\(A=\left(4^2\right)^{17}.\frac{64^{36}}{8^{35}.32^{34}}\)

\(A=16^{17}.\frac{64^{2.36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)

\(A=...6.\frac{...6^{36}}{2^{105}.2^{170}}\)

mình lười tính quá bạn. bạn làm nốt nha

Ta có: \(A=\left(4^2\right)^{17}.\frac{64^{36}}{8^{35}.32^{34}}\)

          \(A=\left(2^2\right)^{34}.\frac{\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)

          \(A=2^{72}.\frac{2^{216}}{2^{105}.2^{170}}\)

          \(A=\frac{2^{72}.2^{216}}{2^{102}.2^{170}}=\frac{2^{288}}{2^{272}}\)

         \(A=2^{16}\)

Hok tốt nha^^

\(x+9=\left(-18\right)+35\\ \Rightarrow x+9=17\\ \Rightarrow x=17-9\\ \Rightarrow x=8\)

mik cảm ơn mn

\(A=\frac{\left(4^2\right)^{17}.64^{36}}{8^{35}.32^{34}}\)

\(A=\frac{\left(2^4\right)^{17}.\left(2^6\right)^{36}}{\left(2^3\right)^{35}.\left(2^5\right)^{34}}\)

\(A=\frac{2^{68}.2^{216}}{2^{105}.2^{170}}=\frac{2^{284}}{2^{275}}=2^9=512\)

-(-23) + (-36) + |-57| - (-29) -35

= 23 - 36 + 57 + 29 - 35

= (29 - 36) + (57 - 35) + 23

= 7 + 32 + 23

= 30 + 32 = 62

mai mình thi rồi, các bạn giúp mình với

Chờ tí

Câu 4: 

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}-\dfrac{15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}=\dfrac{5}{6}\)

Câu 3:

a) \(\dfrac{12}{36}=\dfrac{12:12}{36:12}=\dfrac{1}{3}\)

\(\dfrac{-16}{20}=\dfrac{-16:4}{20:4}=\dfrac{-4}{5}\)

b) \(\dfrac{21}{105}=\dfrac{21:21}{105:21}=\dfrac{1}{5}\)

\(\dfrac{35}{150}=\dfrac{35:5}{150:5}=\dfrac{7}{30}\)

Câu 4: 

a) \(\dfrac{3}{10}+\dfrac{5}{10}=\dfrac{3+5}{10}=\dfrac{8}{10}=\dfrac{4}{5}\)

b) Ta có: \(\left(-27\right)\cdot36+64\cdot\left(-27\right)+23\cdot\left(-100\right)\)

\(=\left(-27\right)\cdot\left(64+36\right)+23\cdot\left(-100\right)\)

\(=-27\cdot100-23\cdot100\)

\(=100\left(-27-23\right)\)

\(=-50\cdot100=-5000\)

c) \(\dfrac{5}{8}+\dfrac{3}{12}=\dfrac{15}{24}+\dfrac{6}{24}=\dfrac{21}{24}=\dfrac{7}{8}\)

d) Ta có: \(\dfrac{-2}{17}+\dfrac{3}{19}+\dfrac{-15}{17}+\dfrac{16}{19}+\dfrac{5}{6}\)

\(=\left(-\dfrac{2}{17}+\dfrac{-15}{17}\right)+\left(\dfrac{3}{19}+\dfrac{16}{19}\right)+\dfrac{5}{6}\)

\(=-1+1+\dfrac{5}{6}\)

\(=\dfrac{5}{6}\)

các bn lm đến đâu cx dc miễn là lm hộ mk cái ạ, ai đang lm vào nhắn tin vs mk để mk bít nha

a; \(-\dfrac{8}{3}+\dfrac{7}{5}-\dfrac{71}{15}< x< -\dfrac{13}{7}+\dfrac{19}{14}-\dfrac{7}{2}\)

              -\(\dfrac{19}{15}\) - \(\dfrac{71}{15}\) < \(x\) < -\(\dfrac{1}{2}\) - \(\dfrac{7}{2}\)

              -6 < \(x\) < -4

             vì \(x\) \(\in\) Z nên \(x\) = -5

- \(\dfrac{19}{6}+\dfrac{-15}{2}+\dfrac{11}{3}\) < \(x\) < - \(\dfrac{5}{4}\) + \(\dfrac{19}{12}\) - \(\dfrac{10}{3}\)

- \(\dfrac{32}{3}+\dfrac{11}{3}< x< \) \(\dfrac{1}{3}\) - \(\dfrac{10}{3}\)

-7 < \(x\) < - 3

Vì \(x\in\) Z nên \(x\in\) {-6;-5;-4}

1/5 ; 1/7

1/5

1/7

1/5

1/7