\(\Leftrightarrow2\left(x-1\right)\left(x+5\right)-4\left(x-1\right)=0\)

=>(x-1)(x+3)=0

=>x=1 hoặc x=-3

\(\Leftrightarrow2\left(x-1\right)\left(x+5\right)-4\left(x-1\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+5-2\right)=0\\ \Leftrightarrow\left(x-1\right)\left(x+3\right)=0\\ \Leftrightarrow\left[{}\begin{matrix}x=1\\x=-3\end{matrix}\right.\)

d) \(2x^2+5x-7=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=1\\x=-\dfrac{7}{2}\end{matrix}\right.\) \(\left(a+b+c=1\right)\)

a; \(\dfrac{2}{3}\)\(x\) - \(\dfrac{3}{2}\)\(x\) = \(\dfrac{5}{12}\)

    (\(\dfrac{2}{3}\) - \(\dfrac{3}{2}\))\(x\) = \(\dfrac{5}{12}\)

     - \(\dfrac{5}{6}\)\(x\) = \(\dfrac{5}{12}\)

     \(x\)   = \(\dfrac{5}{12}\) : (- \(\dfrac{5}{6}\))

     \(x=\) - \(\dfrac{1}{2}\)

Vậy \(x=-\dfrac{1}{2}\) 

b; \(\dfrac{2}{5}\) + \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\)

           \(\dfrac{3}{5}\).(3\(x\) - 3,7) = \(\dfrac{-53}{10}\) - \(\dfrac{2}{5}\)

          \(\dfrac{3}{5}\).(3\(x\) - 3,7) = - \(\dfrac{57}{10}\)

         3\(x\) - 3,7 = - \(\dfrac{57}{10}\) : \(\dfrac{3}{5}\)

         3\(x\)   - 3,7 = - \(\dfrac{19}{2}\)

         3\(x\)         = - \(\dfrac{19}{2}\) + 3,7

          3\(x\)        = - \(\dfrac{29}{5}\)

           \(x\)         = - \(\dfrac{29}{5}\) : 3

           \(x\)        = - \(\dfrac{29}{15}\)

Vậy \(x\) \(\in\) - \(\dfrac{29}{15}\) 

c; \(\dfrac{7}{9}\) : (2 + \(\dfrac{3}{4}\)\(x\)) + \(\dfrac{5}{9}\) = \(\dfrac{23}{27}\)

    \(\dfrac{7}{9}\): (2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{23}{27}\) - \(\dfrac{5}{9}\)

     \(\dfrac{7}{9}\):(2 + \(\dfrac{3}{4}\)\(x\)) = \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) = \(\dfrac{7}{9}\) : \(\dfrac{8}{27}\)

      2 + \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{21}{8}\)

             \(\dfrac{3}{4}x\) = \(\dfrac{21}{8}\) - 2

             \(\dfrac{3}{4}\)\(x\) =  \(\dfrac{5}{8}\)

               \(x\) = \(\dfrac{5}{8}\) : \(\dfrac{3}{4}\)

              \(x\) =  \(\dfrac{5}{6}\)

Vậy \(x=\dfrac{5}{6}\)

Sao không viết câu hỏi ra đây luôn đi chứ có thể nhièu người biết mà không có sách lắm! Sao hướng dẫn được

Câu hỏi đâu bạn?

Bn giúp Mik nhé hiro

các thầy cô giúp em với ạ, em cảm ơn nhiều ạ:33

\(-12\cdot\left(x-5\right)+7\cdot\left(3-x\right)=5\\ -12\cdot x+60+21-7x=5\\ x\left(-12-7\right)+\left(60+21\right)=5\\ x\cdot\left(-19\right)+81=5\\ x\left(-19\right)=-76\\ x=4\)

-12x + 60 + 21 - 7x = 5

-19x = -76

x = 4

\(\left(\dfrac{5}{6}+\dfrac{7}{x}\right)-\dfrac{16}{12}=\dfrac{2}{3}\)

\(\Rightarrow\dfrac{5}{6}+\dfrac{7}{x}=\dfrac{2}{3}+\dfrac{16}{12}=\dfrac{8}{12}+\dfrac{16}{12}=\dfrac{24}{12}=2\)

\(\Rightarrow\dfrac{7}{x}=2-\dfrac{5}{6}=\dfrac{12}{6}-\dfrac{5}{6}=\dfrac{7}{6}\)

=> x = 6

(\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\)) - \(\dfrac{16}{12}\) = \(\dfrac{2}{3}\)

\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\) = \(\dfrac{2}{3}\) + \(\dfrac{16}{12}\)

\(\dfrac{5}{6}\) + \(\dfrac{7}{x}\) = 2

\(\dfrac{7}{x}\) = 2 - \(\dfrac{5}{6}\)

\(\dfrac{7}{x}\) = \(\dfrac{1}{6}\)

\(x\) = 6 x (7 : 1)

\(x\) = 6 x 7

\(x\) = 42

#Yu

⇒56+7x=23+1612=812+1612=2412=2⇒56+7x=23+1612=812+1612=2412=2