giúp mình với mình sắp thi giữa kì rồi

a) 5³⁶ = 5¹² (5³)¹² = 125¹²; 11²⁴ = 11^2.12 = (11²)¹² = 121¹²

a: \(4^5\cdot8^7=2^{10}\cdot2^{21}=2^{31}\)

b: \(125^5\cdot25^3=5^{15}\cdot5^6=5^{21}\)

a) \(4^5\)x \(8^7\)

= \(\left(2^2\right)^5\) x \(\left(2^3\right)^7\)

= \(2^{10}\) x \(2^{21}\)

= \(2^{31}\)

b) \(125^5\) x \(25^3\)

= \(\left(5^3\right)^5\) x \(\left(5^2\right)^3\)

= \(5^{15}\) x \(5^6\)

= \(5^{21}\)

$a,$

$2^{20}.15+2^{10}.85$

$=2^{20}.2^{10}.85+15$

$=2^{30}.100$

$=2^{30}{.10}^2$    

$b,$

${27}^{16}:9^{10}$

$=(3^3{)}^{16}:(3^2{)}^{1}0$

$=3^{48}:3^{20}$

$=3^{28}$ 

$c,$ 

${125}^3:{25}^4$

$=(5^3{)}^5:(5^2{)}^4$

$=5^{15}:5^8$

$=5^7$

$d,$

${24}^4:3^4-{32}^{12}:{16}^{12}$

$=(24:3{)}^4-(32:16{)}^{12}$

$=8^4-2^{12}$

$=(2^3{)}^4-2^{12}$

$=2^{12}-2^{12}$ 

\(3^3.3^4=3^{3+4}=3^7\)

\(5^2.5^7=5^{2+7}=5^9\)

\(7^5.7=7^{5+1}=7^6\)

a,3³.3⁴=3⁷

b,5².5⁷=5⁹

c,7⁵.7=7⁶

a)    3³.3⁴=3⁷

b)     5².5⁷=5⁹

c)     7⁵.7=7⁶

Ai kick mình mình kick lại

a) 3³ . 3⁴ = 3⁷

b) 5² . 5⁷ = 5⁹

c) 7⁵ . 7 = 7⁶

a, 3³ . 3⁴ = 3⁷

b, 5² . 5⁷ = 5⁹

c, 7⁵ . 7 = 7⁶

\(a,3^3.3^4=3^{3+4}=3^7\)

\(b,5^2.5^7=5^{2+7}=5^9\)

\(c,7^5.7=7^{5+1}=7^6\)

a) 3^7=2187

b) 5^9=1953125

c) 7^6=117649

a     3^7=2187

b 5^9=9153125

c    7^6=117649

\(3^3.3^4=2187\)

\(5^2.5^7=1953125\)

\(7^{5.7}=7^{35}\)

3^3.3^4=3^7=2187

5^2.5^7=5^9=1953125

7^5.7=7^6=117649

bn k mik nhoa!

\(3^3.3^4=3^7\)

\(5^2.5^7=5^9\)

\(7^{5.7}=7^{35}\)

\(16^2:4^2\)

\(=\left(4^2\right)^2:4^2\)

\(=4^4:4^2\)

\(=4^{4-2}\)

\(=4^2\)

==========

\(25^5:5^2\)

\(=\left(5^2\right)^5:5^2\)

\(=5^{10}:5^2\)

\(=5^{10-2}\)

\(=5^8\)

============

\(9^8:3^2\)

\(=\left(3^2\right)^8:3^2\)

\(=3^{16}:3^2\)

\(=3^{16-2}\)

\(=3^{14}\)

===========

\(a^6:a\)

\(=a^{6-1}\)

\(=a^5\)

a) \(3^5.3^7=3^{5+7}=3^{12}\)

b) \(a^5.a=a^{5+1}=a^6\)

c) \(5^4:5^3=5^{4-3}=5^1=5\)

d) \(a^3:a^3=a^{3-3}=a^0=1\)

a) \(3^5.3^7=3^{12}\)

b) \(a^5.a=a^6\)

c) \(5^4:5^3=5\)

d) \(a^3:a^3=1\)