a)4030110

403005

b)4022024

4022024

Ta có:

A > B

Chắc chắn 100%

a=4020025

b=4020024

  nên A > B

Ta có : A = 2005^2 = 2005.2005 = 2005.(2004+1) = 2005.2004+2005

            B = 2004.2006 = 2004.(2005+1) = 2004.2005+2004

Vì 2005.2004 = 2004.2005 và 2005 > 2004

=> 2005^2 > 2004.2006 => A >B

4 013 008

4 013 008

2004/2003

day nha ban

2004/2003

k nha

link nee

https://olm.vn/hoi-dap/detail/47059131770.html

nho ti

ck cho mk

2005 x 2005 -2004 x 2006

=4020025 -4020024

=1

2005 x 2005 -2004 x 2006 

= 4020025 - 4020024

= 1

`2005 xx 2005 -2004 xx 2006`

`= 4020025 - 4020024`

`= 1`

2005 x 2007 - \(\frac{1}{2004}\)+ 2005 x 2006

= 4024035 - \(\frac{1}{2004}\)+ 4022030

= 4024035 + 4022030

= 8046065

\(\frac{2005.2007-1}{2004+2005.2006}=\frac{2005.2006+2005-1}{2004+2005.2006}=\frac{2005.2006+2004}{2004+2005.2006}=1\)

K CHO MIK NHA!

$A=\frac{{2005}^{2005}+1}{{2005}^{2006}+1}<\frac{{2005}^{2005}+1+2004}{{2005}^{2006}+1+2004}=\frac{2005.({2005}^{2004}+1)}{2005.({2005}^{2005}+1)}==\frac{{2005}^{2004}+1}{{2005}^{2005}+1}=B.$

Vậy A < B

$A=\frac{{2005}^{2005}+1}{{2005}^{2006}+1}<\frac{{2005}^{2005}+1+2004}{{2005}^{2006}+1+2004}=\frac{2005.({2005}^{2004}+1)}{2005.({2005}^{2005}+1)}==\frac{{2005}^{2004}+1}{{2005}^{2005}+1}=B.$

Vậy A < B

$A=\frac{{2005}^{2005}+1}{{2005}^{2006}+1}<\frac{{2005}^{2005}+1+2004}{{2005}^{2006}+1+2004}=\frac{2005.({2005}^{2004}+1)}{2005.({2005}^{2005}+1)}==\frac{{2005}^{2004}+1}{{2005}^{2005}+1}=B.$

Vậy A < B

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