Ta có: \(P=12\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\)

\(\Rightarrow P=\dfrac{24\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{\left(5^{16}-1\right)\left(5^{16}+1\right)}{2}\)

\(\Rightarrow P=\dfrac{5^{32}-1}{2}\)

Ta có:

( 5 2 - 1).P = ( 5 2  – 1).12.( 5 2  + 1)( 5 4  + 1)( 5 8  + 1)( 5 16  + 1)

= 12.(  5 2  – 1).( 5 2  + 1)( 5 4 + 1)( 5 8  + 1)( 5 16 + 1)

= 12.(  5 4  - 1)(  5 4  + 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 8  - 1)(  5 8  + 1)( 5 16  + 1)

= 12.(  5 16  - 1)( 5 16  + 1)

= 12.(  5 32  - 1)

\(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^2-1\right)\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)=2\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\left(5^{128}-1\right)=2.5^{128}-2\)

c: Ta có: \(C=48\left(5^2+1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^2-1\right)\left(5^2+1\right)\cdot\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^4-1\right)\left(5^4+1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^8-1\right)\left(5^8+1\right)\left(5^{16}+1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{16}-1\right)\cdot\left(5^{16}+1\right)\cdot\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{32}-1\right)\left(5^{32}+1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{64}-1\right)\left(5^{64}+1\right)\)

\(=2\cdot\left(5^{128}-1\right)\)

\(=2\cdot5^{128}-2\)

d: Ta có: \(E=\left(x-2\right)^3-\left(x+1\right)\left(x^2-x+1\right)+6\left(x-1\right)^2\)

\(=x^3-6x^2+12x-8-x^3-1+6x^2-12x+6\)

\(=-3\)

a/=68

a) 125 : 25 + 12 . 4      c) 2680 + [ 10 . ( 4³ -54 ) : 5² + 2⁴]

= 5 + 48                        = 2680 + [ 10 . ( 64 - 54 ) : 25 + 16]

= 53                              = 2680 + [ 10 . 10 : 25 + 16]

                                     = 2680 + [ 100 : 25 + 16]

                                     = 2680 + [ 4 + 16 ]

                                     = 2680 + 20

                                     = 2700

a/ 125 : 25 + 12 . 4

=5+48

=53

c/ 2680 + [ 10 . ( 4³ - 54 ) : 5² + 2⁴ ]

=2680 +  [ 10 . 10 : 25 + 16 ]

= 2680 + 20

=2700

b/ 25 - ( 62 - 75 ) + ( - 38 )

= 25 - (- 13) + (- 38) 

=25 + 13 + (- 38)

=38 + (-38)

=0

Làm cho câu a thôi nha ! Ngại đánh máy ☻

a . 5 x 3² - 4 x 2³ + 35 : 7

= 5 x 9 - 4 x 8 + 5

=  45 - 32 + 5

=     13 + 5 

= 18

Ai  trả  lời  nhanh  mình  k  cho  !!!!!          ^-^

\(\frac{-1}{-16}-\frac{1}{15}\)

\(=\frac{1}{16}-\frac{1}{15}\)

\(=\frac{15-16}{16\times15}\)

\(=\frac{-1}{240}\)

c. ơn bn nha

\(\frac{-1}{-16}\)-\(\frac{1}{15}\)

=\(\frac{1}{16}\)-\(\frac{1}{15}\)

=\(\frac{15}{240}\)-\(\frac{16}{240}\)

=\(\frac{15-16}{240}\)

=\(\frac{-1}{240}\)

\(-\frac{1}{16}-\frac{1}{15}\)

\(=-\left(\frac{1}{16}+\frac{1}{15}\right)\)

\(=-\frac{16+15}{16\times15}\)

\(=-\frac{31}{240}\)

31/240

đó bạn

\(-\frac{1}{16}-\frac{1}{15}=\frac{-15}{240}-\frac{16}{240}=\frac{-15-16}{240}=\frac{-31}{240}\)