a) \(\left(3x-1\right)^6=\left(3x-1\right)^4\)

\(\Rightarrow\left[{}\begin{matrix}3x-1=0\\3x-1=1\\3x-1=-1\end{matrix}\right.\)\(\Rightarrow\left[{}\begin{matrix}x=\dfrac{1}{3}\\x=\dfrac{2}{3}\\x=0\end{matrix}\right.\)

b) Áp dụng t/c dtsbn:

\(\dfrac{a+b-c}{c}=\dfrac{a-b+c}{b}=\dfrac{-a+b+c}{a}=\dfrac{a+b+c}{a+b+c}=1\)

\(\Rightarrow\left\{{}\begin{matrix}a+b-c=c\\a-b+c=b\\-a+b+c=a\end{matrix}\right.\)\(\Rightarrow\left\{{}\begin{matrix}a+b=2c\\a+c=2b\\b+c=2a\end{matrix}\right.\)

\(\Rightarrow M=\dfrac{\left(a+b\right)\left(b+c\right)\left(c+a\right)}{abc}=\dfrac{2a.2b.2c}{abc}=8\)

Giúp Mình Với

Mình Đang Cần Gấp

a: \(\Leftrightarrow\left(3x-1\right)^4\cdot\left(3x-2\right)\cdot3x=0\)

\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=\dfrac{1}{3}\\x=\dfrac{2}{3}\end{matrix}\right.\)

discovery -> discoveries

such -> so

a -> x

so -> such

lovely a -> a lovely

what -> that

black new -> new black 

What -> That's or such ->x

\(=\dfrac{1}{2}\times\dfrac{2}{3}\times\dfrac{3}{4}\times...\times\dfrac{2008}{2009}\)

\(=\dfrac{1}{2009}\)

=> B

B

B

⇒ Yes, I do. Because I can keep fit by doing it.

Yes. Because it brings many benefits for our health

yes.because it's good for health

Ta có :

\(\dfrac{x}{5}=\dfrac{2}{3}\)

\(\Rightarrow x.3=5.2\)

\(x.3=10\)

\(x=10:3\)

\(x=\dfrac{10}{3}\)

Vậy \(x=\dfrac{10}{3}\) là giá trị cần tìm

Ta có :\(\dfrac{x}{5}=\dfrac{2}{3}\)

\(\Rightarrow x.3=2.5\)

\(x.3=10\)

\(x=10:3\)

\(\Rightarrow x=\dfrac{10}{3}\)

Vậy \(x=\dfrac{10}{3}\)

Vậy \(x=\dfrac{10}{3}\)

Ta có: \(\dfrac{x}{5}=\dfrac{2}{3}\)

=> \(3\times x=2\times5\)

\(3\times x=10\)

\(x=10\div3\)

\(x=\dfrac{10}{3}\)

Vậy \(x=\dfrac{10}{3}\)