\(3^{8x+4}=81^{x+3}\)

\(3^{8x+4}=\left(3^4\right)^{x+3}\)

\(3^{8x+4}=3^{4x+12}\)

\(\Rightarrow8x+4=4x+12\)

\(\Rightarrow8x-4x=12-4\)

\(\Rightarrow4x=8\Rightarrow x=2\)

2

  3^{8.x + 4} = 81^{x + 3}

  3^{8.x + 4} = (3⁴)^{x + 3}

  3^{8.x + 4} = 3^{4.x + 12}

  8.x + 4 = 4.x + 12

8.x - 4.x = 12 - 4

        4.x = 8

           x = 8 : 4

           x = 2

3⁵ˣ⁺⁴ = 81ˣ⁺³

3⁵ˣ⁺⁴ = (3⁴)ˣ⁺³

3⁵ˣ⁺⁴ = 3⁴ˣ⁺¹²

5x + 4 = 4x +12

5x - 4x =12 - 4

x = 8

    `x^3 + 81x - 170 = 0`

`<=>x^3 - 2x^2 + 2x^2 - 4x + 85x - 170 = 0`

`<=> x^2 ( x - 2 ) + 2x ( x - 2 ) + 85 ( x - 2 ) = 0`

`<=> ( x - 2 ) ( x^2 + 2x + 85 ) = 0`

`<=> ( x - 2 ) [ ( x + 1 )^2 + 84 ] = 0`

  Mà `( x + 1 )^2 + 84 > 0 AA x`

   `=> x - 2 = 0`

`<=> x = 2`

Vậy `S = { 2 }`

`#3107`

\(3^{8x+4}=81^{x+3}\\ \Rightarrow3^{8x+4}=\left(3^4\right)^{x+3}\\ \Rightarrow3^{8x+4}=3^{4x+12}\\ \Rightarrow8x+4=4x+12\\ \Rightarrow8x-4x=12-4\\ \Rightarrow4x=8\\ \Rightarrow x=8\div4\\ \Rightarrow x=2\\ \text{Vậy, x = 2.}\)

Lời giải:

$3^{8x+4}=81^{x+3}$

$3^{8x+4}=(3^4)^{x+3}$

$3^{8x+4}=3^{4(x+3)}$

$\Rightarrow 8x+4=4(x+3)$
$\Rightarrow 2x+1=x+3$

$\Rightarrow x=2$

\(3^{8x+4}=81^{x+3}\)

\(\Rightarrow\left(3^4\right)^{2x+1}=81^{x+3}\)

\(\Rightarrow81^{2x+1}=81^{x+3}\)

\(\Rightarrow2x+1=x+3\)

\(\Rightarrow2x-x=3-1\)

\(\Rightarrow x=2\)

\(A\left(x\right)=43x-\left(52x^2+34x^2-8x^4\right)-\left(8x^4+16x^3-42x^2+43x\right)+19\)

\(\Leftrightarrow A\left(x\right)=43x-86x^2+8x^4-16x^3+42x^2-43x+19\)

\(\Leftrightarrow A\left(x\right)=-16x^3-44x^2+19\)

Bậc là: 3

Thực hiện phá ngoặc lần lượt và rút gọn VT = -73x + 36.

Giải phương trình -73x + 36 = 182 thu được x = -2.