4X-1+3=67
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tìm x
5)
4x x 5 x 4x 3 5
6)
2
2
x 2 x 1 6
7)
2
3
(3 2) 3 .
4
x x x
8) (3x + 1). (2x- 3) – 6x.(x + 2) = 16
8: =>6x^2-9x+2x-3-6x^2-12x=16
=>-19x=19
=>x=-1
Giúp Tui với
175- 4x mũ 3 =67
`#040911`
`175 - 4x^3 = 67`
`\Rightarrow 4x^3 = 175 - 67`
`\Rightarrow 4x^3 =108`
`\Rightarrow x^3 = 108 \div 4`
`\Rightarrow x^3 = 27`
`\Rightarrow x3 = 3^3`
`\Rightarrow x = 3`
Vậy, `x = 3.`
5\(x\) -3 = 4x + 6
7 - 2x = 4x - 67
a)
\(5x-3=4x+6\)
\(\Rightarrow5x-4x=6+3\)
=> x = 9
Vậy x = 9
b)
\(7-2x=4x-67\)
\(\Rightarrow7+67=4x+2x\)
\(\Rightarrow6x=74\)
\(\Rightarrow x=\frac{37}{2}\)
Vậy x = 37 / 2
*5x -3 = 4x + 6
5x - 4x = 6 + 3
=> x = 9
Vậy x = 9.
*7 - 2x = 4x - 67
7 + 67 = 4x + 2x
74 = 6x
=> x = 37/3
Vậy x = 37/3.
5x-3 =4x +6
=> 5x- 4x =3+6
=> x=9
7- 2x =4x -67
-2x-4x = -7-67
-6x = -74
=>x = -74/64
= 37/2
Phân tích đa thức sau thành nhân tử :
a, E = ( x-18 ) ( x-7 ) ( x + 35 ) (x+ 90 ) - 67\(x^2\)
b, F = 8(4x+1)(2x-3)(4x-3)(x+1) - 130
Tìm x,biết:
a, 2x+15=67-(-18)
b, 4x-12=3x-(-7)
c, 2|x-1|+3=13
a, 2x+15=67-(-18) b, 4x-12=3x-(-7) c, 2|x-1|+3=13
2x+15=67+18 4x-12=3x+7 2|x-1| = 13-3
2x+15= 85 4x-3x = 12+7 2|x-1| =10
2x =85-15 x = 19 |x-1| = 10:2
2x = 70 |x-1| = 5
x = 70:2 +) Nếu x=5 thì x-1=5 suy ra x=6
x = 35 +) Nếu x=-5 thì x-1= -5 suy ra x= -4
a, 2x + 15 = 67-(-18)
=> 2x + 15 = 67 + 18
=> 2x = 85 - 15
=> 2x = 70
=> x = 35
b, 4x - 12 = 3x-(-7)
=> 4x - 12 = 3x + 7
=> 4x - 3x = 7 + 12
=> x = 19
c, 2|x - 1| + 3 = 13
=> 2|x - 1| = 10
=> |x - 1| = 5
=> x - 1 = 5 hoặc x - 1 = -5
=> x = 6 hoặc x = -4
a) 2x + 15=67+18 b)4x-12=3x+18 c) 2|x-1|+3=13
2x +15=85 4x-3x=12+18 2|x-1|=13-3
2x=85-15 1x =30 2|x-1|=10
2x=70 x=30:1=>x=30 |x-1|=10:2
x=70:2 =>x=45 |x-1|=5=> x=5 hoặc x= -5
x-1=5=>x=5+1=>x=6
x-1=5>x=-5+1=>x=-4
câu b mình ko hỉu lắm! chúc bạn hok tốt
4x + 67 = 91
Ta có:
4x + 67 =91
4x=91-67
4x= 24
x=24:4
x=6
Vậy x=24
1.(x+1)/35 + (x+3)/33 = (x+5)/33 + (x+7)/20
2. (X+1)/12+ (X+2)/13 = (X+3)/14+ (X+4)/15
3. (X-85)/15+ (X-75)/13+(X-67)/11+ (X-64)/9=10
4. (X-1)/13-(2X-13)/15=(3X-15)/27- (4X-27)/29
2: \(\Leftrightarrow\left(\dfrac{x+1}{12}-1\right)+\left(\dfrac{x+2}{13}-1\right)=\left(\dfrac{x+3}{14}-1\right)+\left(\dfrac{x+4}{15}-1\right)\)
=>x-11=0
=>x=11
3: \(\Leftrightarrow\left(\dfrac{x-85}{15}-1\right)+\left(\dfrac{x-74}{13}-2\right)+\left(\dfrac{x-67}{11}-3\right)+\left(\dfrac{x-64}{9}-4\right)=0\)
=>x-100=0
=>x=100
|x+11/67| + |x+2/17| + |x+4/17|=4x
\(\left|x+\frac{11}{67}\right|+\left|x+\frac{2}{17}\right|+\left|x+\frac{4}{17}\right|=4x\)
Có: \(\left\{{}\begin{matrix}\left|x+\frac{11}{67}\right|\\\left|x+\frac{2}{17}\right|\\\left|x+\frac{4}{17}\right|\end{matrix}\right.>0\forall x.\)
Do đó \(4x>0\Rightarrow x>0.\)
Lúc này ta có: \(\left(x+\frac{11}{67}\right)+\left(x+\frac{2}{17}\right)+\left(x+\frac{4}{17}\right)=4x\)
⇒ \(\left(x+x+x\right)+\left(\frac{11}{67}+\frac{2}{17}+\frac{4}{17}\right)=4x\)
⇒ \(3x+\frac{589}{1139}=4x\)
⇒ \(4x-3x=\frac{589}{1139}\)
⇒ \(1x=\frac{589}{1139}\)
⇒ \(x=\frac{589}{1139}:1\)
⇒ \(x=\frac{589}{1139}\left(TM\right)\)
Vậy \(x=\frac{589}{1139}.\)
Chúc bạn học tốt!
(123-4x)-67=8
Tìm x
123-4x=8+67
123-4x=75
4x=123-75
4x=48
x=12
vậy x=12
hok tốt nhé
\(\left(123-4x\right)-67=8\)
\(\Rightarrow123-4x=75\)
\(\Rightarrow4x=48\)
\(\Rightarrow x=12\)
(123-4x)67=8
123-4x=75
4x=123-75
4x=48
x=12
tk cho mình nhé
tìm x biết(đề)
(4x+11)-(x+34)=67
mong nhận được câu trả lời:)))))
(4x+11)-(x+34)=67
<=> 4x+11-x-34=67
<=> 3x=90
<=>x= 30
4x+11)-(x+34)=67
<=> 4x+11-x-34=67
<=> 3x=90
<=>x= 30