Question

\(\dfrac{1}{3}\) . ( x - 2 ) - \(\dfrac{3}{4}\) x = 1

\(\dfrac{x+3}{x-4}\) = \(\dfrac{5}{12}\) ( x ≠ 4 )

\(\dfrac{x-2}{x+3}\) = \(\dfrac{x-5}{x-7}\)

( 3x + 2 )\(^4\) = 81

\(2^{x-3}\) = \(1024^4\)

\(3^x\) + 5 . \(3^{x-1}\) = 648

( x - 2,5 )\(^2\) = \(\dfrac{4}{9}\)

\(\left(2x+\dfrac{1}{3}\right)^3\) = \(-\dfrac{8}{27}\)

\(\dfrac{2}{3}\) . \(3^{x+1}\) - 7 . \(3^x\) = -405

Answer 1

đề bài yêu cầu gì vậy em

Answer 2

a: =>1/3x-1/3-3/4x=1

=>-5/12x=4/3

=>x=-4/3:5/12=-4/3*12/5=-48/15=-16/5

b: =>12x+36=5x-20

=>7x=-56

=>x=-8

c: =>x^2-9x+14=x^2-2x-15

=>-7x=-29

=>x=29/7

d: =>3x+2=3 hoặc 3x+2=-3

=>3x=1 hoặc 3x=-5

=>x=1/3 hoặc x=-5/3

e: \(\Leftrightarrow2^{x-3}=2^{40}\)

=>x-3=40

=>x=43