1: \(\Leftrightarrow\left(x+1\right)^2=4\)
=>x+1=2 hoặc x+1=-2
=>x=1 hoặc x=-3
2: \(\Leftrightarrow7x-21=5x+25\)
=>2x=46
=>x=23
3: \(\Leftrightarrow x^2+4x+3=x^2+0.5x+4x+2\)
=>4,5x+2=4x+3
=>x=1
1: \(\Leftrightarrow\left(x+1\right)^2=4\)
=>x+1=2 hoặc x+1=-2
=>x=1 hoặc x=-3
2: \(\Leftrightarrow7x-21=5x+25\)
=>2x=46
=>x=23
3: \(\Leftrightarrow x^2+4x+3=x^2+0.5x+4x+2\)
=>4,5x+2=4x+3
=>x=1
Thu gọn các đơn thức đồng dạng trong đa thức sau:
a) \(A=x^5-\dfrac{1}{2}x+7x^3-2x+\dfrac{1}{5}x^3+3x^4-x^5+\dfrac{2}{5}x^4+15\)
b) \(B=3x^2-10+\dfrac{2}{5}x^3+7x-x^2+8+7x^2\)
c) \(C=\dfrac{1}{7}x-2x^4+5x+6\)
a)\(\dfrac{\left(x+\dfrac{3}{4}\right)\cdot\dfrac{7}{2}-\dfrac{1}{6}}{-\left(\dfrac{4}{5}+\dfrac{1}{3}\right)\cdot\dfrac{1}{2}+1}=2\dfrac{33}{52}\)
b)\(\dfrac{\left(5-\dfrac{2}{7}\right)\cdot\dfrac{7}{9}:\dfrac{3}{5}}{\left(3x-\dfrac{5}{6}\right):\dfrac{1}{7}}=5\dfrac{5}{21}\)
Bài 7: Tìm X
\(\dfrac{2^{18}}{32^3}.\dfrac{27^4}{54^3}\) \(\dfrac{x+1}{9}=\dfrac{4}{x+1}\) Tìm x, y biết:
\(\dfrac{40^4}{120^4}:\dfrac{130^3}{390^3}\) \(19.5^{2x+7}=475\) 5x=4y và y-x=7
\(2^x.8\) \(\dfrac{2x}{5}=\dfrac{10}{x}\)
\((\dfrac{1}{2})^x=\dfrac{1}{32}\) \(33^x:11^x=243\)
a) \(\dfrac{\left(x+\dfrac{3}{4}\right)\cdot\dfrac{7}{2}-\dfrac{1}{6}}{-\left(\dfrac{4}{5}+\dfrac{1}{3}\right)\cdot\dfrac{1}{2}+1}=2\dfrac{33}{52}\)
b)\(\dfrac{\left(5-\dfrac{2}{7}\right)\cdot\dfrac{7}{9}\cdot\dfrac{3}{5}}{\left(3x-\dfrac{5}{6}\right):\dfrac{1}{7}}=5\dfrac{5}{21}\)
1)Tìm x, biết:
a)\(\dfrac{x-1}{3}=\dfrac{x+1}{5}\)
b)\(\dfrac{2x+1}{3x-2}=\dfrac{5x+1}{9x+1}\)
2)Tìm x,y,z biết:
a)\(\dfrac{x}{2}=\dfrac{y}{3}=\dfrac{z+1}{4}\) và 2x+3y-z=11
b)\(\dfrac{2x+1}{5}=\dfrac{3y-2}{7}=\dfrac{2x+3y-1}{6x}\)
Giúp mình với mình đang cần gấp!!!THANK NHÌU
Tìm x
a) \(\left(\dfrac{3}{5}x-\dfrac{2}{3}x-x\right)\cdot\dfrac{1}{7}=-\dfrac{5}{21}8\)
b) \(\left(5x-1\right)\cdot\left(2x+\dfrac{1}{3}\right)=0\)
c) \(\dfrac{5\left|x+1\right|}{2}=\dfrac{90}{\left|x+1\right|}\)
1,\(\dfrac{3}{16}\)- ( x - \(\dfrac{5}{4}\) ) - ( \(\dfrac{3}{4}\) + \(\dfrac{-7}{8}\) - 1 ) = \(2\dfrac{1}{2}\)
2,\(\dfrac{1}{2}\) . ( \(\dfrac{1}{6}\) - \(\dfrac{9}{10}\) ) = \(\dfrac{1}{5}\) - x + ( \(\dfrac{1}{15}\) - \(\dfrac{-1}{5}\) )
Giúp mik nhanh với ạ
1)Tính giá trị biểu thức:
\(\dfrac{\left(13\dfrac{1}{4}-2\dfrac{5}{27}-10\dfrac{5}{6}\right).230\dfrac{1}{25}+46\dfrac{3}{4}}{\left(1\dfrac{3}{7}+\dfrac{10}{3}\right):\left(12\dfrac{1}{3}-14\dfrac{2}{7}\right)}\)
2)Tìm x biết:
a) \(42+\dfrac{3}{7}.\left|3x-1\right|=12\)
b) \(\left|2x-1\right|=\left|x+2\right|\)
c) \(2.3^x.3^2=18\) với \(x\in N\)
Tìm các cặp số ( x : y ) nguyên sao cho :
a, x - y + 2 xy = 3
b,\(3x^2-3xy-5x-y=-20\)
c,\(\dfrac{x}{8}-\dfrac{1}{y}=\dfrac{1}{4}\)
d,\(2x+\dfrac{1}{7}=\dfrac{1}{y}\)