`!`

ta có : `5000m^3= 5000000000cm^3 ; 800dm^3=800000cm^3 ; 9m^3 =9000000cm^3`

từ bé đến lớn là : `400 000cm^3 ;800dm^3 ; 9m^3 ; 5000m^3`

a: -10/8<-1

-19/19=-1

-1<-2/10<0

0<5/12<1<17/15

=>17/15>1>5/12>-2/10>-19/19>-10/8

b: -1/3=-4/12; -5/12=-5/12; -3/4=-9/12; -1/4=-3/12; -7/12=-7/12

=>-3/4<-7/12<-5/12<-1/3<-1/4

Theo thứ tự từ lớn đến bé:\(\dfrac{17}{15};1;\dfrac{5}{12};0;\dfrac{2}{-10};-\dfrac{19}{19};-\dfrac{10}{8}\)

Theo thứ tự từ bé đến lớn : \(-\dfrac{3}{4};-\dfrac{7}{12};-\dfrac{5}{12};-\dfrac{1}{3};\dfrac{1}{-4}\)

a, 9; 7; 5; 2

b, 1; 6; 4; 8

a) 9, 7, 5 2

b) 1, 4, 6, 8

a. 9-7-5-2

b. 1-4-6-8

\(\dfrac{12}{10}\);\(\dfrac{8}{10}\);\(\dfrac{2}{5}\);\(\dfrac{9}{45}\)

\(^{ }\dfrac{12}{10}\);\(\dfrac{8}{10}\);\(\dfrac{2}{5}\);\(\dfrac{9}{45}\)

12/10 ; 8/10 ; 2/5 ; 9/45

12/10 ; 8/10 ; 2/5 ; 9/45

8/10 -> 12/20 -> 2/5 -> 9/45

Lời giải chi tiết:

a)

b)

Ta có:
\(\dfrac{6}{5}=\dfrac{6\times168}{5\times168}=\dfrac{1008}{840}\)     ;    \(\dfrac{3}{4}=\dfrac{3\times210}{4\times210}=\dfrac{630}{840}\)     ;     \(\dfrac{9}{8}=\dfrac{9\times105}{8\times105}=\dfrac{945}{840}\) 

\(\dfrac{1}{7}=\dfrac{1\times120}{7\times120}=\dfrac{120}{840}\)     ;    \(\dfrac{2}{3}=\dfrac{2\times280}{3\times280}=\dfrac{560}{840}\)

⇒ \(\dfrac{120}{840}< \dfrac{560}{840}< \dfrac{630}{840}< \dfrac{945}{840}< \dfrac{1008}{840}\) ⇒ \(\dfrac{1}{7}< \dfrac{2}{3}< \)\(\dfrac{3}{4}< \dfrac{9}{8}< \dfrac{6}{5}\)
 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 . 

2/3 , 3/4 , 6/5 , 9/8 , 1/7 .

2/3 => 8/5 => 9/5

oka~~y

thứ tự từ bế đến lớn là:2/3:8/5;9/5 nha

HT