A=3*5*7*11*13*37-10101/1212120+40404

A=10101*(55-1)/10101*(120+4)

A=55-1/120+4

A=54/124=27/62

A=\(\frac{\left(5.11\right)\left(3.7.13.37\right)-10101}{12.10101+4.10101}\)

A=\(\frac{55.10101-10101}{12.10101+4.10101}\)

A=\(\frac{54.10101}{16.10101}\)

A=\(\frac{54}{16}=3,375\)

.5.7.11.13.37-10101/1212120+40404

=3.5.7.11.13.37-10101/1212120.1/10+40404 (vì 1/1212120=1/121212.1/10)

= 3.37.7.11.13.5-101010/121212.1/100+40404

=111.1001.5-5/6.1/100+40404

=151515.5-250/3

=595959-250/3

=1787876/3

1787876/3

A=3.5.7.11.13.37-10101/1212120+40404

A=(5.11).(3.7.13.37)-10101/10101.120+4.10101

A=55.10101-10101/10101.(120+4)

A=10101.(55-1)/10101.124

A=54/124

A=27/62

A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62

đúng nhé

Ta có:

\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)

\(=\frac{\left(3.7.11.13.37\right).5-10101.1}{120.10101+4.10101}\)

\(=\frac{10101.\left(5-1\right)}{10101.\left(120+4\right)}\)

\(=\frac{4}{124}=\frac{1}{31}\)

Sai rồi:

A = 5.11.(3.7.13.37) - 10101/(10101.120 + 10101.4)

= (5.11.10101 - 10101)/(10101.120+10101.4)

= 10101(5.11-1)/10101(120+4)

= 27/62.

A= 5.11.(3.7.13.37)-10101/(10101.120+10101.4)

=(5.11.10101-10101)/(10101.120+10101.4)

=10101.(5.11-1)/10101(120+4)

=27/62

k mik nha mik k lại 100 cái lun

A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62

\(=\frac{27}{62}\)

tíck mik nha

A= [5.11.10101 -10101]/[10101.120+10101.4] = 10101.[5.11-1] / 101.[120+4] = 54/124=27/62

\(A=\frac{3.5.7.11.13.37-10101}{1212120+40404}\)

\(A=\frac{\left(3.7.13.17\right).\left(5.11\right)-10101}{120.10101+4.10101}\)

\(A=\frac{10101.55-10101.1}{120.10101+4.10101}\)

\(A=\frac{10101.\left(55-1\right)}{10101.\left(120+4\right)}\)

\(A=\frac{10101.54}{10101.124}\)

\(A=\frac{54}{124}\)

\(A=\frac{27}{62}\)

- chúc bn hok tốt

#Hạ 

Rút gọn A=27/62.. check mk nhá

Rút gọn A = 27/62 

k cho mình nhé

\(A=\frac{3x5x7x11x13x37-10101}{1212120+40404}=\frac{545454}{1252524}=\frac{27}{62}\)

ai tích mình tích lại