Tìm x biết : a , ( x 1 ) mũ 3 = 8 b , ( 2x 3 ) mũ 3 = 125 c , 2 mũ x 1 = 16 d , ( x 1 ) mũ 2019 = ( x 1 ) mũ 2020 e...

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9 tháng 7 2023 lúc 8:23

bài 4 : viết các biểu thức sau dưới dạng tích

a , 25 x mũ 2 -16

b , 16 a mũ 2 - 9 b mũ 2

c , 8 x mũ 3 + 1

d , 125 x mũ 3 + 27 y mũ 3

e , 8 x mũ 3 - 125

g , 27 x mũ 3 - y mũ 3

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Lớp 8 Toán Câu hỏi của OLM

Kiều Vũ Linh CTV

9 tháng 7 2023 lúc 8:32

a) 25x² - 16

= (5x)² - 4²

= (5x - 4)(5x + 4)

b) 16a² - 9b²

= (4a)² - (3b)²

= (4a - 3b)(4a + 3b)

c) 8x³ + 1

= (2x)³ + 1³

= (2x + 1)(4x² - 2x + 1)

d) 125x³ + 27y³

= (5x)³ + (3y)³

= (5x + 3y)(25x² - 15xy + 9y²)

e) 8x³ - 125

= (2x)³ - 5³

= (2x - 5)(4x² + 10x + 25)

g) 27x³ - y³

= (3x)³ - y³

= (3x - y)(9x² + 3xy + y²)

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Nguyễn Đức Trí

9 tháng 7 2023 lúc 8:33

a) \(25x^2-16=\left(5x-4\right)\left(5x+4\right)\)

b) \(16a^2-9b^2=\left(4a-3b\right)\left(4a+3b\right)\)

c) \(8x^3+1=\left(2x+1\right)\left(4x^2-2x+1\right)\)

d) \(125x^3+27y^3=\left(5x+3y\right)\left(25x^2-15xy+9y^2\right)\)

e) \(8x^3-125=\left(2x-5\right)\left(4x^2-10x+25\right)\)

g) \(27x^3-y^3=\left(3x-y\right)\left(9x^2+3xy+y^2\right)\)

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Đoàn Khôi Nguyên

9 tháng 7 2023 lúc 8:39

tao phá olm đêy nè:

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Nguyễn Anh Thư

21 tháng 9 2020 lúc 20:22

Bài 4: Tìm x biết
a) (x-3) mũ 2 -4=0
b) (2x+3) mũ 2 - (2x+1)(2x-1)=22
c) (4x+3)(4x-3) - (4x-5) mũ 2=16
d) x mũ 3 - 9x mũ 2 + 27x - 27= -8
e) (x+1) mũ 3 - x mũ 2 nhân (x+3)=2
f) (x-2) mũ 3 - x(x-1)(x+1) + 6x mũ 2=5

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Lớp 8 Toán Câu hỏi của OLM

l҉o҉n҉g҉ d҉z҉

21 tháng 9 2020 lúc 20:32

a) ( x - 3 )² - 4 = 0

<=> ( x - 3 )² - 2² = 0

<=> ( x - 3 - 2 )( x - 3 + 2 ) = 0

<=> ( x - 5 )( x - 1 ) = 0

<=> x = 5 hoặc x = 1

b( 2x + 3 )² - ( 2x + 1 )( 2x - 1 ) = 22

<=> 4x² + 12x + 9 - ( 4x² - 1 ) = 22

<=> 4x² + 12x + 9 - 4x² + 1 = 22

<=> 12x + 10 = 22

<=> 12x = 12

<=> x = 1

c) ( 4x + 3 )( 4x - 3 ) - ( 4x - 5 )² = 16

<=> 16x² - 9 - ( 16x² - 40x + 25 ) = 16

<=> 16x² - 9 - 16x² + 40x - 25 = 16

<=> 40x - 34 = 16

<=> 40x = 50

<=> x = 50/40 = 5/4

d) x³ - 9x² + 27x - 27 = -8

<=> ( x - 3 )³ = -8

<=> ( x - 3 )³ = (-2)³

<=> x - 3 = -2

<=> x = 1

e) ( x + 1 )³ - x²( x + 3 ) = 2

<=> x³ + 3x² + 3x + 1 - x³ - 3x² = 2

<=> 3x + 1 = 2

<=> 3x = 1

<=> x = 1/3

f) ( x - 2 )³ - x( x - 1 )( x + 1 ) + 6x² = 5

<=> x³ - 6x² + 12x - 8 - x( x² - 1 ) + 6x² = 5

<=> x³ + 12x - 8 - x³ + x = 5

<=> 13x - 8 = 5

<=> 13x = 13

<=> x = 1

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Huỳnh Quang Sang

21 tháng 9 2020 lúc 20:34

a) \(\left(x-3\right)^2-4=0\)

=> \(\left(x-3\right)^2-2^2=0\)

=> \(\left(x-3-2\right)\left(x-3+2\right)=0\)

=> \(\left(x-5\right)\left(x-1\right)=0\)

=> \(\orbr{\begin{cases}x=5\\x=1\end{cases}}\)

b) \(\left(2x+3\right)^2-\left(2x+1\right)\left(2x-1\right)=22\)

=> \(\left(2x+3\right)^2-\left[\left(2x\right)^2-1^2\right]=22\)

=> \(\left(2x+3\right)^2-\left(4x^2-1\right)=22\)

=> \(\left(2x\right)^2+2\cdot2x\cdot3+3^2-4x^2+1=22\)

=> \(4x^2+12x+9-4x^2+1=22\)

=> \(12x+9+1=22\)

=> \(12x+10=22\)

=> 12x = 12

=> x = 1

c) \(\left(4x+3\right)\left(4x-3\right)-\left(4x-5\right)^2=16\)

=> \(\left(4x\right)^2-3^2-\left[\left(4x\right)^2-2\cdot4x\cdot5+5^2\right]=16\)

=> \(16x^2-9-\left(16x^2-40x+25\right)=16\)

=> \(16x^2-9-16x^2+40x-25=16\)

=> \(-9+40x-25=16\)

=> \(40x=16+25-\left(-9\right)=16+25+9=50\)

=> x = 50/40 = 5/4

d) \(x^3-9x^2+27x-27=-8\)

=> \(x^3-3\cdot x^2\cdot3+3\cdot x\cdot3^2-3^3=8\)

=> \(\left(x-3\right)^3=-8\)

=> \(\left(x-3\right)^3=\left(-2\right)^3\)

=> x - 3 = -2 => x = 1

e) \(\left(x+1\right)^3-x^2\left(x+3\right)=2\)

=> \(x^3+3x^2+3x+1-x^3-3x^2=2\)

=> \(3x+1=2\)

=> \(3x=1\)=> x = 1/3

f) \(\left(x-2\right)^3-x\left(x-1\right)\left(x+1\right)+6x^2=5\)

=> \(x^3-3\cdot x^2\cdot2+3\cdot x\cdot2^2-2^3-x\left(x^2-1\right)+6x^2=5\)

=> \(x^3-6x^2+12x-8-x^3+x+6x^2=5\)

=> \(\left(12x+x\right)-8=5\)

=> 13x = 13

=> x = 1

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Thành Đạt Nguyễn

25 tháng 9 2020 lúc 20:12

a) (x+3)^2-4=0

=>(x+3)^2 = 4

=>(x+3)^2 = 2^2 = (-2)^2

=>x+3 = 2 hoặc -2

=> x= -1 hoặc -5

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Yoo si jin 1983

30 tháng 9 2018 lúc 21:36

Tìm x thuộc N. a) 2 mũ x 16 b) 2 mũ x+1 16 c) 5 mũ x +1 125 d) 5 mũ 2x -1125 e) 12x 144f) 3 mũ x-2 81 g) 4 mũ x +2 4 mũ 3* 64h) 5 mũ 2x -2 125*5 mũ 7k) 4 mũ x -1 16*4 mũ 3m) 3 mũ x+1 9 * 3 mũ 2n) 4/2 mũ x -3 125 i) 2x *16 128 j) 3 mũ x * 9 27 u) 2 mũ x : 2 16 s) 5 mũ 2 x -3 - 2* 5 mũ 2 5 mũ 2*3t) ( 2x +1 ) mũ 3 27 v) ( 8x -14) mũ 4 16r) 4 x mũ 3 +15 47y) ( 7 x -11) mũ 3 2 mũ 5 * 5 mũ 2+200ê) 45 x 81 với x là bội của 9

Đọc tiếp

Tìm x thuộc N.

a) 2 mũ x = 16

b) 2 mũ x+1= 16

c) 5 mũ x +1= 125

d) 5 mũ 2x -1=125

e) 12x =144

f) 3 mũ x-2 =81

g) 4 mũ x +2 = 4 mũ 3* 64

h) 5 mũ 2x -2 =125*5 mũ 7

k) 4 mũ x -1 =16*4 mũ 3

m) 3 mũ x+1 =9 * 3 mũ 2

n) 4/2 mũ x -3 =125

i) 2x *16 =128

j) 3 mũ x * 9 =27

u) 2 mũ x : 2 =16

s) 5 mũ 2 x -3 - 2* 5 mũ 2= 5 mũ 2*3

t) ( 2x +1 ) mũ 3 = 27

v) ( 8x -14) mũ 4 =16

r) 4 x mũ 3 +15 =47

y) ( 7 x -11) mũ 3 = 2 mũ 5 * 5 mũ 2+200

ê) 45< x < 81 với x là bội của 9

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Lớp 6 Toán Câu hỏi của OLM

Trần Tiến Pro ✓

30 tháng 9 2018 lúc 21:59

a) 2^x = 16 e) 12^x = 144

2^x = 2⁴ 12^x = 12²

=> x = 4 => x = 2

b) 2^x+1 = 16 các câu còn lại tương tự nhé nhiều quá

2^x+1 = 2⁴

x + 1 = 4

=> x = 3

c) 5^x+1 = 125

5^x+1 = 5³

x + 1 = 3

=> x = 2

d) 5^{2x - 1} = 125

5^2x-1 = 5³

2x - 1 = 3

2x = 4

=> x = 2

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Nguyễn Trịnh Hoài Hưng

30 tháng 9 2018 lúc 22:02

a)Ta có : 2^x = 16

2^x = 2⁴

=> x = 4

b) Ta có: 2^x+1 = 16

2^x+1 = 2⁴

=> x+1 = 4

=> x = 4-1

=> x = 3

Mấy câu sau tương tự vậy đó để hôm khác mình làm tiếp cho bây giờ mình đi ngủ đã buồn ngủ quá hihi ! ^-^

Học tốt nha bạn !

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NIGHTCORE

3 tháng 10 2018 lúc 21:01

dài vậy cha

ai làm cho

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Linh Mệt Mỏi

17 tháng 9 2016 lúc 16:22

Bài 2: Tìm x

a) x mũ 3-2= 2 mũ 5- (3 mũ 16 : 3 mũ 14+2 mũ 8 : 2 mũ 6)

b) (x-1) mũ 2 =25

c) (2x+1) mũ 3= 125

Giúp mình với các bạn ơi

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Lớp 6 Toán Câu hỏi của OLM

nguyễn anh thư

11 tháng 10 2019 lúc 11:45

bài 1 tìm x thuộc n

a) 1/9 * 3 mũ 4 * 3 mũ n = 3 mũ 7

b) 2.3 mũ x = 26. 2 mũ 2 +2.30

c) 10 mũ x -3 =100

d) (x-3) mũ 3 =144

e) (2x+1) mũ 3 =125

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Lớp 6 Toán Câu hỏi của OLM

BÙI BẢO KHÁNH

10 tháng 8 2023 lúc 15:19

Bài 2: Tìm số tự nhiên x,biết: 1, 2 mũ x 4 2, 2 mũ x 8 3, 2 mũ x 16 4, 2 mũ x 1 5, 3 mũ x 9 6, 3 mũ x 81 7, 3 mũ x 27 8, 5 mũ x 25 9, 5 mũ x 125 10, 8 mũ x 64 11, 3 mũ x + 1 3 mũ 2 12, 2 mũ 2 x + 1 2 mũ 7 13, 5 mũ x - 1 5 mũ 2 14, 5 mũ 2 x - 4 5 mũ 10 15, 6 x + 4 6 mũ 10 16, 2 mũ 2 x - 3 2 mũ 9 17, 7 mũ 2 x - 3 7 mũ 7 18, 8 mũ x - 2 1 19, 9 mũ x - 8 81 20, 10 mũ 2 x - 1 1000 Giúp mình với,mình đang cần gấp !!

Đọc tiếp

Bài 2: Tìm số tự nhiên x,biết:

1, 2 mũ x = 4

2, 2 mũ x = 8

3, 2 mũ x = 16

4, 2 mũ x = 1

5, 3 mũ x = 9

6, 3 mũ x = 81

7, 3 mũ x = 27

8, 5 mũ x = 25

9, 5 mũ x = 125

10, 8 mũ x = 64

11, 3 mũ x + 1 = 3 mũ 2

12, 2 mũ 2 x + 1 = 2 mũ 7

13, 5 mũ x - 1 = 5 mũ 2

14, 5 mũ 2 x - 4 = 5 mũ 10

15, 6 x + 4 = 6 mũ 10

16, 2 mũ 2 x - 3 = 2 mũ 9

17, 7 mũ 2 x - 3 = 7 mũ 7

18, 8 mũ x - 2 = 1

19, 9 mũ x - 8 = 81

20, 10 mũ 2 x - 1 = 1000

Giúp mình với,mình đang cần gấp !!

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Lớp 6 Toán Câu hỏi của OLM

Nguyễn Anh Thư

5 tháng 10 2020 lúc 19:58

Bài 2: Tìm x, biết
a) (x+3) mũ 2 - (x-4)(x+8) = 1
b) (x+3)(x mũ 2 - 3x + 9) -x(x-2)(x+2) = 15
c) (x-2) mũ 2 - (x+3) mũ 2 - 4(x+1) = 5
d) (2x-3)(2x+3) - (x-1) mũ 2 - 3x(x-5) = -44
e) (x-2) mũ 3 - (x-3)(x mũ 2 + 3x + 9) + 6(x+1) mũ 2 = 49
f) 5x(x-3) mũ 2 - 5(x-1) mũ 3 + 15(x+2)(x-2) = 5
g) (x+3) mũ 3 - x(3x+1) mũ 2 + (2x+1)(4x mũ 2 - 2x + 1) - 3x mũ 2 = 42

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Lớp 8 Toán Câu hỏi của OLM

FL.Han_

5 tháng 10 2020 lúc 20:09

a) \(\left(x+3\right)^2-\left(x-4\right)\left(x+8\right)=1\)

\(\Leftrightarrow\left(x^2+6x+9\right)-\left(x^2+4x-32\right)-1=0\)

\(\Leftrightarrow2x=-40\)

\(\Rightarrow x=-20\)

b) \(\left(x+3\right)\left(x^2-3x+9\right)-x\left(x-2\right)\left(x+2\right)=15\)

\(\Leftrightarrow x^3+27-x^3+4x=15\)

\(\Leftrightarrow4x=-12\)

\(\Rightarrow x=-3\)

c) \(\left(x-2\right)^2-\left(x+3\right)^2-4\left(x+1\right)=5\)

\(\Leftrightarrow\left(x^2-4x+4\right)-\left(x^2+6x+9\right)-\left(4x+4\right)=5\)

\(\Leftrightarrow-14x=14\)

\(\Rightarrow x=-1\)

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FL.Han_

5 tháng 10 2020 lúc 20:14

d) \(\left(2x-3\right)\left(2x+3\right)-\left(x-1\right)^2-3x\left(x-5\right)=-44\)

\(\Leftrightarrow4x^2-9-\left(x^2-2x+1\right)-\left(3x^2-15x\right)=-44\)

\(\Leftrightarrow17x=-34\)

\(\Rightarrow x=-2\)

e) \(\left(x-2\right)^3-\left(x-3\right)\left(x^2+3x+9\right)+6\left(x+1\right)^2=49\)

\(\Leftrightarrow x^3-6x^2+12x-8-x^3+27+6x^2+12x+6=49\)

\(\Leftrightarrow24x=24\)

\(\Rightarrow x=1\)

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FL.Han_

5 tháng 10 2020 lúc 20:23

f) \(5x\left(x-3\right)^2-5\left(x-1\right)^3+15\left(x+2\right)\left(x-2\right)=5\)

\(\Leftrightarrow5x^3-30x^2+45x-5x^3+15x^2-15x+5+15x^2-60=5\)

\(\Leftrightarrow30x=60\)

\(\Rightarrow x=2\)

g) \(\left(x+3\right)^3-x\left(3x+1\right)^2+\left(2x+1\right)\left(4x^2-2x+1\right)-3x^2=42\)

\(\Leftrightarrow x^3+9x^2+27x+27-9x^3-6x^2-x+8x^3+1-3x^2=42\)

\(\Leftrightarrow26x=14\)

\(\Rightarrow x=\frac{7}{13}\)

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katty money

5 tháng 9 2019 lúc 20:18

Tìm x :

a, 2640+(( 900 -3x )/45)*24=3000

b, 1404:(118-(4x+6))=27

c, 16/8x-2019/2021

d, 5xmũ 2 -3x=0

e, 3(x-1)+4(x-1)mũ 2 =0

f,2(x-2) mũ 2 =(x-2)

g, (x-2020) mũ 4 = ( x-2020) mũ 2

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Lớp 6 Toán Câu hỏi của OLM

阮草~๖ۣۜDαɾƙ

5 tháng 9 2019 lúc 20:24

b. 1404 : [118 - (4x + 6)] = 27

118 - (4x + 6) = 52

4x + 6 = 66

4x = 60

x = 15

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.

5 tháng 9 2019 lúc 20:25

d) \(5x^2-3x=0\)

\(\Leftrightarrow x\left(5x-3\right)=0\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\5x-3=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=0\\x=\frac{3}{5}\end{cases}}\)

e) \(3\left(x-1\right)+4\left(x-1\right)^2=0\)

\(\Leftrightarrow\left(x-1\right)\left[3-4.\left(x-1\right)\right]=0\)

\(\Leftrightarrow\orbr{\begin{cases}x-1=0\\3-4\left(x-1\right)=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=1\\4\left(x-1\right)=3\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=1\\x-1=\frac{3}{4}\Rightarrow x=\frac{7}{4}\end{cases}}\)

f) \(2\left(x-2\right)^2=\left(x-2\right)\)

\(\Leftrightarrow\orbr{\begin{cases}x-2=0\\2\left(x-2\right)-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2\\x-2=\frac{1}{2}\Rightarrow x=\frac{5}{2}\end{cases}}\)

g) \(\left(x-2020\right)^4=\left(x-2020\right)^2\)

\(\Leftrightarrow\orbr{\begin{cases}\left(x-2020\right)^2=0\\\left(x-2020\right)^2-1=0\end{cases}}\)

\(\Leftrightarrow\orbr{\begin{cases}x=2020\\x=2019,x=2021\end{cases}}\)

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Phạm Đỗ Bảo Ngọc

22 tháng 7 2021 lúc 20:14

phân tích đa thức sau thành nhân tử

a, x mũ 3 - 8

b, 27x mũ 3 + 125y mũ 3

c, ( 2x - 1 ) mũ 3 + 8

d, x mũ 6 + 216

e, 1 - 27 x mũ 3

i, ( x - 3 ) mũ 3 + 27

f, x mũ 3 y mũ 3 + 125

g, 8x mũ 3 - 1 phần 8

m, x mũ 3 + 1 phần 27

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Lớp 8 Toán Câu hỏi của OLM

Nguyễn tấn nhân

22 tháng 7 2021 lúc 19:59

uuuttyutyyuyuyyuyuyuyuyuyuyuy

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