14\(\frac{1}{23}\)- \(\left(25\frac{13}{25}-10\frac{1}{23}\right)+\frac{13}{25}-2,5\)
GIUP MINH VOI!!!!!
Tính giá trị biểu thức
\(1.A=\frac{1}{5}+\frac{3}{17}-\frac{4}{3}+\left(\frac{4}{5}-\frac{3}{17}+\frac{1}{3}\right)-\frac{1}{7}+\left[\frac{-14}{30}\right]\)
\(2.B=\left(\frac{5}{8}-\frac{4}{12}+\frac{3}{2}\right)-\left(\frac{5}{8}+\frac{9}{13}\right)-\left[\frac{-3}{2}\right]+\frac{7}{-15}\)
\(3.C=\frac{5}{18}+\frac{8}{19}-\frac{7}{21}+\left(\frac{-10}{36}+\frac{11}{19}+\frac{1}{3}\right)-\frac{5}{8}\)
\(4.D=\frac{1}{9}-\left[\frac{-5}{23}\right]-\left(\frac{-5}{23}+\frac{1}{9}+\frac{25}{7}\right)+\frac{50}{14}-\frac{7}{30}\)
\(5.E=\frac{1}{13}+\left(\frac{-5}{18}-\frac{1}{13}+\frac{12}{17}\right)+\left(\frac{12}{17}+\frac{5}{18}+\frac{7}{5}\right)\)
\(6.F=\frac{15}{14}-\left(\frac{17}{23}-\frac{80}{87}+\frac{5}{4}\right)+\left(\frac{12}{17}-\frac{15}{14}+\frac{1}{4}\right)\)
\(7.G=\frac{1}{25}-\frac{4}{27}+\left(\frac{-23}{27}+\frac{-1}{25}-\frac{5}{43}\right)+\frac{5}{43}-\frac{4}{7}\)
\(8.H=\frac{4}{15}-\frac{23}{28}-\left(\frac{-23}{28}+\frac{-11}{15}-\frac{29}{27}\right)-\frac{2}{27}\)
\(9.K=\frac{1}{16}-\frac{5}{21}+\left(\frac{-1}{16}+\frac{-3}{5}-\frac{-5}{21}\right)+\frac{-2}{5}+\frac{3}{4}\)
\(10.L=\frac{7}{12}+\frac{15}{14}-\left(\frac{14}{22}+\frac{-1}{14}+\frac{5}{21}\right)-\frac{-5}{21}+\frac{3}{5}\)
yutyugubhujyikiu
Tính:
a)\(A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right);\) b) \(B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\)
a)
\(\begin{array}{l}A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\left( { - 4,6} \right)\\A = \frac{5}{{11}}.\left( {\frac{{ - 3}}{{23}}} \right).\frac{{11}}{5}.\frac{{ - 23}}{5}\\A = \frac{{5.\left( { - 3} \right).11.\left( { - 23} \right)}}{{11.23.5.5}}\\A = \frac{3}{5}\end{array}\)
b)
\(\begin{array}{l}B = \left( {\frac{{ - 7}}{9}} \right).\frac{{13}}{{25}} - \frac{{13}}{{25}}.\frac{2}{9}\\B = \frac{{13}}{{25}}.\left( {\frac{{ - 7}}{9} - \frac{2}{9}} \right)\\B = \frac{{13}}{{25}}.(-1)\\B = \frac{{-13}}{{25}}.\end{array}\)
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{13}{12}:3\)
giup voi
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{47}-3\frac{13}{12}:3\)
= \(\frac{28}{15}.\frac{3}{4}-\left(\frac{104}{195}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)
= \(\frac{4.3.7}{4.3.5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)
= \(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)
= \(1-\frac{49}{36}\)
= \(-\frac{13}{36}\)
Chúc bạn làm bài tốt
\(1\frac{13}{15}.0,75-\left(\frac{104}{195}+25\%\right).\frac{24}{27}-3\frac{13}{12}:3\)
=\(\frac{28}{15}.\frac{3}{4}-\left(\frac{8}{15}+\frac{1}{4}\right).\frac{24}{47}-\frac{49}{12}.\frac{1}{3}\)
=\(\frac{7}{5}-\frac{47}{60}.\frac{24}{47}-\frac{49}{36}\)
=\(\frac{7}{5}-\frac{2}{5}-\frac{49}{36}\)
=\(\frac{-13}{36}\)
Bài 1:
\(E=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right)\cdot230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right)\div\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
Bài 2:
\(G=\frac{4,5\div\left[47,375-\left(26\frac{1}{3}-18\cdot0,75\right)\cdot2,4\div0,88\right]}{17,81\div1,37-23\frac{2}{3}\div1\frac{5}{6}}\)
\(1\frac{13}{15}.\left(0,5\right)^2\)\(.|-3|+\left(\frac{8}{15}-25\%\right):1\frac{23}{24}\)
\(1\frac{13}{15}\cdot\left(0.5\right)^2\cdot\left|-3\right|+\left(\frac{8}{15}-25\%\right):1\frac{23}{24}\)
\(=\frac{28}{15}\cdot\frac{1}{4}\cdot3+\left(\frac{8}{15}-\frac{1}{4}\right)\cdot\frac{47}{24}\)
\(=\frac{28\cdot1\cdot3}{15\cdot4}+\frac{17}{60}\cdot\frac{47}{24}\)
\(=\frac{21}{25}+\frac{799}{1440}=\frac{10043}{7200}\)
Tính :
a) \(\frac{6}{14}+\frac{8}{-36}-\frac{5}{35}=\)
b) \(\frac{31}{23}-\left(\frac{7}{32}+\frac{8}{23}\right)\)
c) \(\frac{10}{17}+\frac{5}{13}+\frac{-7}{17}-\frac{8}{13}+\frac{11}{25}\)
a)\(\frac{6}{14}+\frac{8}{-36}-\frac{5}{35}=\frac{3}{7}+\frac{2}{-9}-\frac{1}{7}=\frac{2}{7}+\frac{2}{-9}=\frac{-18+14}{-63}=\frac{4}{63}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{7}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)
\(A=\frac{\left(13\frac{1}{4}-2\frac{5}{27}-10\frac{5}{6}\right).230\frac{1}{25}+46\frac{3}{4}}{\left(1\frac{3}{10}+\frac{10}{3}\right):\left(12\frac{1}{3}-14\frac{2}{7}\right)}\)