=5/4:3/4

(1/4:y-3/8)=5/3

1/4:y=5/3+3/8

1/4:y=40/24+9/24

1/4:y=49/24

y=1/4:49/24=6/49

2,

a,20,14x92+10,07x8+40,28x2

10,07x2x92+10,07x8+10,07x4x2

=10,07x184+10,07x8+10,07x8

=10,07x(184+8+8)

=10,07x2002014

b,24x335+68x74+68x26+76x335

=335x(24+76)+68x(74+26)

=335x100+68x100

=100x(335+68)

=100x403=40300

cho tớ đúng đi

câu 1 : 13500

câu 2 : 1350

k nha

câu đầu tiên 13500 câu thứ 2 tìm cái gì

(100 + 35) x 35 + (200 - 65) x 65

= 135 x 35 + 135 x 65

= 135 x (35 + 65)

= 135 x 100

= 13500

Số các số hạng là:

(2000-74):2+1=964 (số)

Tổng là:

(2000+74)x964:2=999668

Đáp số:999668 

de nhu the nao z e

Đặt: \(A=74+76+...+2000\)

\(\Rightarrow2A=74+76+...+2000+74+76+....+2000\)

\(\Rightarrow2A=\left(2000+74\right)+\left(76+1998\right)+....+\left(74+2000\right)\)

\(\Rightarrow2A=2074.964\)

\(\Rightarrow2A=1999336\)

\(\Rightarrow A=1999336:2=999668\)

Cho mk xin 2 chu binh yen

                              va