Bài 1: 

a: Ta có: 8,5<3,5x<15

mà x là số nguyên

nên \(3,5x\in\left\{10,5;14\right\}\)

hay \(x\in\left\{3;4\right\}\)

b: Ta có: \(\left(3-\dfrac{1}{3}x\right):2+1.5=3\)

=>(3-1/3x):2=1,5

=>3-1/3x=3

=>x=0

a) X nhân 3/8 = 9/16
    X= 9/16 chia 3/8
    X= 9/16 nhân 8/3
    X= 3/2
b) x chia 12/7=5/8
    x= 5/8 nhân 12/7
    x= 15/14

Lời giải:

a. 

$x\times \frac{3}{8}=\frac{9}{16}$

$x=\frac{9}{16}: \frac{3}{8}$

$x=\frac{3}{2}$

b.

$x:\frac{12}{7}=\frac{5}{8}$

$x=\frac{5}{8}\times \frac{12}{7}$

$x=\frac{15}{14}$

a, ( x - 2/3 )^2 = 9/16

    x - 2/3        = ( 3/4 )^2 hoặc ( - 3/4 )^2

Nếu: x - 2/3     = 3/4

=>   x              = 3/4 + 2/3

=>   x              = 17/12

Nếu: x - 2/3      = - 3/4

=>    x              = - 3/4 + 2/3

=>    x              =  -1/12

vậy x = 17/12 hoặc x = -1/12

b, ( 3/4 - x )^3   = -8

 => 3/4 - x        = ( -2 )^3

 => 3/4 - x        = -2

 =>        x         = 3/4 - (-2)

 =>        x         = 11/4

vậy x = 11/4

tk nha

1: =>x^2+4x-21=0

=>(x+7)(x-3)=0

=>x=3 hoặc x=-7

2: =>(2x-5-4)(2x-5+4)=0

=>(2x-9)(2x-1)=0

=>x=9/2 hoặc x=1/2

3: =>x^3-9x^2+27x-27-x^3+27+9(x^2+2x+1)=15

=>-9x^2+27x+9x^2+18x+9=15

=>18x=15-9-27=-21

=>x=-7/6

6: =>4x^2+4x+1-4x^2-16x-16=9

=>-12x-15=9

=>-12x=24

=>x=-2

7: =>x^2+6x+9-x^2-4x+32=1

=>2x+41=1

=>2x=-40

=>x=-20

ta có:

$\dfrac{x}{3}=-\dfrac{16}{48}\\\Leftrightarrow x=\dfrac{-16.3}{48}=-1$

$\dfrac{y}{-9}=-\dfrac{16}{48}\\\Leftrightarrow y=\dfrac{-16.(-9)}{48}=3$

$\dfrac{-8}{z}=\dfrac{-16}{48}\\\Rightarrow x=\dfrac{-8.48}{-16}=24$

Vậy $x=-1,y=3,z=24$

x=-1

y=-3

z=24

Giải:

a) \(2^5=4^x\) 

\(\Rightarrow2^5=\left(2^2\right)^x\) 

\(\Rightarrow2^5=2^{2x}\) 

\(\Rightarrow2x=5\) 

\(\Rightarrow x=\dfrac{5}{2}\) 

b) \(2.4^2.8^3.16^4=8^x\) 

\(\Rightarrow2.\left(2^2\right)^2.\left(2^3\right)^3.\left(2^4\right)^4=\left(2^3\right)^x\) 

\(\Rightarrow2.2^4.2^9.2^{16}=2^{3x}\) 

\(\Rightarrow2^{30}=2^{3x}\) 

\(\Rightarrow3x=30\) 

\(\Rightarrow x=30:3\) 

\(\Rightarrow x=10\) 

c) \(3^3:3^5=9^x\) 

\(\Rightarrow3^{-2}=\left(3^2\right)^x\) 

\(\Rightarrow3^{-2}=3^{2x}\) 

\(\Rightarrow2x=-2\) 

\(\Rightarrow x=-2:2\)

\(\Rightarrow x=-1\) 

Chúc bạn học tốt!

a) Ta có: \(2^5=4^x\)

nên \(2^{2x}=2^5\)

\(\Leftrightarrow2x=5\)

hay \(x=\dfrac{5}{2}\)

b) Ta có: \(2\cdot4^2\cdot8^3\cdot16^4=8^x\)

\(\Leftrightarrow2^{3x}=2\cdot2^5\cdot2^9\cdot2^{16}=2^{31}\)

\(\Leftrightarrow3x=31\)

hay \(x=\dfrac{31}{3}\)

c) Ta có: \(3^3:3^5=9^x\)

\(\Leftrightarrow3^{-2}=3^{2x}\)

\(\Leftrightarrow2x=-2\)

hay x=-1

a.\(\left(-12\right)x-14=-2\)

\(\left(-12\right)x=-2+14\)

\(\left(-12\right)x=12\)

\(x=12:\left(-12\right)\)

\(x=-1\)

\(b,\left(-8\right)x=\left(-5\right)\left(-7\right)-3\)

\(\left(-8\right)x=35-3\)

\(\left(-8\right)x=32\)

\(x=32:\left(-8\right)\)

\(x=-4\)

\(c,\left(-9\right)x+3=\left(-2\right)\left(-7\right)+16\)

\(\left(-9\right)x+3=14+16\)

\(\left(-9\right)x+3=30\)

\(\left(-9\right)x=30-3\)

\(\left(-9\right)x=27\)

\(x=27:\left(-9\right)\)

\(x=-3\)