\(\frac{9}{5}.x=\frac{18}{25}\)

\(x=\frac{18}{25}:\frac{9}{5}=\frac{18}{25}.\frac{5}{9}\)

\(x=\frac{2}{5}\)

\(x-20\%.x=2,5\)

\(x\left(1-20\%\right)=2,5\)

\(x.0,8=2,5\)

\(x=2,5:0.8\)

\(x=\frac{25}{8}=3,125\)

\(a,\Rightarrow x=\dfrac{-120}{-15}=8\\ b,\Rightarrow x=\dfrac{15}{-5}=-3\\ c,\Rightarrow x=\dfrac{140}{-20}=-7\\ d,\Rightarrow x^2=5^2=\left(-5\right)^2\Rightarrow\left[{}\begin{matrix}x=5\\x=-5\end{matrix}\right.\\ e,\Rightarrow4x=-8\Rightarrow x=-2\\ g,\Rightarrow x^2=\dfrac{-12}{-3}=4\Rightarrow\left[{}\begin{matrix}x=2\\x=-2\end{matrix}\right.\)

a: \(\dfrac{-8}{3}\cdot\dfrac{15}{24}=\dfrac{-8}{24}\cdot\dfrac{15}{3}=\dfrac{-1}{3}\cdot5=-\dfrac{5}{3}\)

b: \(=\dfrac{3}{4}\cdot\dfrac{1}{-9}=\dfrac{-1}{12}\)

c: \(x=-\dfrac{7}{6}+\dfrac{5}{8}=-\dfrac{13}{24}\)

d: \(x=-\dfrac{14}{25}-\dfrac{3}{4}=\dfrac{-56-75}{100}=\dfrac{-131}{100}\)

a, \(\left(x-158\right):6=20\)

\(x-158=20.6\)

\(x-158=120\)

\(x=120+158\)

\(x=278\)

~~~Hok tốt~~~

a) \(\left(x-158\right):6=20\)

\(\Leftrightarrow x-158=\frac{20}{6}=\frac{10}{3}\)

\(\Leftrightarrow x=\frac{10}{3}+158\)

\(\Leftrightarrow x=\frac{484}{3}\)

Vậy : \(x=\frac{484}{3}\)

b) \(x-1,25.4=2,5\)

\(\Leftrightarrow x-5=2,5\)

\(\Leftrightarrow x=2,5+5\)

\(\Leftrightarrow x=7,5\)

Vậy : \(x=7,5\)

c) \(x+0,25=\frac{43}{4}-\frac{18}{5}\)

\(\Leftrightarrow x+\frac{1}{4}=\frac{143}{20}\)

\(\Leftrightarrow x=\frac{143}{20}-\frac{1}{4}\)

\(\Leftrightarrow x=\frac{69}{10}\)

Vậy : \(x=\frac{69}{10}\)

b, \(x-1,25.4=2.5\)

\(x-5=2,5\)

\(x=2,5+5\)

\(x=7.5\)

~~~Hok tốt ~~~

a.

\(1,25\times4-x=2,5\)

\(5-x=2,5\)

\(x=5-2,5\)

\(x=2,5\)

b.

\(\left(158-x\right)\div7=20\)

\(158-x=20\times7\)

\(158-x=140\)

\(x=158-140\)

\(x=18\)

c.

\(x-0,25=\frac{43}{4}-\frac{18}{5}\)

\(x-\frac{1}{4}=\frac{43}{4}-\frac{18}{5}\)

\(x=\frac{43}{4}-\frac{18}{5}+\frac{1}{4}\)

\(x=\left(\frac{43}{4}+\frac{1}{4}\right)-\frac{18}{5}\)

\(x=\frac{44}{4}-\frac{18}{5}\)

\(x=11-\frac{18}{5}\)

\(x=\frac{37}{5}\)

a. 1,25 × 4 - x = 2,5

5- x= 2,5

x= 5-2,5

x=2,5

b.(158- x) :7= 20

158- x= 20x7

158 -x= 140

x=158- 140

x=18

c. x- 0,25= \(\frac{43}{4}+\frac{18}{5}\)

x- 0,25=14,35

x= 14,35+ 0,25

x=14,6

a. 1,25 × 4 - x = 2,5

5- x= 2,5

x= 5-2,5

x=2,5

b.(158- x) :7= 20

158- x= 20x7

158 -x= 140

x=158- 140

x=18

Trả lời :

a) \(1,25\times4-x=2,5\)

\(5-x=2,5\)

\(x=5-2,5\)

\(x=2,5\)

~HT~

1.

x : \(\dfrac{2}{9}=18\)

x = 18 x \(\dfrac{2}{9}\)

x = 4

\(\Rightarrow\) Chọn C

2. 

\(\dfrac{3}{5}\) của 4 tấn:

Đổi: 4 tấn = 4000 kg.

\(\dfrac{3}{5}\) của 4000 kg là:

  4000 x \(\dfrac{3}{5}\) = 2400 kg

\(\Rightarrow\) Chọn A

3. 25ha = ... km²

Ta có: 1ha = 0,01 km²

\(\Rightarrow\) 25ha = 0,01 x 25 = 0,25 km²

\(\Rightarrow\) Chọn C

a) Ta có: B(12) = {0;12;24;36;48;60;...}

x ∈ B(12) và 20 ≤ x ≤ 50 nên x = 24;36;48.

b) x ∈ Ư(20) và x > 8.

Ta có: x ∈ Ư(20) = {1;2;3;4;5;10;20;...}

x ∈ Ư(20) và x > 8 nên x = 10; 20.

c) Ta có: x ⋮ 5 nên x là bội của 15

B(15) = {0;15;30;45;60...} vì 0 < x ≤ 40 nên x = 15; 30.

d) Ta có: 16 ⋮ x nên x là ước của 16.

Ư(16) = {1;2;4;8;16}. Vậy x = 1,2,4,8,16.

e) Ta có: B(18) = {0;18;36;54;72;90;108}

Vì 9 < x < 120 nên x ∈ {18;36;54;72;90;108}

f) Vì 6 ⋮ (x – 1) nên (x – 1) là ước của 6.

=> (x – 1) ∈ {1;2;3;6} => x ∈ {2;3;4;7}

a= 9

b=45

A=9

B=45