rút gọn \(\frac{x^4-4x^3+x^2+6x+12 }{x^2-2x+12}\)
Những câu hỏi liên quan
rút gọn các phân thức sau:
a) \(A=\frac{x^2-9}{x^2-6x+9}\)
b) \(B=\frac{9x^2-16}{3x^2-4x}\)
c) \(C=\frac{x^2+4x+4}{2x+4}\)
d) \(D=\frac{2x-x^2}{x^2-4}\)
e)\(E=\frac{3x^2+6x+12}{x^3-8}\)
giải hộ e vs ạ
Trả lời:
a, \(A=\frac{x^2-9}{x^2-6x+9}=\frac{\left(x-3\right)\left(x+3\right)}{\left(x-3\right)^2}=\frac{x+3}{x-3}\)
b, \(B=\frac{9x^2-16}{3x^2-4x}=\frac{\left(3x-4\right)\left(3x+4\right)}{x\left(3x-4\right)}=\frac{3x+4}{x}\)
c, \(C=\frac{x^2+4x+4}{2x+4}=\frac{\left(x+2\right)^2}{2\left(x+2\right)}=\frac{x+2}{2}\)
d, \(D=\frac{2x-x^2}{x^2-4}=\frac{x\left(2-x\right)}{\left(x-2\right)\left(x+2\right)}=-\frac{x\left(x-2\right)}{\left(x-2\right)\left(x+2\right)}=-\frac{x}{x+2}\)
e, \(E=\frac{3x^2+6x+12}{x^3-8}=\frac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\frac{3}{x-2}\)
câu 1 |: phan tich da thuc thanh nhan tử x^3 +3x^2-3x-1
\câu 2 làm tính chia
a,( x^4 -2x^3 +2x-1 ) : (x^2-1)
\b, (x^6 -2x^5+2x^4+6x^3-4x^2) : (6x^2)
\cau3 rút gọn phân thức \(\frac{3x^2+6x^2+12}{x^3-8}\)
\mọi người làm gấp với a! lam dc cau nào nhờ giai hộ
câu 1:
x3-1+3x2-3x =(x-1)(x^2+x+1)+3x(x-1)=(x-1)(x^2+x+1+3x)=(x-1)(x^2+4x=1)
Đúng 0
Bình luận (0)
Câu 2 :
a) \(\left(x^4-2x^3+2x-1\right):\left(x^2-1\right)\)
\(=\left(x^4-x^2-2x^3+2x+x^2-1\right):\left(x^2-1\right)\)
\(=\left[x^2\left(x^2-1\right)-2x\left(x^2-1\right)+\left(x^2-1\right)\right]:\left(x^2-1\right)\)
\(=\left(x^2-1\right)\left(x^2-2x+1\right):\left(x^2-1\right)\)
\(=x^2-2x+1\)
b) \(\left(x^6-2x^5+2x^4+6x^3-4x^2\right):6x^2\)
\(=\frac{1}{6}x^4-\frac{1}{3}x^3+\frac{1}{3}x^2+x-\frac{2}{3}\)
Câu 3 :
Sửa đề :
\(\frac{3x^2+6x+12}{x^3-8}=\frac{3\left(x^2+2x+4\right)}{\left(x-2\right)\left(x^2+2x+4\right)}=\frac{3}{x-2}\)
Đúng 0
Bình luận (0)
Rút gọn:
a) \(\frac{4x^3-8x^2+4x}{x^2-6x+5}\)
b)\(\frac{4x^3-64x}{x^2-7x+12}\)
c) \(\frac{x^2-6x+8}{x^3-8}\)
\(a.=\frac{4x\left(x^2-2x+1\right)}{x^2-1x-5x+5}\)
\(=\frac{4x\left(x-1\right)^2}{x\left(x-1\right)-5\left(x-1\right)}\)
\(=\frac{4x\left(x-1\right)^2}{\left(x-5\right)\left(x-1\right)}\)
\(=\frac{4x\left(x-1\right)}{x-5}\)
b) \(\frac{4x^3-64x}{x^2-7x+12}\)
\(=\frac{4x\left(x^2-16\right)}{x^2-3x-4x+12}\)
\(=\frac{4x\left(x+4\right)\left(x-4\right)}{x\left(x-3\right)-4\left(x-3\right)}\)
\(=\frac{4x\left(x+4\right)\left(x-4\right)}{\left(x-4\right)\left(x-3\right)}\)
\(=\frac{4x\left(x+4\right)}{x-3}=\frac{4x^2+16x}{x-3}\)
c) \(\frac{x^2-6x+8}{x^3-8}\)
\(=\frac{x^2-2x-4x+8}{\left(x-2\right)\left(x^2+2x+4\right)}\)
\(=\frac{x\left(x-2\right)-4\left(x-2\right)}{\left(x-2\right)\left(x^2+2x+4\right)}\)
\(=\frac{\left(x-4\right)\left(x-2\right)}{\left(x-2\right)\left(x^2+2x+4\right)}\)
\(=\frac{x-4}{x^2+2x+4}\)
A=\(\frac{6x-\left(x+6\right)\sqrt{x}-3}{2\left(x-4\sqrt{x}+3\right)\left(2-\sqrt{x}\right)}-\frac{3}{-2x+10\sqrt{x}-12}-\frac{1}{3\sqrt{x}-x-2}\)
Rút gọn
d,5x+10/4x-8.4-2x/x+2
Bài 2: rút gọn
a, 6x ² y ³/8x ³y ²
b, x ³-x/3x+3
c, x ²+3xy/x ²-9y ²
d, x ²+4x+4/3x+6
Bài 3: Thực hiện phép tính
a, (x/x-3+(9-6x/x ²-3x)
b, 1/x-1/x+1
c, (x-12/6x-36)+(6/x ²-6x)
d, (6x-3/x):(4x ²-1/3x ²)
e, (x+y/2x-2y)-(x-y/2x+2y)-(y ²+x ²/y ²-x ²)
f, 7x+6/2x(x+7)-3x+6/2x ²+14x
g, (2/x+2-4/x ²+4x+4):(2/x ²-4+1/2-x)
rút gọn
4x^2+3x+3/(x+3)(x-3) . 2.(x+3)(x-3)/6x-12
Rút gọn:
a) \(\frac{x^2-2x-8}{x^2+x-12}\)
b) \(\frac{x^4-5x^2+4}{x^4-x^2+4x-4}\)
b) \(\frac{x^4-5x^2+4}{x^4-x^2+4x-4}\)
\(=\frac{x^4-x^2-4x^2+4}{x^2\left(x^2-1\right)+4\left(x-1\right)}\)
\(=\frac{\left(x^2-1\right)\left(x^2-4\right)}{\left(x-1\right)\left(x^3+x^2+4\right)}\)
\(=\frac{\left(x-1\right)\left(x+1\right)\left(x-2\right)\left(x+2\right)}{\left(x-1\right)\left(x^3+x^2+4\right)}\)
\(=\frac{\left(x-1\right)\left(x+1\right)\left(x-2\right)\left(x+2\right)}{\left(x-1\right)\left(x+2\right)\left(x^2-x+2\right)}\)
\(=\frac{x^2-x-2}{x^2-x+2}\)
Đúng 0
Bình luận (0)
Rút gọn biểu thức
A= -(3x+7)+(5x-2)+(2x-10)
B= (6x+8)-(4x-5)-3x
C= 2.(5x+3)-(2x-1)+12
D=(x+7)-3.(x+1)+2x-5
A=-(3x+7)+(5x-2)+(2x-10)
=-3x-7+5x-2+2x-10
=(-3x+5x+2x)-(7+2+10)
=4x-19
B = (6x+8)-(4x-5)-3x
= 6x+8-4x+5-3x
= (6x-4x-3x) + (8+5)
= -x + 13
= 13-x
C = 2(5x+3) - (2x-1) + 12
= 10x+6 - 2x + 1 + 12
= (10x-2x) + (6+1+12)
= 8x + 19
D = (x+7)-3(x+1)+2x-5
= x+7-3x-3+2x-5
= (x-3x+2x) + (7-3-5)
= -1
Đúng 0
Bình luận (0)
$\frac{4x+3}{5}$ -$\frac{6x-2}{7}$ =$\frac{5x+4}{3}$ +3
b.
$\frac{x+4}{5}$ -x+4=$\frac{x}{3}$ -$\frac{x-2}{2}$
c.$\frac{5x+2}{6}$ -$\frac{8x-1}{3}$ =$\frac{4x+2}{5}$ -5
d.$\frac{2x+3}{3}$ =$\frac{5-4}{2}$
e. $\frac{5x+3}{12}$ =$\frac{1+2x}{9}$
f.$\frac{7x-1}{6}$ =$\frac{16-x}{5}$
g. $\frac{x-3}{5}$ =6-$\frac{1-2x}{3}$
h. $\frac{3x-2}{6}$ -5=$\frac{3-2(x+7)}{4}$
giúp vs ạ, cần gấp
d: =>4x+6=15x-12
=>4x-15x=-12-6=-18
=>-11x=-18
hay x=18/11
e: =>\(45x+27=12+24x\)
=>21x=-15
hay x=-5/7
f: =>35x-5=96-6x
=>41x=101
hay x=101/41
g: =>3(x-3)=90-5(1-2x)
=>3x-9=90-5+10x
=>3x-9=10x+85
=>-7x=94
hay x=-94/7
Đúng 3
Bình luận (1)