Bài 1:

a. $(-20)+x=-30$

$x-20=-30$

$x=-30+20=-(30-20)=-10$

b.

$(-10)-x=-20$

$x=(-10)-(-20)=-10+20=20-10=10$

c. Đề sai. Bạn xem lại.

d.

$x+(-3)=-7$

$x=-7-(-3)=-7+3=-(7-3)=-4$

e.

$x-(-5)=-9$

$x=(-9)+(-5)=-14$

f.

$x(-11)=12$

$x=\frac{12}{-11}=\frac{-12}{11}$

h.

$2x-10=20$

$2x=20+10=30$

$x=30:2=15$

l.

$4x-8=-8$
$4x=-8+8=0$

$x=0:4=0$

k.

$-12-(-2)x=-8$

$(-2)x=-12-(-8)=-12+8=-(12-8)=-4$

$x=(-4):(-2)=2$

Bài 2:

a. $-20-(10-x)=-3$

$10-x=-20-(-3)=-20+3=-(20-3)=-17$

$x=10-(-17)=10+17=27$

b.

$14+(14-x)=-2$
$14-x=-2-14=-16$

$x=14-(-16)=14+16=30$

c.

$-15-(x-3)=-7$

$x-3=-15-(-7)=-15+7=-8$

x=-8+3=-5$

d.

$(x+4)+(-20)=-8$

$x+4=-8-(-20)=-8+20=12$
$x=12-4=8$

e.

$-2x-2=-4$

$-2x=-4+2=-2$

$x=(-2):(-2)=1$

f.

$-2x+4=-4$

$-2x=-4-4=-8$

$x=(-8):(-2)=4$

l.

$-12-(-2)x=-2-4=-6$

$(-2)x=-12-(-6)=-12+6=-6$

$x=(-6):(-2)=3$

tính trừ bt nha bạn vế thương thì cũng tĩnh ra xong mới tính nha

a, \(x\) + \(\dfrac{1}{4}\) - \(\dfrac{3}{8}\) = \(\dfrac{7}{12}\)

    \(x\) - \(\dfrac{1}{8}\) = \(\dfrac{7}{12}\)

    \(x\)       = \(\dfrac{7}{12}\) + \(\dfrac{1}{8}\)

     \(x\)      = \(\dfrac{17}{24}\)

b, \(x\) - \(\dfrac{3}{14}\) = \(\dfrac{5}{14}\) + \(\dfrac{15}{21}\)

    \(x\)  - \(\dfrac{3}{14}\) = \(\dfrac{15}{14}\)

    \(x\)          = \(\dfrac{15}{14}\) + \(\dfrac{3}{14}\)

     \(x\)         = \(\dfrac{9}{7}\)

a) \(\left(19x+2\cdot5^2\right)\div14=\left(13-8\right)^2-4^2\)

\(\left(19x+2\cdot25\right)\div14=5^2-16\)

\(\left(19x+50\right)\div14=25-16=9\)

\(19x+50=9\cdot14=126\)

\(19x=126-50=76\)

\(x=76\div19=4\)

b) \(2\cdot3^x=10\cdot3^{12}+8\cdot\left(3^3\right)^4\)

\(2\cdot3^x=\left(10+8\right)\cdot3^{12}\)

\(2\cdot3^x=18\cdot3^{12}\)

\(\Rightarrow2\cdot3^x=2\cdot3^2\cdot3^{12}\Rightarrow2\cdot3^x=2\cdot3^{15}\Rightarrow x=15\)

a, \left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2(19.x+2.52)÷14=(13−8)2−42
\left(19.x+2.25\right)\div14=5^2-4^2(19.x+2.25)÷14=52−42
\left(19.x+2.25\right)\div14=25-16(19.x+2.25)÷14=25−16
\left(19.x+50\right)\div14=9(19.x+50)÷14=9
\left(19.x+50\right)=9.14(19.x+50)=9.14
19.x+50=12619.x+50=126
19.x=126-5019.x=126−50
19.x=7619.x=76
\Rightarrow x=76\div19⇒x=76÷19
\Rightarrow x=4⇒x=4
Vậy x = 4
b, 2.3^x=10.3^{12}+8.27^42.3x=10.312+8.274
2.3^x=10.3^{12}+8.\left(3^3\right)^42.3x=10.312+8.(33)4
2.3^x=10.3^{12}+8.3^{12}2.3x=10.312+8.312
2.3^x=\left(10+8\right).3^{12}2.3x=(10+8).312
2.3^x=18.3^{12}2.3x=18.312
2.3^x=2.3^3.3^{12}2.3x=2.33.312
2.3^x=2.3^{15}2.3x=2.315
\Rightarrow x=15⇒x=15
Vậy x = 15

\(a.\dfrac{1}{2}:3+x=\dfrac{14}{5}\)

\(\dfrac{1}{6}+x=\dfrac{14}{5}\)

\(=>x=\dfrac{79}{30}\)

\(b.\dfrac{8}{5}:x:\dfrac{7}{4}=\dfrac{11}{6}\)

\(\left(\dfrac{8}{5}\cdot\dfrac{4}{7}\right):x=\dfrac{11}{6}\)

\(\dfrac{32}{35}:x=\dfrac{11}{6}\)

\(x=\dfrac{192}{385}\)

\(c.\dfrac{24}{10}+x:\dfrac{3}{4}=\dfrac{11}{3}\)

\(x:\dfrac{3}{4}=\dfrac{11}{3}-\dfrac{24}{10}\)

\(x:\dfrac{3}{4}=\dfrac{38}{30}\)

\(=>x=\dfrac{19}{20}\)

\(a,\dfrac{1}{2}:3+x=\dfrac{14}{5}\\ \Leftrightarrow x+\dfrac{1}{6}=\dfrac{14}{5}\\ \Leftrightarrow x=\dfrac{79}{30}\\ b,\dfrac{8}{5}:x:\dfrac{7}{4}=\dfrac{11}{6}\\ \Leftrightarrow x=\dfrac{192}{385}\\ c,\dfrac{24}{10}+x:\dfrac{3}{4}=\dfrac{11}{3}\\ \Leftrightarrow\dfrac{4}{3}x=\dfrac{19}{15}\\ \Leftrightarrow x=\dfrac{19}{20}\)

a   1/6+x=14/5

     x=14/5-1/6

     x= 79/30

b    8/5:x=11/6*7/4

     8/5:x=77/24

     x=77/24:8/5

     x=385/192

c  x:3/4=11/3-24/10

  x:3/4=19/5

  x=19/5*3/4

  x=57/20

\(x\in\left(\infty;-\infty\right)\)

\(\frac{19x+50}{14}=\frac{9}{1}\Rightarrow\left(19x+50\right)1=14.9\)

\(\frac{\left(19x+50\right)1}{19x}=\frac{14.9}{19x}\)

\(\frac{19x+50}{19x}=\frac{14.19}{19x}\)

\(\Rightarrow x=4\)

a, \(\left(19.x+2.5^2\right)\div14=\left(13-8\right)^2-4^2\)

\(\left(19.x+2.25\right)\div14=5^2-4^2\)

\(\left(19.x+2.25\right)\div14=25-16\)

\(\left(19.x+50\right)\div14=9\)

\(\left(19.x+50\right)=9.14\)

\(19.x+50=126\)

\(19.x=126-50\)

\(19.x=76\)

\(\Rightarrow x=76\div19\)

\(\Rightarrow x=4\)

Vậy x = 4

b, \(2.3^x=10.3^{12}+8.27^4\)

\(2.3^x=10.3^{12}+8.\left(3^3\right)^4\)

\(2.3^x=10.3^{12}+8.3^{12}\)

\(2.3^x=\left(10+8\right).3^{12}\)

\(2.3^x=18.3^{12}\)

\(2.3^x=2.3^3.3^{12}\)

\(2.3^x=2.3^{15}\)

\(\Rightarrow x=15\)

Vậy x = 15

​ngu...~_~ bài ny mà cx nỏ bt làm : a ) x=4         b ) x=14

a) \(\left(19\cdot x+2\cdot5^2\right):14=\left(13-8\right)^2-4^2\)

\(\left(19\cdot x+50\right):14=9\)

\(19\cdot x+50=9\cdot14\)

\(19\cdot x+50=126\)

\(19\cdot x=126-50\)

\(19\cdot x=76\)

\(x=76:19\)

\(x=4\)

Vậy \(x=4\)

2:

1: =>36x+14x=69+81=150

=>50x=150

=>x=3

2: 3^x=81

=>3^x=3^4

=>x=4

3: 3(2x+1)^2=75

=>(2x+1)^2=25

=>2x+1=5 hoặc 2x+1=-5

=>x=-3 hoặc x=2

1:

1: \(\dfrac{13\cdot17^4+4\cdot17^4}{17^3}-\dfrac{14\cdot3^3-14\cdot3^2}{9}\)

\(=\dfrac{17^4\cdot\left(13+4\right)}{17^3}-\dfrac{14\cdot3^2\left(3-1\right)}{9}\)

\(=17\cdot17-14\cdot2\)

=289-28

=261

2:

\(2^3\cdot5^2-\left[131-\left(23-2^3\right)^2\right]\)

\(=8\cdot25-131+\left(-1\right)^2\)

=69+1

=70

a)5/14:x+3/10=1/2

=>5/14:x=1/2-3/10

=>5/14:x=1/5

=>x=5/14:1/5

=>x=25/14

vậy x=15/14

2/ 1 - 3 + 5 - 7 + ... + (x-2) - x = -600

=> ( - 2 ) + ( - 2 ) + .... + ( - 2 ) = - 600 ( số số hạng các số - 2 là A ) 

=> ( - 2 ) . A =  - 600 => A = 300 

Mặt Khác số số hạng ở dãy trên = ( x - 1 ) : 2 + 1 ( 1 ) 

Số số cặp = Số số hạng : 2 = 300 => Số số hạng = 600 

Thay vào ( 1 ) Ta có :

( x - 1 ) : 2 + 1 = 600 => ( x - 1 ) : 2 = 599 => x = 599 . 2 + 1 = 1198+ 1 = 1199 

Các câu 1,3,4 làm tương tự

2+4+6+..........+x=600