ĐK: ` x\ne 0; x \ne -100`
`4800/x-4800/(x+100)=8`
`<=>1/x-1/(x+100) =1/600`
`<=> (x+100-x)/(x(x+100) = 1/600`
`<=> 100/(x(x+100))=1/600`
`<=> x^2+100x = 60000`
\(\left[{}\begin{matrix}x=200\\x=-300\end{matrix}\right.\)
Vậy...
`4800/x-4800/(x+10)=8`
`ĐK:x ne 0,x ne -10`
`pt<=>600/x-600/(x+10)=1`
`<=>(600x+6000-600x)/(x^2+10x)=1`
`<=>6000/(x^2+10x)=1`
`<=>x^2+10x=6000`
`<=>x^2+10x-6000=0`
`Delta'=25+6000=6025`
`<=>x_1=20,x_2=-30`