Vì \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow2x-15=\orbr{\begin{cases}0\\1\end{cases}}\)vì chỉ có \(0^5=0^3;1^5=1^3\)

\(\Rightarrow2x=\orbr{\begin{cases}15\\16\end{cases}}\)

\(\Rightarrow x=\orbr{\begin{cases}\frac{15}{2}\\8\end{cases}}\)

\(\left(2x-15\right)^5=\left(2x-15\right)^3.\)

\(\Rightarrow\hept{\begin{cases}2x-15=0\\2x-15=1\end{cases}\Rightarrow\hept{\begin{cases}2x=15\\2x=16\end{cases}}\Rightarrow\hept{\begin{cases}x=\frac{15}{2}\\x=8\end{cases}}}\)

\(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\left(2x-15\right)^5-\left(2x-15\right)^3=0\)

\(\left(2x-15\right)^3\left[\left(2x-15\right)^2-1\right]=0\)

\(\left(2x-15\right)^3\left(2x-15-1\right)\left(2x-15+1\right)=0\)

\(\left(2x-15\right)^3\left(2x-16\right)\left(2x-14\right)=0\)

\(\Rightarrow\left(2x-15\right)^3=0\)hoac \(\orbr{\begin{cases}2x-16=0\\2x-14=0\end{cases}}\)

\(\Rightarrow2x-15=0\)hoac \(\orbr{\begin{cases}2x=16\\2x=14\end{cases}}\)

\(\Rightarrow2x=15\) hoac \(\orbr{\begin{cases}x=8\\x=7\end{cases}}\)

\(\Rightarrow x=\frac{15}{2}\)hoac \(\orbr{\begin{cases}x=8\\x=7\end{cases}}\)

      vay \(x=\frac{15}{2}\)hoac \(\orbr{\begin{cases}x=8\\x=7\end{cases}}\)

Đề là j bn ?

tìm nghiệm của đa thức trên

= 0 

\(\dfrac{x}{x-5}\cdot\left(x^2-2x-15\right)=\dfrac{x\left(x^2-5x+3x-15\right)}{x-5}=\dfrac{x\left(x-5\right)\left(x+3\right)}{x-5}=x\left(x+3\right)\)

\(2\left(x-3\right)+5⋮x-3\Rightarrow x-3\inƯ\left(5\right)=\left\{\pm1;\pm5\right\}\)

\(=x\in\left\{2;4;8\right\}\)

\(6\cdot x+9=15\)

\(\Rightarrow6\cdot x=15-9\)

\(\Rightarrow6\cdot x=6\)

\(\Rightarrow x=\dfrac{6}{6}=1\)

_______________

\(43+2x=49\)

\(\Rightarrow2x=49-43\)

\(\Rightarrow2x=6\)

\(\Rightarrow x=\dfrac{6}{2}=3\)

____________

\(x:2+5=11\)

\(\Rightarrow x:2=11-5\)

\(\Rightarrow x:2=6\)

\(\Rightarrow x=6\cdot2=12\)

______________

\(77-11x=0\)

\(\Rightarrow11x=77\)

\(\Rightarrow x=\dfrac{77}{11}\)

\(\Rightarrow x=7\)

_______________

\(12-4:x=8\)

\(\Rightarrow4:x=12-8\)

\(\Rightarrow4:x=4\)

\(\Rightarrow x=\dfrac{4}{4}=1\)

_____________

\(x:3+8=11\)

\(\Rightarrow x:3=11-8\)

\(\Rightarrow x:3=3\)

\(\Rightarrow x=3\cdot3=9\)

a: 6x+9=15

=>6x=6

=>x=1

b: 2x+43=49

=>2x=6

=>x=3

c: x:2+5=11

=>x:2=6

=>x=12

d: 77-11x=0

=>7-x=0

=>x=7

e: 12-4:x=8

=>4:x=4

=>x=1

f: x:3+8=11

=>x:3=3

=>x=9

a.x=1

b.x=3

c.x=12

d.x=7

e.x=1

f.x=9

1,=> 36x^2-12x-36x^2+27x=30

   =>15x                           =30

   =>    x                           =2

2,=>5x-2x^2+2x^2-2x=15

  =>3x                      =15

  =>x                         =5

\(\left(2x-1\right):\dfrac{10}{7}=\dfrac{28}{15}:\dfrac{4}{3}\)

\(\Rightarrow\left(2x-1\right).\dfrac{7}{10}=\dfrac{28}{15}.\dfrac{3}{4}\)

\(\Rightarrow\left(2x-1\right).\dfrac{7}{10}=\dfrac{7}{5}\)

\(\Rightarrow2x-1=\dfrac{7}{5}:\dfrac{7}{10}\)

\(\Rightarrow2x-1=\dfrac{7}{5}.\dfrac{10}{7}\)

\(\Rightarrow2x-1=2\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\dfrac{3}{2}\)

a/(x-5)^4=9x-5)^6\(\Rightarrow\) TH1:x-5=1\(\rightarrow\) x=6

                        \(\Rightarrow\) TH2:x-5=-1\(\rightarrow\) x=4

                       \(\Rightarrow\) TH3:x-5=0\(\rightarrow\) x=5

vậy....................

b/(2x-15)^5=(2x-15)^6\(\Rightarrow\) 2x-15=1\(\rightarrow\) 2x=16\(\rightarrow\)x=8

                              \(\Rightarrow\) 2x-15=0\(\rightarrow\)2x=15\(\rightarrow\)x=7.5

vậy................

a) Có : ( x-5 ) \(^4\) = ( x - 5 ) \(^6\)

\(\Rightarrow\left(x-5\right)^6:\left(x-5\right)^4=1\Rightarrow\left(x-5\right)^2=1\)

\(\Rightarrow x-5=1\) hoặc \(x-5=-1\)

\(\Rightarrow x=1+5\) hoặc \(x=-1+5\)

\(\Rightarrow x=6\) hoặc \(x=4\)

b) \(\left(2x-15\right)^5=\left(2x-15\right)^3\)

\(\Rightarrow\left(2x-15\right)^5:\left(2x-15\right)^3=1\Rightarrow\left(2x-15\right)^2=1\)

\(\Rightarrow2x-15=1\) hoặc \(2x-15=-1\)

\(\Rightarrow2x=16\) hoặc \(2x=14\)

\(\Rightarrow x=8\) hoặc \(x=7\)

a, x+35= 2x+15+(13-4)

\(\Leftrightarrow x-2x=15-35+9\)

\(\Leftrightarrow-x=-11\)

\(\Leftrightarrow x=11\)

b, 5-2x =15-(-9)-3x

\(\Leftrightarrow-2x+3x=15+9-5\)

\(\Leftrightarrow x=19\)

c, x+135 =3x -15

\(\Leftrightarrow x-3x=-15-135\)

\(\Leftrightarrow-2x=-150\)

\(\Leftrightarrow x=\frac{-150}{-2}=75\)

a) x + 35 = 2x + 15 + ( 13 - 4 )

x - 2x = - 35 + 15 + 13 - 4

-x = - 20 + 9

-x = - 11

\(\Rightarrow\) x = 11

Vậy x = 11

b) 5 - 2x = 15 - ( -9 ) - 3x

-2x + 3x = 15 + 9 - 5

x = 24 - 5

x = 19

Vậy x = 19

c) x + 135 = 3x - 15

x - 3x = -135 - 15

-2x = -150

x = -150 : (-2)

x = 75

Vậy x = 75

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