\(4800:x+\frac{130}{4}+255=7,3\times50\)

\(4800:x+\frac{130}{4}+\frac{255\times4}{4}=365\)

\(4800:x+\frac{130}{4}+\frac{1020}{4}=365\)

\(4800:x+\frac{130+1020}{4}=365\)

\(4800:x+\frac{1150}{4}=365\)

\(4800:x+\frac{575}{2}=365\)

\(4800:x=365-\frac{575}{2}\)

\(4800:x=\frac{365\times2}{2}-\frac{575}{2}\)

\(4800:x=\frac{730}{2}-\frac{575}{2}\)

\(4800:x=\frac{730-575}{2}\)

\(4800:x=\frac{155}{2}\)

\(x=4800:\frac{155}{2}\)

\(x=\frac{1920}{31}\)

Chúc Em Học Tốt !

giải hộ em bài nữa nha :X/27=3/X

\(\frac{x}{27}=\frac{3}{x}\)

\(x\times x=27\times3\)

\(x^2=81\)

\(x=\sqrt{81}\)

\(x=9\)

a: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{2001}{2000}=\dfrac{2001}{2}\)

b: \(=10.1\left(340+120-270\right)=10.1\cdot190=101\cdot19=1919\)

c: \(=24\%+8\%+59\%+9\%=1\)

giup m nha minh s tick

X =  150

150 nhá bạn tick cho mình nhá

a: \(=\dfrac{3}{2}\cdot\dfrac{4}{3}\cdot...\cdot\dfrac{2001}{2000}=\dfrac{2001}{2}\)

b: \(=101\left(34+13-27\right)=101\cdot20=2020\)

c: \(=24\%+8\%+59\%+9\%=1\)

tinh trong ngoac truoc =12/3 nhan cho x

suy ra lay 36 : 12/3=9

con bai b ban ket hop cac gia tri la voi nhau vi phep cong co tinh chat ket hop

lay x*57+x*50-x*7=x*57+50-7=x*100

x nhan 100 = 10000
suy ra x bang 100

thu lai ket qua di minh chac la dung

nho k cho minh nha thank

51x - ( 1+2+3+4+....+50) = 255

51x - 1275 = 255

51x = 255 + 1275

51x = 1530

x= 1530 : 51 

x =30

x+x-1+x-2+x-3+x-4+...+x-50 = 255

4800 : 8 x 4 = 2400

ĐK: ` x\ne 0; x \ne -100`

`4800/x-4800/(x+100)=8`

`<=>1/x-1/(x+100) =1/600`

`<=> (x+100-x)/(x(x+100) = 1/600`

`<=> 100/(x(x+100))=1/600`

`<=> x^2+100x = 60000`

\(\left[{}\begin{matrix}x=200\\x=-300\end{matrix}\right.\)

Vậy...

`4800/x-4800/(x+10)=8`

`ĐK:x ne 0,x ne -10`

`pt<=>600/x-600/(x+10)=1`

`<=>(600x+6000-600x)/(x^2+10x)=1`

`<=>6000/(x^2+10x)=1`

`<=>x^2+10x=6000`

`<=>x^2+10x-6000=0`

`Delta'=25+6000=6025`

`<=>x_1=20,x_2=-30`