x-15/73 +x-13/71 \< x-19/69 + x-9/67
\(\frac{x-85}{15}+\frac{x-73}{13}+\frac{x-67}{11}+\frac{x-64}{9}=10\)
\(\frac{x-85}{15}+\frac{x-74}{13}+\frac{x-67}{11}+\frac{x-64}{9}=10\\ \Leftrightarrow\left(\frac{x-85}{15}-1\right)+\left(\frac{x-74}{13}-2\right)+\left(\frac{x-67}{11}-3\right)+\left(\frac{x-64}{9}-4\right)=10-10\\ \Leftrightarrow\frac{x-100}{15}+\frac{x-100}{13}+\frac{x-100}{11}+\frac{x-100}{9}=0\\ \Leftrightarrow\left(x-100\right)\left(\frac{1}{15}+\frac{1}{13}+\frac{1}{11}+\frac{1}{9}\right)\Leftrightarrow x-100=0\left(Vi\frac{1}{15}+\frac{1}{13}+\frac{1}{11}+\frac{1}{9}\ne0\right)\Leftrightarrow x=100\)
1. Giải các phương trình sau :
a. \(\frac{x-15}{73}\) + \(\frac{x-13}{71}\) < hoặc = \(\frac{x-11}{69}\) + \(\frac{x-4}{67}\)
b. \(\frac{x-2x-4}{\left(x+1\right)\left(x-3\right)}\) > 1
2. Giải và biện luận theo m :
m(2x - m ) > hoặc = 2(x-m)+1
a,-15-(-36)
b, -67-43
c, -65-(-89)
d, -73-(-18)
e,69-71
g, 73- (-27)
h, 63-(-98)
Tính giá trị biểu thức bằng 1 cách hợp lí nhất nhé
a= 11 b=-110 c=24 d=-55 e=-3 g=100 h=161
tìm x
71-(33+x)=76
(x+73)-26=76
45-(x+9)=6
x-73-(-14)=45
(x-7)-25=-13
(x-4)-120= -100
a) 71-(33+x) = 76
71-33-x=76
38-x=76
x = -38
các bài cn lại bn lm tương tự nha!
71 - ( 33 + x ) = 76
33 + x = -5
x = -38
Vậy .....
( x + 73 ) - 26 = 76
x + 73 = 102
x = 29
Vậy ....
tìm x biết x-13/87+x-27/73+x-67/33+x-73/27=|1-4|.2019^0+1
a,-8/3+7/5+-71/15<x<-13/7+19/14+-7/2
b,-19/6+-15/2+11/3<x<-5/4+19/12+-10/3
c,-6/7+3/35<x<-2/5+3/7
d,x=3/4+1/-12
e,x/14=1/7+-3/14
f,11/18+13/6=85/x
g,8/17+5/17<x/17<6/17+9/17
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)
<=>\(\dfrac{x-13}{87}-1+\dfrac{x-27}{73}-1+\dfrac{x-67}{83}-1+\dfrac{x-73}{27}-1=0\)
<=>\(\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)
<=>\(\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)
Do \(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}>0\)
=>x-100=0
<=>x=100
\(\dfrac{x-13}{87}+\dfrac{x-27}{73}+\dfrac{x-67}{83}+\dfrac{x-73}{27}=4\)
\(\Rightarrow\left(\dfrac{x-13}{87}-1\right)+\left(\dfrac{x-27}{73}-1\right)+\left(\dfrac{x-67}{83}-1\right)+\left(\dfrac{x-73}{27}\right)=0\)
\(\Rightarrow\dfrac{x-100}{87}+\dfrac{x-100}{73}+\dfrac{x-100}{83}+\dfrac{x-100}{27}=0\)
\(\Rightarrow\left(x-100\right)\left(\dfrac{1}{87}+\dfrac{1}{73}+\dfrac{1}{83}+\dfrac{1}{27}\right)=0\)
\(\Rightarrow x-100=0\Rightarrow x=100\)
\(\frac{x-2}{71}+\frac{x-4}{69}=\frac{x-6}{67}+\frac{x-8}{65}\)
giải hộ tớ vơi. mai tớ ktra rồi
\(\frac{x-2}{71}+\frac{x-4}{69}=\frac{x-6}{67}+\frac{x-8}{65}\)
\(\Leftrightarrow\frac{x-2}{71}-1+\frac{x-4}{69}-1=\frac{x-6}{67}-1+\frac{x-8}{65}-1\)
\(\Leftrightarrow\frac{x-73}{71}+\frac{x-73}{69}=\frac{x-73}{67}+\frac{x-73}{65}\)
\(\Leftrightarrow\frac{x-73}{71}+\frac{x-73}{69}-\frac{x-73}{67}-\frac{x-73}{65}=0\)
\(\Leftrightarrow\left(x-73\right)\left(\frac{1}{71}+\frac{1}{69}-\frac{1}{67}-\frac{1}{65}\right)=0\)
Mà \(\frac{1}{71}+\frac{1}{69}-\frac{1}{67}-\frac{1}{65}\ne0\)
\(x-73=0\Leftrightarrow x=73\)
\(\frac{x-2}{71}-1+\frac{x-4}{69}-1=\frac{x-6}{67}-1+\frac{x-8}{65}-1\)
\(\Leftrightarrow\frac{x-73}{71}+\frac{x-73}{69}=\frac{x-73}{67}+\frac{x-73}{65}\)
\(\Leftrightarrow\left(x-3\right)\left(\frac{1}{71}+\frac{1}{69}-\frac{1}{67}-\frac{1}{65}\right)=0\)
\(\Rightarrow...\)
Ta có: \(\frac{x-2}{71}+\frac{x-4}{69}=\frac{x-6}{67}+\frac{x-8}{65}\)
\(\frac{x-2}{71}+\frac{x-4}{69}-2=\frac{x-6}{67}+\frac{x-8}{65}\)
\(\frac{x-2}{71}-1+\frac{x-4}{69}-1=\frac{x-6}{67}-1+\frac{x-8}{65}-1=0\)
\(\frac{x-73}{71}+\frac{x-73}{69}-\frac{x-6}{67}-\frac{x-8}{65}=0\)
\(\left(x-73\right)\left(\frac{1}{71}+\frac{1}{69}-\frac{1}{67}-\frac{1}{65}\right)=0\)
\(\left(\frac{1}{71}+\frac{1}{69}-\frac{1}{67}-\frac{1}{65}\right)\ne0\)
=> x - 73 = 0 <=> x = 73
Vậy x = 73.
(x-85)/15 + (x-74)/13 + (x-67)/11 + (x-64)/9 = 10