a) 1160 : {145.[1500 : (2².5³) - 194 : 97]}

= 1160 : {145.[1500 : (4.125) - 2]}

= 1160 : {145.[1500 : 500 - 2]}

= 1160 : {145.[3 - 2]}

= 1160 : 145

= 8

b) 1245 - {10² - 320 : [(794 - 111.6) : 2² ]}

= 1245 - {100 - 320 : [(794 - 666) : 2² ]}

= 1245 - {100 - 320 : [128 : 2² ]}

= 1245 - {100 - 320 : 32}

= 1245 - {100 - 10}

= 1245 - 90

= 1155

c) 9¹² : 3²² . {5³ - [(139 - 67).5] : 10}

= (3²)¹² : 3²² . {125 - [72 . 5] : 10}

= 3^2.12 : 3²² . {125 - 360 : 10}

= 3²⁴ : 3²² . {125 - 36}

= 3² . 89

= 9.89

= 301

a) 1160: { 145.[1500: 500-2]=1160:145=8

b) 1245-{ 100-320:[ 128:4]}=1245-{ 100-320:32}=1245-90=1155

c) 3^24:3^22{ 125-[72.5]:10}=3^2(125-36)=9.89=801

d) {343-[216-475:25.3]}.8=[343-(216-57)].8=(343-159).8=184.8=1472

1.

\(\left(572\cdot7+266\right)\cdot\left(366\cdot9-168\cdot18\right)\cdot\left(346\cdot6-348\right)\)

\(=\left(286\cdot7\cdot2+133\cdot2\right)\cdot\left(366\cdot9-168\cdot2\cdot9\right)\cdot\left(173\cdot6\cdot2-174\cdot2\right)\)

\(=\left(2002\cdot2+133\cdot2\right)\cdot\left(366\cdot9-336\cdot9\right)\cdot\left(1038\cdot2-174\cdot2\right)\)

\(=\left[2\cdot\left(2002+133\right)\right]\cdot\left[9\cdot\left(366-336\right)\right]\cdot\left[2\cdot\left(1038-174\right)\right]\)

\(=2\cdot2135\cdot9\cdot30\cdot2\cdot864\)

\(=4270\cdot9\cdot30\cdot2\cdot864\)

\(=\left(4270\cdot30\right)\cdot9\cdot2\cdot864\)

\(=\left(427\cdot10\right)\cdot\left(3\cdot10\right)\cdot9\cdot2\cdot864\)

\(=\left(427\cdot3\right)\cdot\left(10\cdot10\right)\cdot9\cdot2\cdot864\)

\(=1281\cdot100\cdot9\cdot2\cdot864\)

\(=\left(1281\cdot100\right)\cdot\left(9\cdot2\cdot864\right)\)

\(=\left(1281\cdot100\right)\cdot15552\)

\(=\left(1281\cdot15552\right)\cdot100\)

\(=19922112\cdot100\)

\(=1992211200\)

2.

\(\left(1+3+5+7+...+97+9\right)\cdot\left(45\cdot3-15\cdot2-45\right)\)

\(=\left(1+3+5+7+...+97+9\right)\cdot\left(15\cdot3\cdot3-15\cdot2-15\cdot3\right)\)

\(=\left(1+3+5+7+...+97+9\right)\cdot\left[15\cdot\left(3\cdot3\right)-15\cdot2-15\cdot3\right]\)

\(=\left(1+3+5+7+...+97+9\right)\cdot\left(15\cdot9-15\cdot2-15\cdot3\right)\)

\(=\left(1+3+5+7+...+97+9\right)\cdot\left[15\cdot\left(9-2-3\right)\right]\)

\(=\left(1+3+5+7+...+97+9\right)\cdot15\cdot4\)

\(=\left[\left(1+3+5+7+...+97\right)+9\right]\cdot\left(15\cdot4\right)\)

Trong \(\left(1+3+5+7+...+97\right)\) có số số hạng là:

        \(\left(97-1\right)\div2+1=49\) ( số hạng )

\(\Rightarrow\left[\left(1+3+5+7+...+97\right)+9\right]\cdot\left(15\cdot4\right)\)

\(=\left[\left(97+1\right)\cdot49\div2\right]\cdot\left(15\cdot4\right)\)

\(=2401\cdot60\)

\(=\left(2401\cdot6\right)\cdot10\)

\(=14406\cdot10\)

\(=144060\)

3.

\(\left(180\div15-132\div11\right)\cdot\left(57869-297\div11\cdot108\right)\)

\(=\left(12-12\right)\cdot\left(57869-297\div11\cdot108\right)\)

\(=0\cdot\left(57869-297\div11\cdot108\right)\)

\(=0\)

Sửa lại bài 2; dòng 11 ( từ đề bài bài 2 ):

\(=\left\{\left[\left(97+1\right)\cdot49\div2\right]+9\right\}\cdot\left(15\cdot4\right)\)

\(=\left(2401+9\right)\cdot\left(15\cdot4\right)\)
\(=2410\cdot\left(15\cdot4\right)\)

\(=2410\cdot60\)

\(=\left(241\cdot10\right)\cdot\left(6\cdot10\right)\)

\(=\left(241\cdot6\right)\cdot\left(10\cdot10\right)\)

\(=1446\cdot10\)

\(=14460\)

nhiều quá bn oi...

Giúp mình với

5/6 + 7/12 = 10/12 + 7/12 = 17/12

9/16 - 3/8 = 9/16 - 6/16 = 3/16

11/10 + 3/5 : 2/3 =11/10 + 3/5 x 3/2 = 11/10 + 9/10 = 20/10 = 2

\(\dfrac{5}{6}+\dfrac{7}{12}=\dfrac{10}{12}+\dfrac{7}{12}=\dfrac{17}{12}\)

\(\dfrac{9}{16}-\dfrac{3}{8}=\dfrac{9}{16}-\dfrac{6}{16}=\dfrac{3}{16}\)

\(\dfrac{11}{10}+\dfrac{3}{5}:\dfrac{2}{3}=\dfrac{11}{10}+\dfrac{3}{5}\times\dfrac{3}{2}=\dfrac{11}{10}+\dfrac{9}{10}=\dfrac{20}{10}=2\)

5/6 + 7/12

= 10/12 + 7/12

= 17/12 

9/16 - 3/8

= 9/16 - 6/16

= 3/16 

11/10 + 3/5 : 2/3

= 11/10 + ( 3/5 : 2/3 )

= 11/10 + ( 3/5 x 3/2 )

= 11/10 + 9/10

= 20/10 = 2.

a: =-15-24+12=-15-12=-27

a) Ta có: \(6^6:6^3+4^3\cdot4^3\cdot4^2\)

\(=6^3+4^8\)

\(=216+65536=65752\)

b) Ta có: (-137)+(-129)

=-137-129

=-266

c) Ta có: -84-36

=-(84+36)

=-120

d) Ta có: \(11\cdot37+63\cdot11-49\)

\(=11\cdot\left(37+63\right)-49\)

\(=11\cdot100-49\)

\(=1100-49=1051\)

e) Ta có: \(16:2^3+4:3^3-4\cdot3\)

\(=2^4:2^3+\dfrac{4}{27}-12\)

\(=2+\dfrac{4}{27}-12\)

\(=-10+\dfrac{4}{27}=\dfrac{-270}{27}+\dfrac{4}{27}=\dfrac{-266}{27}\)

\(=3\times129+7\times71=387+497=884\)

ai giúp mình nhé