5^x+1 = 500 + 5^x

<=> 5^x+1 - 5^x = 500

<=> 5^x( 5 - 1 ) = 500

<=> 5^x.4 = 500

<=> 5^x = 125 = 5³

<=> x = 3

Ta có \(5^{x+1}-5^x=500\)

\(\rightarrow5^x.\left(5-1\right)=500\)\(\rightarrow5^x.4=500\)

\(\rightarrow5^x=125=5^3\)

\(\rightarrow x=3\)

Ta có \(5^{x+1}-5^x=500\)

<=>\(5^x.\left(5-1\right)=500\)

<=>\(5^x.4=500\)

<=>\(5^x=500:4=125\)

<=>\(5^x=5^3\)

<=>x=3

Vậy x=3

5^x+1-5^x=500

5(5^x-1)=500

5^x-1=100

5^x =101

=>x E tập hợp rỗng

a) 2 100 : 10 = 210

    4 500 : 100 = 45

    83 000 : 1 000 = 83

b) 720 : 10 : 8 = 72 : 8 = 9

    1 500 : (5 x 100) = 1 500 : 5 : 100 = 300 : 100 = 3

    60 000 : 1 000 x 6 = 60 x 6 = 360

2,75 x10 ^10

Sai,đúng nhất là :

27.5 nghìn tỷ=27 500 000 000

x=3 nhé

5^{x + 1}  - 5^x = 500
\(\Rightarrow\)5^x . 5 - 5^x = 500
\(\Rightarrow\)5^x ( 5 - 1 ) = 500
\(\Rightarrow\)5^x . 4 = 500
\(\Rightarrow\)5^x = 125 
\(\Rightarrow\)5^x = 5³
\(\Rightarrow\)x = 3

a) (3.x - 2)³ = 2.32

=> (3.x - 2)³ = 64 = 4³

=> 3.x - 2 = 4

=> 3.x = 6

=> x = 2.

b) 5^x+1 - 5^x = 500

=>5^x.5 - 5^x = 500

=> 5^x.(5 - 1) = 500

=> 5^x.4 = 500

=> 5^x = 125 = 5³

=> x = 3

\(a,\left(3.x-2\right)^3=2.32\)

\(\Rightarrow\left(3x-2\right)^3=64\)

\(\Rightarrow\left(3x-2\right)^3=4^3\)

\(\Rightarrow3x-2=4\)

\(\Rightarrow3x=4+2=6\)

\(\Rightarrow x=2\)

\(b,5^{x+1}-5^x=500\)

\(\Rightarrow5^x.5-5^x=500\)

\(\Rightarrow5^x\left(5-1\right)=500\)

\(\Rightarrow5^x=500:4=125=5^3\)

\(\Rightarrow x=3\)

a,(3.x-2)³=64

(3.x-2)³=4³

(3.x-2)=4

3.x=4+2

3.x=6

x=6:3=2

\(5^{x+1}-5^x=500\)

\(5^x.5-5^x=500\)

\(5^x.\left(5-1\right)=500\)

\(5^x.4=500\)

\(\Rightarrow5^x=125\)

\(\Rightarrow x=3\)

( 3 x - 2 ) ³ = 2 . 2 ⁵

( 3 x - 2 ) ³ = 64

( 3 x - 2 )³  = 4 ³         

=> 3 x - 2 = 4

     3 x      = 6

        x      = 2

5 ^{x + 1}   - 5 ^x     = 500

5 ^x  . ( 5 - 1 ) = 500

5 ^x   . 4          = 500

 5 ^x               = 125

 5 ^x                       = 5 ³

=> x = 3

(3x-2)³=2.2⁵

(3x-2)³=2⁶

(3x-2)³=4³

=>3x-2=4

=>3x=6

=>x=2

5^x+1-5^x=500

5^x.5-5^x=500

5^x.(5-1)=500

5^x.4=500

=>5^x=125

=>x=5

a, (3.x-2)³=2.32

=>(3x-2)³=64

=>(3x-2)³=4³

=>3x-2=4

=>3x=6

=>x=2

b,5^x+1-5^x=500

=>5^x(5-1)=500

=>5^x*4=500

=>5^x=125

=>5^x=5³

=>x=3