53−3(x+4)=32

\(^{3^2}\).\(^{3^3}\)+\(2^3\).\(2^2\)

(\(^{2^3}\).\(^{3^3}\))+(\(2^2\).​\(^{3^2}\)​​​

=275

a) \(2^3.3^2=8.9=72\)

b) \(5^{10}:5^7=5^2=25\)

c) \(2^6:2=2^5=32\)

d) \(7^4:7^4=7^0=1\)

e) \(9^5:9^5=9^0=1\)

a) 23.32=8.9=7223.32=8.9=72

b) 510:57=52=25510:57=52=25

c) 5

32

d) $1$

e) $1$

Ta có:

\(A=\frac{3^{10}.11+3^{10}.5}{3^9.2^4}=\frac{3^{10}.\left(11+5\right)}{3^9.16}\)

\(=\frac{3^{10}.16}{3^9.16}=\frac{3.1}{1.1}=3\)

Vậy giá trị biểu thức A là 3

de lam

G = 21 mũ 2 . 14 . 125 trên 35 mũ 5 . 6\

giúp mình với

\(\left(\frac{2}{5}\right)^2+5\frac{1}{2}:\left(4,5-2\right)-0,2\)

\(=\frac{4}{25}+\frac{11}{2}:\frac{5}{2}-\frac{1}{5}\)

\(=\frac{4}{25}+\frac{11}{2}.\frac{2}{5}-\frac{1}{5}\)

\(=\frac{4}{25}+\frac{11}{5}-\frac{1}{5}\)

\(=\frac{4}{25}+\frac{55}{25}-\frac{5}{25}\)

\(=\frac{54}{25}\)

a) Đề sai

b) \(\left|x+\frac{4}{5}\right|=\frac{1}{7}\)

\(\Rightarrow\orbr{\begin{cases}x+\frac{4}{5}=\frac{1}{7}\\x+\frac{4}{5}=\frac{-1}{7}\end{cases}}\Rightarrow\orbr{\begin{cases}x=\frac{1}{7}-\frac{4}{5}\\x=\frac{-1}{7}-\frac{4}{5}\end{cases}\Rightarrow\orbr{\begin{cases}x=\frac{5}{35}-\frac{28}{35}\\x=\frac{-5}{35}-\frac{28}{35}\end{cases}\Rightarrow}\orbr{\begin{cases}x=\frac{-23}{35}\\x=\frac{-33}{35}\end{cases}}}\)

Vậy \(x=\frac{-23}{35}\)hoặc \(x=\frac{-33}{35}\)

a) \(100-\left(3.5^2-2.3^3\right)\)

\(100-\left(75-52\right)=100-23=77\)

b)\(4.5^2-3.2^3+3^9:3^7\)

\(100-24+9=85\)

c) \(\left(392:7\right).2^3-2^3+2020^0\)

\(8\left(56-1\right)+1=441\)

d) \(\left(6^2+7^2+8^2+9^2+10^2\right)-\left(1^2+2^2+3^2+4^2+5^2\right)=275\)

(lười - thông cảm :(

Đây bạn ơi a,\(100-\left(3.5^2-2.3^3\right)=100-\left(75-54\right)\))=100-19=81

b,\(4.5^2-3.2^3+\frac{3^9}{3^7}=100-24+9=85\)

c,\(\left(392:7\right).2^3-2^3+2020^0=56.2^3-2^3+1=441\)

d,\(=\left(6^2-1^2\right)+\left(7^2-2^2\right)+\left(8^2-3^3\right)+\left(9^2-4^2\right)+\left(10^2-5^2\right)\)

=\(5.7+5.9+5.11+5.13+5.15=5\left(7+9+11+13+15\right)\)

=\(5.55=275\)

\(4^3:8\cdot3^2-5^2+9\)

\(=8\cdot9-25+9\)

=81-25

=56