\(\dfrac{1}{3}\) . ( x - 2 ) - \(\dfrac{3}{4}\) x = 1
\(\dfrac{x+3}{x-4}\) = \(\dfrac{5}{12}\) ( x ≠ 4 )
\(\dfrac{x-2}{x+3}\) = \(\dfrac{x-5}{x-7}\)
( 3x + 2 )\(^4\) = 81
\(2^{x-3}\) = \(1024^4\)
\(3^x\) + 5 . \(3^{x-1}\) = 648
( x - 2,5 )\(^2\) = \(\dfrac{4}{9}\)
\(\left(2x+\dfrac{1}{3}\right)^3\) = \(-\dfrac{8}{27}\)
\(\dfrac{2}{3}\) . \(3^{x+1}\) - 7 . \(3^x\) = -405