\(\Leftrightarrow x-\dfrac{3^{17}-3^{18}}{3^{16}\cdot5+3^{16}\cdot7}=0\)

=>\(x=\dfrac{3^{17}\left(1-3\right)}{3^{16}\left(5+7\right)}=3\cdot\dfrac{-2}{12}=-3\cdot\dfrac{1}{6}=-\dfrac{1}{2}\)

a.\(\frac{11^4.11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5-9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)

=\(\frac{11^4.11^5}{11^4-11^4.11}:\frac{9^8.3-9^8.9}{9^8.5-9^8.7}:\frac{10^5-10^5.3}{10^5.11}\)
=\(\frac{11^4.11^5}{11^4.\left(1-11\right)}:\frac{9^8.\left(3-9\right)}{9^8.\left(5-7\right)}:\frac{10^5.\left(1-3\right)}{10^5.11} \)
=\(\frac{11^4.11^5}{11^4.\left(-10\right)}:\frac{9^8.\left(-6\right)}{9^8.\left(-2\right)}:\frac{10^5.\left(-2\right)}{10^5.11}\)
=\(\frac{11^5}{-10}:3:\frac{-2}{11}\)
=\(\frac{11^5}{-10}.\frac{1}{3}.\frac{-11}{2}\)

Chiều mình làm tiếp cho nha!👋

11/2 mink đoán thế,số thập phân thì là 5,5

a.

\(\frac{11^4\times6-11^5}{11^4-11^5}=\frac{11^4\times\left(6-11\right)}{11^4\times\left(1-11\right)}=\frac{-5}{-10}=\frac{1}{2}\)

b.

\(\frac{9^8\times3-3^{18}}{9^8\times5+9^8\times7}=\frac{9^8\times3-\left(3^2\right)^9}{9^8\times\left(5+7\right)}=\frac{9^8\times3-9^9}{9^8\times12}=\frac{9^8\times\left(3-9\right)}{9^8\times12}=-\frac{6}{12}=-\frac{1}{2}\)

c.

\(\frac{10^5-10^5\times3}{10^5\times11}=\frac{10^5\times\left(1-3\right)}{10^5\times11}=-\frac{2}{11}\)

Chúc bạn học tốt

a)\(\frac{11^4.6-11^5}{11^4-11^5}:\frac{9^8.3-9^9}{9^8.5+9^8.7}\)

\(=1.6:\frac{9^8.3-9^8.9}{9^8.\left(5+7\right)}\)

\(=6:\frac{9^8.\left(3-9\right)}{9^8.12}\)

\(=6:\frac{9^8.\left(-6\right)}{9^8.12}\)

\(=6:\left(-\frac{6}{12}\right)\)

\(=6:\left(-\frac{1}{2}\right)\)

\(=-12\)

b) 3/5 : ( -1/5-1/6)+3/5:(-1/3-16/15) ( mình chuyển về ps luôn )

=3/5: (-11/30) + 3/5 : (-7/5) 

=3/5:[-11/30+(-7/5)]

=3/5:53/30

=18/53

c) (1/2-13/14):5/7-(-2/21+1/7):5/7

= -3/7:5/7-1/21:5/7

=(-3/7-1/21):5/7

=-10/21:5/7

=-2/3

câu b vá c mình làm tắt nha. chúc bạn học tốt

\(\frac{3^8.5^9+15^8.3^2}{15^9.3^3-3^8.5^9}\)

\(=\frac{3^8.5^9+5^8.3^{10}}{5^9.3^{12}-3^8.5^9}\)

\(=\frac{3^8.5^8.\left(5+3^2\right)}{5^9.3^8.\left(3^4-1\right)}=\frac{14}{80}=\frac{7}{40}\)

\(=\frac{15^8.5+15^8.3^2}{15^8.5.3.3^3-15^8.5}\)

\(=\frac{15^8\left(5+9\right)}{15^8\left(5.3^4-5\right)}\)

\(=\frac{15^8.14}{15^8.400}\)

\(=\frac{14}{400}\)

\(=\frac{7}{200}\)

\(\frac{3^8\cdot5+15^8\cdot3^2}{15^9\cdot3^3-3^8\cdot5^9}\)

\(=\frac{3^8\cdot5^9+5^8\cdot3^9}{5^9\cdot3^3-3^8\cdot5^9}\)

\(=\frac{3^8\cdot5^8\left(5+3^2\right)}{5^9\cdot3^8\cdot\left(3^4-1\right)}\)

\(=\frac{14}{80}=\frac{7}{40}\)

Giang ho dai ca viet nham nhé:

\(5.3^x=8.3^9+7.27^3\)

<=> \(5.3^x=8.3^9+7.\left(3^3\right)^3\) <=> \(5.3^x=8.3^9+7.3^9\)

<=> \(5.3^x=15.3^9\) <=> \(3^x=3.3^9=3^{10}\) => x = 10

nhầm chỉnh lại :

\(5.3^x=8.3^9+7.27^3\Rightarrow5.3^x=8.3^9+7.3^9=15.3^9\Rightarrow15.3^{x-1}=15.3^9\Rightarrow3^{x-1}=3^9\Rightarrow x-1=9\Rightarrow x=10\)

Có 5.3^x=8.3^9+7.27^3

=>5.3^x=8.3^9+7.(3^3)^3

=>5.3^x=8.3^9+7.3^9

=>5.3^x=3^9.(8+7)

=>5.3^x=3^9.15

=>3^x=3^9.15:5

=>3^x=3^9.3

=>3^x=3^10

=>x=10

Vậy x=10