Find the value of
\(\frac{1}{2}+\frac{1}{2.2}+\frac{1}{2.2.2}+...+\frac{1}{2.2.2.2.2.2.2.2.2.2}\)
Find the value of n if
\(\frac{1}{\sqrt{ }1+\sqrt{ }2}+\frac{1}{\sqrt{ }2+\sqrt{ }3}+...+\frac{1}{\sqrt{ }n-1+\sqrt{ }n}\)
\(\frac{1}{\sqrt{1}+\sqrt{2}}+\frac{1}{\sqrt{2}+\sqrt{3}}+...+\frac{1}{\sqrt{n-1}+\sqrt{n}}=11\)
\(\Leftrightarrow-1+\sqrt{2}-\sqrt{2}+\sqrt{3}-...-\sqrt{n-1}+\sqrt{n}=11\)
\(\Leftrightarrow\sqrt{n}-1=11\Leftrightarrow\sqrt{n}=12\Leftrightarrow n=144\)
Find the value of
Let a , b and c be positive real numbers such that a + b + c = 3 . Find the minimum value of the expression .
\(P=\frac{1}{a^2}+\frac{1}{b^2}+\frac{1}{c^2}+\frac{1}{a^2+b^2+c^2}\)
Let a,b,c,d,e are integers satisfying the following expression:
\(\frac{501}{2015}\)=\(\frac{1}{a+\frac{1}{b+\frac{1}{c+\frac{1}{d+\frac{1}{e}}}}}\)
Find the value of a+b+c+d+e
Toán tiếng anh,giải giúp mik
Ta có: 2015/501=4+11/501 =>a=4
501/11=45+6/11 =>b=45
11/6=3+2/3 =>c=3
3/2=1+1/2 =>d=1
2/1=2 =>e=2
Vậy a=4 :b=45 :c=3 :d=1: e=2
Chúc bạn học tốt . Để dễ hiểu bạn hãy tham hảo đề toán giải máytính cầm tay
let P(x) be a polynomial of degree 3 and x1, x2, x3 are the solutions of P(x)=0. let \(\frac{P\left(\frac{1}{3}\right)-P\left(\frac{-1}{3}\right)}{P\left(0\right)}=8,\frac{P\left(\frac{1}{4}\right)-P\left(\frac{-1}{4}\right)}{P\left(0\right)}=9\)and x1+x2+x3 = 35. find the value of \(\frac{x2+x3}{x1}+\frac{x1+x3}{x2}+\frac{x1+x2}{x3}\)
Find the value of x:
3|1-2x| + 2|\(\frac{1}{4}-\frac{1}{2}x\)| = \(3^2-2^2\)
|3 - 6x| + |1/2 - x| = 5
=> 3 - 6x+1/2 - x = 5
=> -7x + 7/2 = 5
=> -7x = 3/2
=> x = -3/14
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find the value of x such that (Tìm x biết ) : \(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
( a khác -1; -7 )
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{a+7}{\left(a+1\right)\left(a+7\right)}-\frac{a+1}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)
=>x+7=6
=>x=6-7
=>x=-1
vậy x=-1
\(\frac{1}{a+1}-\frac{1}{a+7}=\frac{\left(a+7\right)-\left(a+1\right)}{\left(a+1\right)\left(a+7\right)}=\frac{6}{\left(a+1\right)\left(a+7\right)}\)=> x + 7 = 6 => x = -1
given 1<x<3., Find the value of \(A=\frac{\left|x-3\right|}{x-3}-\frac{\left|x-1\right|}{1-x} +\left|x-1\right|+\left|3-x\right|\)
Answer:A=...........
Lời giải:
Vì \(1< x< 3\Rightarrow \left\{\begin{matrix}
|x-3|=|3-x|=3-x\\
|x-1|=x-1\end{matrix}\right.\). Khi đó:
\(A=\frac{|x-3|}{x-3}-\frac{|x-1|}{1-x}+|x-1|+|3-x|\)
\(=\frac{3-x}{x-3}-\frac{x-1}{1-x}+x-1+3-x\)
\(=-1-(-1)+2=2\)
Vậy giá trị của $A$ là $2$
Find the value of x such that
\(\frac{x+7}{\left(a+1\right)\left(a+7\right)}=\frac{1}{a+1}-\frac{1}{a+7}\)
(a\(\ne\)-7;-1 )
Answer: x=