a/x^4 lớn hơn hoặc = 0 

x^2 lớn hơn hoặc = 0

2 > 0

=> x^4+x^2+2 >0 => bieu thức luôn dương

b/ (x+3)(x-11)+2003 <=> x^2 -8x -33 +2003 <=> x^2 -8x +1970 <=> x^2-8x+16+1954 <=> (x-4)^2+1954 

ta có : (x-4)^2 lớn hơn hoặc = 0

           1954 >0

=> (x-4)^2+1954>0 => bt luôn dương

Bài 1 trước nha . chúc bạn học tốt . Ủng hộ nha

\(=>-9\left(x^2-\frac{4}{3}x+\frac{5}{3}\right)=>-9\left(x^2-2.\frac{2}{3}x+\frac{4}{9}+\frac{11}{9}\right)=>-9\left(x-\frac{2}{3}\right)^2-11\)

Ta có \(\left(x-\frac{2}{3}\right)^2\ge0=>-9\left(x-\frac{2}{3}\right)^2\le0,-11< 0\)

\(-9\left(x-\frac{2}{3}\right)^2-11\le0\)=> bt luôn âm

\(=>-5-x^2-x+2=>-x^2-x-3=>-x^2-2.\frac{1}{2}x+\frac{1}{4}-\frac{13}{4}\)\(=>-\left(x-\frac{1}{2}\right)^2-\frac{13}{4}\)

Ta có \(\left(x-\frac{1}{2}\right)^2\ge0=>=>-\left(x-\frac{1}{2}\right)^2\le0,-\frac{13}{4}< 0\)

\(=>-\left(x-\frac{1}{2}\right)^2-\frac{13}{4}< 0\)=> bt luôn âm

ùng hộ mình nha. cảm ơn

3/2 x 4/5 - x = 2/3

6/5 - x = 2/3

x = 6/5 - 2/3

x = 8/15

=> x = 8/15

Bài làm

\(\frac{3}{2}x\frac{4}{5}-X=\frac{2}{3}\)

       \(\frac{6}{5}-X=\frac{2}{3}\)

                  \(X=\frac{6}{5}-\frac{2}{3}\)

                  \(X=\frac{18}{15}-\frac{10}{15}\)

                 \(X=\frac{8}{15}\)

# Chúc bạn học tốt #

a)

x= 1/4 - 3/4

x= -1/2

b)

2/3x=1/7 + 3/7

2/3x=4/7

x=4/7:2/3

x=6/7

hok tốt

a) \(\left(x+3\right)^2-x\left(x-1\right)=2\)

\(\Leftrightarrow x^2+6x+9-x^2+x=2\)

\(\Leftrightarrow7x+9=2\)

\(\Leftrightarrow7x=2-9\)

\(\Leftrightarrow7x=-7\)

\(\Leftrightarrow x=\dfrac{-7}{7}=-1\)

b) \(\left(2x+3\right)^2-\left(x+1\right)\left(4x-3\right)=-1\)

\(\Leftrightarrow4x^2+12x+9-\left(4x^2-3x+4x-3\right)=-1\)

\(\Leftrightarrow4x^2+12x+9-4x^2+3x-4x+3=-1\)

\(\Leftrightarrow11x+12=-1\)

\(\Leftrightarrow11x=-13\)

\(\Leftrightarrow x=\dfrac{-13}{11}\)

a) Ta có: \(M=\dfrac{x-7}{x-4\sqrt{x}+3}+\dfrac{1}{\sqrt{x}-1}-\dfrac{1}{\sqrt{x}-3}\)

\(=\dfrac{x-7+\sqrt{x}-3-\sqrt{x}+1}{\left(\sqrt{x}-3\right)\left(\sqrt{x}-1\right)}\)

\(=\dfrac{\sqrt{x}+3}{\sqrt{x}-1}\)

b) Để \(M>\dfrac{3}{4}\) thì \(M-\dfrac{3}{4}>0\)

\(\Leftrightarrow\dfrac{\sqrt{x}+3}{\sqrt{x}-1}-\dfrac{3}{4}>0\)

\(\Leftrightarrow\dfrac{4\sqrt{x}+12-3\sqrt{x}+3}{4\left(\sqrt{x}-1\right)}>0\)

\(\Leftrightarrow\sqrt{x}-1>0\)

\(\Leftrightarrow x>1\)

Kết hợp ĐKXĐ, ta được: \(\left\{{}\begin{matrix}x>1\\x\ne9\end{matrix}\right.\)

a) -3/5

b) -9/4

c) x thuộc N*( chắc thế)

Bn giải kĩ đc k 

\(a,x+\frac{3}{4}=\frac{1}{4}\)

\(\Rightarrow x=\frac{1}{4}-\frac{3}{4}=-\frac{1}{2}\)

\(b,\frac{2}{3}x-\frac{3}{7}=\frac{1}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{1}{7}+\frac{3}{7}\)

\(\Rightarrow\frac{2}{3}x=\frac{4}{7}\)

\(\Rightarrow x=\frac{4}{7}:\frac{2}{3}=\frac{4}{7}\cdot\frac{3}{2}=\frac{6}{7}\)

\(c,1\frac{2}{3}x-50\%x=-1\frac{1}{6}\)

\(\Rightarrow\frac{5}{3}x-\frac{50}{100}x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{50}{100}\right]x=-\frac{7}{6}\)

\(\Rightarrow\left[\frac{5}{3}-\frac{1}{2}\right]x=-\frac{7}{6}\)

\(\Rightarrow\frac{7}{6}x=-\frac{7}{6}\Leftrightarrow x=-\frac{7}{6}:\frac{7}{6}=-\frac{7}{6}\cdot\frac{6}{7}=-1\)

a,x+\(\frac{3}{4}\)=\(\frac{1}{4}\)

=>x           =\(\frac{1}{4}\)-\(\frac{3}{4}\)

=> x          =\(\frac{-1}{2}\)   

Vậy x=\(\frac{-1}{2}\)

b,\(\frac{2}{3}\)x-\(\frac{3}{7}\)=\(\frac{1}{7}\)

=>\(\frac{2}{3}\)x          =\(\frac{1}{7}\)+\(\frac{3}{7}\)

=>\(\frac{2}{3}\)x           =\(\frac{4}{7}\)      

=>         x            =\(\frac{4}{7}\) :\(\frac{2}{3}\)

=>         x            =\(\frac{4}{7}\).\(\frac{3}{2}\)

=>         x             =\(\frac{6}{7}\)

Vậy x=\(\frac{6}{7}\)

c,\(\frac{12}{3}\)x-50%x   =\(\frac{-11}{6}\)

=>\(\frac{12}{3}\)x-\(\frac{1}{2}\)x=\(\frac{-11}{6}\)

=>x(\(\frac{12}{3}\)-\(\frac{1}{2}\))=\(\frac{-11}{6}\)

=>x(\(\frac{24}{6}\)-\(\frac{3}{6}\))=\(\frac{-11}{6}\)

=>x\(\frac{21}{6}\)              =\(\frac{-11}{6}\)

=>x                           =\(\frac{-11}{6}\):\(\frac{21}{6}\)

=>x                            =\(\frac{-11}{6}\).\(\frac{6}{21}\)

=>x                            =\(\frac{-11}{21}\)

Vậy x=\(\frac{-11}{21}\)

Ý c, mk tưởng 1 2/3 và -1 1/6 là phân số nên mk giải sai ý đó

BÀI GIẢI LẠI :

1\(\frac{2}{3}\)x-50%x=-1\(\frac{1}{6}\)

\(\frac{5}{3}\)x-\(\frac{1}{2}\)x=\(\frac{-7}{6}\)

x(\(\frac{5}{3}\)-\(\frac{1}{2}\))=\(\frac{-7}{6}\)

x\(\frac{7}{6}\)             =\(\frac{-7}{6}\) 

x                       =\(\frac{-7}{6}\):\(\frac{7}{6}\)

x                        =-1

Vậy x=-1

xl vì bài giải trước nha

lm ơn đi jup e vs ạ muộn nhất lak sáng mai pk  xong

mak ai chs ff nhớ alo e ạ

tuyển người kéo rank ạ