Tính B=54-1/2(1+2)-1/3(1+2+3)-...-1/12(1+2+3+...+12)
Những câu hỏi liên quan
1:tính bằng cách thuận tiện nhất:
a)54 x 113 + 45 x 113 + 113 b)3/7 + 4/9 + 8/14 + 10/18
2:tính giá trị biểu thức
a)9/5 - 1/2 + 1/3
b)12/9 x 1/12 + 1/6 x 12/9
c)3/4 x (5/6 + 2/3)
d)3/2 - 2/3 : 2
1.a,=(54+45+1).113
=100.113
=11300
b,=(3/7+8/14)+(4/9+10/18)
=1+1
=2
2.a,=13/10+1/3
=49/30
b,=12/9.(1/12+1/6)
=12/9.1/4
=1/3
c,=3/4.3/2
=9/8
d,=3/2-1/3
=7/6
Đúng 2
Bình luận (1)
1:tính bằng cách thuận tiện nhất:
a)54 x 113 + 45 x 113 + 113
= 54 x 113 + 45 x 113 + 113x1
=113 x(54+45+1)
= 113x100
=1300
b)3/7 + 4/9 + 8/14 + 10/18
=(3/7+8/14)+(4/9+10/18)
= 1 + 1
=2
Đúng 2
Bình luận (2)
M=54-1/2(1+2)-1/3(1+2+3)-1/4(1+2+3+4)-....-1/12(1+2+....+12)
\(M=54-\frac{1}{2}.\left(1+2\right)-\frac{1}{3}.\left(1+2+3\right)-....-\frac{1}{12}.\left(1+2+...12\right)\)
\(M=54-\left[\frac{1}{2}.\left(1+2\right)+\frac{1}{3}.\left(1+2+3\right)+....+\frac{1}{12}.\left(1+2+...+12\right)\right]\)
\(M=54-\left(\frac{1}{2}\cdot\frac{2.3}{2}+\frac{1}{3}\cdot\frac{3.4}{2}+....+\frac{1}{12}\cdot\frac{12.13}{2}\right)\)
\(M=54-\left(\frac{3}{2}+\frac{4}{2}+...+\frac{13}{2}\right)=54-44=10\)
Vậy M=10
Đúng 0
Bình luận (0)
Tính nhanh:
a/ (1*5*6+2*10*12+4*20*24+9*45*54)/(1*3*5+2*6*10+4*12*20+9*27*45)
b/ [(1*5*6)+(2*10*12)+(4*20*24)+(9*45*54)]/[(1*3*5)+(2*6*10)+(4*12*20)+(9*27*45)]
/ là phân số nha!!!!!!!!!!!!!
\(M=54-\frac{1}{2}\left(1+2\right)-\frac{1}{3}\left(1+2+3\right)-\frac{1}{4}\left(1+2+3+4\right)-....-\frac{1}{12}\left(1+2+3+...+12\right)\)
M = \(54-\frac{1}{2}\left(1+2\right)-\frac{1}{3}\left(1+2+3\right)-...-\frac{1}{12}\left(1+2+3+...+12\right)\)
\(54-\left(\frac{3}{2}+\frac{4}{2}+...+\frac{13}{2}\right)=54-\frac{1}{2}\left(3+4+5+...+13\right)=54-\frac{1}{2}.176=54-88\)
= -24
Tính nhanh:
a)\(A=\frac{1}{2015}-\frac{1}{2015.2014}-\frac{1}{2014.2013}-...-\)\(\frac{1}{3.2}-\frac{1}{2.1}\)
b)\(B=54-\frac{1}{2}.\left(1+2\right)-\frac{1}{3}.\left(1+2+3\right)\)\(-...-\frac{1}{12}.\left(1+2+3+..+12\right)\)
Giải Hộ Mình Pls
A=1/2015-1/2015.2014-....-1/3.2-1/2.1
A=1/2015-[1/2015.2014+1/2014.2013+....+1/3.2+1/2.1]
A=1/2015-[1/1.2+1/2.3+....1/2014.2015]
A=1/2015-[1-1/2+1/2-1/3+...+1/2014-1/2015]
A=1/2015-[1-2015]
A=1/2015-1+1/2015
A=[1/2015+1/2015]-1
A=2/2015-1
A=-2013/2015
Bài 2: Viết tiếp 2 số hạng vào dãy số sau:
a) 10, 13, 18, 26, ...
b) 0, 1, 2, 4, 7, 12, ...
c) 0, 1, 4, 9, 18, ...
d) 5, 6, 8, 10, ...
e) 1, 6, 54, 648, ... ...
k) 1, 3, 3, 9, 27,
L) 1, 2, 3, 6, 12, 24....
m) 1, 4, 9, 16, 25, 36,
o) 2, 12, 30, 56, 90,
p) 1, 3, 9, 27, ....
g) 1, 5, 14, 33, 72, h) 2, 20, 56, 110, 182.....
q) 2, 6, 12, 20, 30, ...
t) 6, 24, 60, 120, 210...
a) 10; 13; 18; 26; 36; 52...
c) 0; 1; 4; 9; 16; 25...
m) 1; 4; 9; 16; 25; 36; 49; 64...
p) 1; 3; 9; 27; 81; 243...
Đúng 1
Bình luận (0)
Tính nhanh : cho
A = 1 * 5 * 6 + 2 * 10 * 12 + 4 * 20 * 24 + 9 * 45 * 54
B = 1 * 3 * 5 + 2 * 6 * 10 + 4 * 12 * 20 + 9 * 27 * 45
Hãy tính A / B
1) x+1/2=-5/3
2) 1/3-x=3/5
4) x-4/3=-7/9
5) x--7/3=5/6
6) x-1/5=9/10
7) x+5/12=3/8
8) 5/4=7/6
9) x-2/7=1/35
10) x-2/7=-7/10
cả phép tính nữa nha
1: =>x=-5/3-1/2=-13/6
2: =>x=1/3-3/5=-4/15
4: =>x=-7/9+4/3=-7/9+12/9=5/9
5: =>x=5/6-7/3=5/6-14/6=-9/6=-3/2
6: =>x=9/10+1/5=11/10
7: =>x=3/8-5/12=36/96-40/96=-1/24
8: Đề sai rồi bạn
Đúng 1
Bình luận (0)
1)tìm x
a)(1/3-5/6.x)^3+21/54=5/6
b)1/12-1/3(1/2.x-1)^4=1/16
c)(3/5)^x-1+5.(3/5)^x-1=54/25
d)(2/3)^x+(2/3)^x+2=101/243
2) so sánh
a)1/27^11 và 1/81^8
b)1/3^99 và 1/11^21
a) => \(\left(\frac{1}{3}-\frac{5}{6}x\right)^3=\frac{5}{6}-\frac{21}{54}=\frac{24}{54}=\frac{4}{9}\)
=> \(\frac{1}{3}-\frac{5}{6}x=\sqrt[3]{\frac{4}{9}}\) => \(\frac{5}{6}x=\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\) => \(x=\frac{6}{5}.\left(\frac{1}{3}-\sqrt[3]{\frac{4}{9}}\right)\)
b) \(\frac{1}{3}\left(\frac{1}{2}x-1\right)^4=\frac{1}{12}-\frac{1}{16}=\frac{1}{48}\) => \(\left(\frac{1}{2}x-1\right)^4=\frac{3}{48}=\frac{1}{16}\)
=> \(\frac{1}{2}x-1=\frac{1}{2}\) hoặc \(\frac{1}{2}x-1=-\frac{1}{2}\)
=> \(\frac{1}{2}x=\frac{3}{2}\) hoặc \(\frac{1}{2}x=\frac{1}{2}\) => x = 3 hoặc x = 1
c) \(\left(1+5\right).\left(\frac{3}{5}\right)^{x-1}=\frac{54}{25}\) => \(\left(\frac{3}{5}\right)^{x-1}=\frac{9}{25}=\left(\frac{3}{5}\right)^2\)
=> x - 1= 2 => x = 3
d) \(\left(1+\left(\frac{2}{3}\right)^2\right).\left(\frac{2}{3}\right)^x=\frac{101}{243}\) => \(\frac{13}{9}.\left(\frac{2}{3}\right)^x=\frac{101}{243}\)
=> \(\left(\frac{2}{3}\right)^x=\frac{101}{243}:\frac{13}{9}=\frac{101}{351}\) (có lẽ đề sai)
2) \(\frac{1}{27^{11}}=\frac{1}{\left(3^3\right)^{11}}=\frac{1}{3^{33}}\); \(\frac{1}{81^8}=\frac{1}{\left(3^4\right)^8}=\frac{1}{3^{32}}\)
Vì 333 > 332 => \(\frac{1}{3^{33}}\) < \(\frac{1}{3^{32}}\) => \(\frac{1}{27^{11}}\) < \(\frac{1}{81^8}\)
b) \(\frac{1}{3^{99}}=\frac{1}{\left(3^3\right)^{33}}=\frac{1}{27^{33}}
Đúng 0
Bình luận (0)