Phân tích đa thức thành nhân tử.
a,3x^2-3xy-5x+5y
b,x^2+4x-45
c,3y^3+6xy^2+3x^2y
d,x^3-3x^2-4x+12
e,x^3+3x^2+3x+1
f,x^2-3x+xy-3y
g,x^2-2xy+y^2-4
h,x^2-2xy+y^2-z^2
i,3x^2+6xy+3y^2-3z^2
HUHU. AI GIÚP EM VỚI. EM CẦN NỘP GẤP.
Phân tích các đa thức sau thành nhân tử:
a) x^3-4x^2+4x
b) x^2-2xy+y^2-9
c)2x^3-x^2-8x+4
d) x^2-y^2-5x+5y
e) 3x^2-6xy+3y^2-12z^2
f) x^3-4x^2+4x-xy^2
g) x^3-2x^2y+xy^2-25x
h) x^3-3x+2
i) 3x^2-7x-10
\(a,=x\left(x-2\right)^2\\ b,=\left(x-y\right)^2-9=\left(x-y-3\right)\left(x-y+3\right)\\ c,=x^2\left(2x-1\right)-4\left(2x-1\right)=\left(x-2\right)\left(x+2\right)\left(2x-1\right)\\ d,=\left(x-y\right)\left(x+y\right)-5\left(x-y\right)=\left(x-y\right)\left(x+y-5\right)\\ e,=3\left[\left(x-y\right)^2-4z^2\right]=3\left(x-y-2z\right)\left(x-y+2z\right)\\ f,=x\left[\left(x-2\right)^2-y^2\right]=x\left(x-y-2\right)\left(x+y-2\right)\\ g,=x\left[\left(x-y\right)^2-25\right]=x\left(x-y-5\right)\left(x-y+5\right)\\ h,=x^3-x-2x+2=x\left(x-1\right)\left(x+1\right)-2\left(x-1\right)\\ =\left(x-1\right)\left(x^2+x-2\right)=\left(x-1\right)^2\left(x+2\right)\\ i,=3x^2+3x-10x-10=\left(x+1\right)\left(3x-10\right)\)
Phân tích đa thức thành nhân tử
1, x\(^2\)-xy+x-y
2, xz+yz-5x-5y
3, 3x\(^2\)-3xy-5x+5y
4, x\(^2\)-2xy+y\(^2\)-xz+yz
5, 3x\(^2\)+6xy+3y\(^2\)-3z\(^2\)
6, 45+x\(^{^{ }3}\)-5x\(^2\)-9x
7, x\(^2\)-6x+5
8,x\(^2\)+7x+12
9, 2x\(^2\)-7x+3
10, 3x\(^2\)-12y\(^2\)
11, 5xy\(^2\)-10xyz+5xz\(^2\)
12,x\(^2\)-y\(^2\)-x+y
13, a\(^3\)x-ab+b-x
14, (1+x\(^2\))-4x(1-x\(^2\))
CÁC CẬU GIẢI CHI TIẾT GIÚP MÌNH VỚI Ạ
13: =x(a^3-1)-b(a-1)
=x(a-1)(a^2+a+1)-b(a-1)
=(a-1)(a^2x+a*x+x-b)
12: =(x-y)(x+y)-(x-y)
=(x-y)(x+y-1)
10: =3(x^2-4y^2)
=3(x-2y)*(x+2y)
7: =x^2-x-5x+5=(x-1)(x-5)
8: =x^2+3x+4x+12=(x+3)(x+4)
9: =2x^2-6x-x+3=(x-3)(2x-1)
phân tích đa thức thành nhân tử
a. 3x^2-6x+9x^2
10x(x-y)-6y(y-x)
c. 3x^2+5y-3xy-5x
d. 3y^2-3z^2+3x^2+6xy
e. 16x^3+54y^3
f. x^2-25-2xy+y^2
g. x^5-3x^4+3x^3-x^2
giúp mình vs mình đang gấp
phân tích thành nhân tử
b. x^2+2xy+y^2-16
c. 3x^2+5x-3xy-5y
d. 4x^2-6x^3y-2x^2+8x
e. x^2-4-2xy+y^2
k. x^2-y^2-z^2-2yz
m. 6xy+5x-5y-3x^2-3y^2
b)x2+2xy+y2-16=(x+y)2-42=(x+y+4)(x+y-4)
c)3x2+5x-3xy-5y=x(3x+5)-y(3x+5)=(3x+5)(x-y)
d)4x2-6x3y-2x2+8x=2x(2x-3x2y-x+4)
e)x2-4-2xy+y2=(x2-2xy+y2)-4=(x-y)2-22=(x-y-2)(x-y+2)
k)x2-y2-z2-2yz=x2-(y+z)2=(x-y-z)(x+y+z)
m)6xy+5x-5y-3x2-3y2=3(x2-2xy+y2)+5(x-y)=3(x-y)2+5(x-y)=(x-y)(3x-3y+5)
b. (x^2+2xy+y^2)-16 =(x+y)^2-16=(x+y+4)(x+y-4)
48. Phân tích các đa thức sau thành nhân tử : a) x² + 4x - y² + 4; 2 c) x² - 2xy + y 2 b) 3x² + 6xy + 3y²-3z²; + 2zt - t².
a: \(=\left(x+2-y\right)\left(x+2+y\right)\)
c: \(=\left(x-y\right)^2\)
Bài 7 : Phân tích đa thức thành nhân tử
A) 3x^2 - 6x + 9x^2 B) 10x (x-y) z 6y (y-x)
C) 3x^2 + 5y - 3xy - 5x D) 3y^2-3z^2+ 3x^2+6xy
E) 16x^3 + 54y^3 F)x^2- 25- 2xy+ y^2
G) x^5 - 3x^4 - 3x^3 - x^2
a) \(3x^2-6x+9x^2\)
\(=12x^2-6x\)
\(=6x\left(2x-1\right)\)
b) hỏi chấm đề ?
c) \(3x^2+5y-3xy-5x\)
\(=3x\left(x-y\right)-5\left(x-y\right)\)
\(=\left(x-y\right)\left(3x-5\right)\)
d) \(3y^2-3z^2+3x^2-6xy\)
\(=3\left(y^2-z^2+x^2-2xy\right)\)
\(=3\left[\left(x-y\right)^2-z^2\right]\)
\(=3\left(x-y-z\right)\left(x-y+z\right)\)
e) \(16x^3+54y^3\)
\(=2\left(8x^3+27y^3\right)\)
\(=2\left(2x+3y\right)\left(4x^2-6xy+9y^2\right)\)
f) \(x^2-25-2xy+y^2\)
\(=\left(x-y\right)^2-5^2\)
\(=\left(x-y-5\right)\left(x-y+5\right)\)
g) \(x^5-3x^4-3x^3-x^2\)
\(=x^2\left(x^3-3x^2-3x-1\right)\)
Phân tích đa thức thành nhân tử
a. 3x^2 - 6x + 9x^2 + x^3
b. 10x( x-y ) - 6y( y-x )
c. 3x^2 + 5y - 3xy - 5x
d. 3y^2 - 3z^2 + 6xy
e. 27 + 27x + 9x^2
f. 8x^3 - 12x^2y + 6xy^2 - y^3
g. X^3 + 8y^3
h. 16x^3 + 54y^3
i. x^2 - 25 - 2xy + y^2
k. x^5 - 3x^4 + 3x^3 - x^2
\(10x\left(x-y\right)-6y\left(y-x\right)\)
\(=10x\left(x-y\right)+6x\left(x-y\right)\)
\(=\left(10x+6x\right)\left(x-y\right)\)
\(c,3x^2+5y-3xy-5x\)
\(=\left(3x^2-3xy\right)+\left(5y-5x\right)\)
\(=3x\left(x-y\right)-5\left(x-y\right)\)
\(=\left(3x-5\right)\left(x-y\right)\)
\(e,27+27x+9x^2=3\left(9+9x+x^2\right)\)
\(f,8x^3-12x^2y+6xy^2-y^3\)
\(=\left(2x-y\right)^3\)
\(g,x^3+8y^3=x^3+\left(2y\right)^3\)
\(=\left(x+2y\right)\left(x^2-2xy+4x^2\right)\)
\(i,x^2-25-2xy+y^2\)
\(\left(x^2-2xy+y^2\right)-25=\left(x-y\right)^2-5^2\)
\(=\left(x-y-5\right)\left(x-y+5\right)\)
Phân tích mỗi đa thức sau thành nhân tử
a)x^3-2x^2y+xy^2+xy
b)x^3+4x^2y+4xy^2-9x
c)x^3-y^3+x-y
d)4x^2-4xy+2x-y+y^2
e)9x^2-3x+2y-4y^2
f)3x^2-6xy+3y^2-5x+5y
a) Xem lại đề
b) x³ - 4x²y + 4xy² - 9x
= x(x² - 4xy + 4y² - 9)
= x[(x² - 4xy + 4y² - 3²]
= x[(x - 2y)² - 3²]
= x(x - 2y - 3)(x - 2y + 3)
c) x³ - y³ + x - y
= (x³ - y³) + (x - y)
= (x - y)(x² + xy + y²) + (x - y)
= (x - y)(x² + xy + y² + 1)
d) 4x² - 4xy + 2x - y + y²
= (4x² - 4xy + y²) + (2x - y)
= (2x - y)² + (2x - y)
= (2x - y)(2x - y + 1)
e) 9x² - 3x + 2y - 4y²
= (9x² - 4y²) - (3x - 2y)
= (3x - 2y)(3x + 2y) - (3x - 2y)
= (3x - 2y)(3x + 2y - 1)
f) 3x² - 6xy + 3y² - 5x + 5y
= (3x² - 6xy + 3y²) - (5x - 5y)
= 3(x² - 2xy + y²) - 5(x - y)
= 3(x - y)² - 5(x - y)
= (x - y)[(3(x - y) - 5]
= (x - y)(3x - 3y - 5)
PP nhóm
1)2xy+3z+6y+xz
2)x^4-9x^3+x^2-9x
3)x^2-xy+x-y
4)xz+yz-5(x+y)
5)3x^2-3xy-5x+5y
6)x^2+4x-y^2+4
7)3x^2+6xy+3y^2-3z^2
8)x^2-2xy+y^2-z^2+2zt-t^2
1)2xy+3z+6y+xz
= x(2y + z) + 3(z + 2y)
= (x + 3)(2y + z)
2)x^4-9x^3+x^2-9x
= x^2(x^2 + 1) - 9x(x^2 + 1)
= (x^2 + 1)(x^2 - 9x)
= x(x - 9)(x^2 + 1)
3)x^2-xy+x-y
= x(x - y) + (x - y)
= (x + 1)(x - y)
4)xz+yz-5(x+y)
= z(x + y) - 5(x + y)
= (z - 5)(x + y)
5)3x^2-3xy-5x+5y
= 3x(x - y) - 5(x - y)
= (3x - 5)(x - y)
6)x^2+4x-y^2+4y
= (x - y)(x + y) + 4(x + y)
= (x - y + 4)(x + y)