a) \(5\times\left(3+7\times x\right)=400\)

\(3+7\times x=80\)

\(7\times x=77\)

\(x=11\)

b) \(x\times37+x\times63=1200\)

\(x\times\left(37+63\right)=1200\)

\(x\times100=1200\)

\(x=12\)

c) \(x\times6+12:3=40\)

\(x\times6+4=40\)

\(x\times6=36\)

\(x=6\)

d) \(4+6\times\left(x+1\right)=70\)

\(6\times\left(x+1\right)=66\)

\(x+1=11\)

\(x=10\)

e) \(163:x+34:x=10\)

\(\left(163+34\right):x=10\)

\(197:x=10\)

\(x=19,7\)

(x+1) * (x² +x+1) * (x-1) * (x²-x+1)   = 7

[(x+1) * (x² +x+1) ]*[(x-1) * (x²-x+1)]= 7  [Áp dụng hằng đẳng thức a³+b³=(a+b)*(a²+ab+b²)]

(x³+1³) * (x³-1³)                               = 7

x³ * x³ - x³ * 1³ + x³ * 1³ - 1³ *1³     =7

(x³)² - 1                                            = 7

(x³)²                                                  =7+1

(x³)²                                                  =8

suy ra x = 3 căn 2

a) -12.(x-5)+7.(3.x)=5

<=> -12x+60+21+7x=5

<=>-5x+81=5

<=>-5x=5-81=-76

<=>x=-76/-5=76/5=15,2

b) 30.(x+2)-6.(x-5)-24.x=100

<=> 30x+60-6x+30-24x=100

<=> 0x=100-60-30=10

=> không có giá trị nào của x để 0x=10

c) \(|5.x-2|< 13\)

Khi 5x-2 < 13

<=> 5x<15 <=> x<3

Khi 5x-2 <-13

<=> 5x<-11 <=> x<-11/5 <=> x<-2,2

\(x\times\frac{3}{5}+x\times\frac{2}{7}=\frac{31}{70}\)

\(x\times\left(\frac{3}{5}+\frac{2}{7}\right)=\frac{31}{70}\)

\(x\times\frac{31}{35}=\frac{31}{70}\)

\(x=\frac{31}{70}:\frac{31}{35}\)

\(x=\frac{1}{2}\)

1/2 BAN NHA 

TA LẤY X*(3/5+2/7)=31/70

X*31/35=31/70

X=31/70:31/35

X=1/2

1/2

ban nhe

tk nhe

xin do

a) Thiếu đề (hoặc sai)

b) x đâu?

c)\(3x-1=x+2\)

\(\Rightarrow3x-x=2+1\)

\(\Rightarrow2x=3\)

\(\Rightarrow x=\frac{3}{2}\)

c) \(\frac{x+2}{5}=\frac{2-3x}{3}\)

\(\Rightarrow3.\left(x+2\right)=5.\left(2-3x\right)\)

\(\Rightarrow3x+6=10-15x\)

\(\Rightarrow3x+15x=10-6\)

\(\Rightarrow18x=4\)

\(\Rightarrow x=\frac{4}{18}=\frac{2}{9}\)

câu 1 là \(x\times\left(4.6+\frac{3}{5}\right)=7.2-8.15\)

câu 2 là \(42+\frac{3}{7}.\left[3\times x-1=12\right]\)

a)\(x.\left(4,6+\frac{3}{5}\right)=7,2-8,15\)

\(\Rightarrow\left(\frac{23}{5}+\frac{3}{5}\right).x=-0,95\)

\(\Rightarrow\frac{26}{5}.x=\frac{-19}{20}\)

\(\Rightarrow x=\frac{-19}{20}:\frac{26}{5}\)

\(\Rightarrow x=\frac{-19}{104}\)

Mà \(4.6\)là\(4,6\)hay \(4\times6?\)nếu sai tớ làm lại

b) Ngoặc sai rồi

\(42+\frac{3}{7}.\left(3x-1\right)=12\)

\(\Rightarrow\frac{3}{7}.\left(3x-1\right)=12-42\)

\(\Rightarrow\frac{3}{7}.\left(3x-1\right)=-30\)

\(\Rightarrow3x-1=-30:\frac{3}{7}\)

\(\Rightarrow3x-1=\frac{-10}{7}\)

\(\Rightarrow3x=\frac{-10}{7}+1\)

\(\Rightarrow3x=\frac{-10+7}{7}=\frac{-3}{7}\)

\(\Rightarrow x=\frac{-3}{7}:3=\frac{-1}{7}\)

Lưu ý nhé viết dấu nhân thì viết \("."\)một thể, \("\times"\)một thể. Còn dâu phảy của số thập phân thì viết ",'' nhé

a, -5/7+ 1+ 30/-7< x < -1/6+ 1/3 +5/6
<=> -4< x <1
<=> x = -3; -2; -1; 0

a, \(\dfrac{-5}{7}+1+\dfrac{30}{-7}\le x\le\dfrac{-1}{6}+\dfrac{1}{3}+\dfrac{5}{6}\)
<=> -4 \(\le x\le1\)
Do x \(\in Z\Rightarrow x=-4;-3;-2;-1;0;1\)
b, \(\dfrac{1}{2}-\left(\dfrac{1}{3}+\dfrac{1}{4}\right)< x< \dfrac{1}{48}-\left(\dfrac{1}{16}-\dfrac{1}{6}\right)\)
<=> -\(\dfrac{1}{12}< x< \dfrac{1}{8}\)
Do x \(\in Z\Rightarrow x=0;1\)
@Mai Tran

c, Do (x - \(\dfrac{1}{2}\))(x + \(\dfrac{3}{4}\)) < 0
=> x - \(\dfrac{1}{2};x+\dfrac{3}{4}\) khác dấu
Có x - \(\dfrac{1}{2}< x+\dfrac{3}{4}\Rightarrow x-\dfrac{1}{2}< 0;x+\dfrac{3}{4}>0\)
=> \(\left[{}\begin{matrix}x-\dfrac{1}{2}< 0\\x+\dfrac{3}{4}>0\end{matrix}\right.\Leftrightarrow\left[{}\begin{matrix}x< \dfrac{1}{2}\\x>-\dfrac{3}{4}\end{matrix}\right.\)<=> -\(\dfrac{3}{4}< x< \dfrac{1}{2}\)
Do x \(\in Z\Rightarrow x=0\)
@Mai Tran

\(a,\)\(-\frac{3}{5}\cdot x=\frac{1}{4}+0,75\)

\(-\frac{3}{5}\cdot x=\frac{1}{4}+\frac{3}{4}=\frac{4}{4}=1\)

\(x=1\div\left(-\frac{3}{5}\right)\)

\(x=-\frac{5}{3}\)

\(b,\)\(\left(\frac{1}{7}-\frac{1}{3}\right)\cdot x=\frac{28}{5}\times\left(\frac{1}{4}-\frac{1}{7}\right)\)

\(\left(\frac{3}{21}-\frac{7}{21}\right)\cdot x=\frac{28}{5}\cdot\left(\frac{7}{28}-\frac{4}{28}\right)\)

\(-\frac{4}{21}\cdot x=\frac{28}{5}\cdot\frac{3}{28}\)

\(-\frac{4}{21}\cdot x=\frac{3}{5}\)

\(x=\frac{3}{5}\div\left(-\frac{4}{21}\right)\)

\(x=-\frac{63}{20}\)

\(c,\)\(\frac{5}{7}\cdot x=\frac{9}{8}-0,125\)

\(\frac{5}{7}\cdot x=\frac{9}{8}-\frac{1}{8}\)

\(\frac{5}{7}\cdot x=1\)

\(x=1\div\frac{5}{7}\)

\(x=\frac{7}{5}\)

\(d,\)\(\left(\frac{2}{11}+\frac{1}{3}\right)\cdot x=\left(\frac{1}{7}-\frac{1}{8}\right)\cdot36\)

\(\left(\frac{6}{33}+\frac{11}{33}\right)\cdot x=\left(\frac{8}{56}-\frac{7}{56}\right)\cdot36\)

\(\frac{17}{33}\cdot x=\frac{1}{56}\cdot36\)

\(\frac{17}{33}\cdot x=\frac{9}{14}\)

\(x=\frac{9}{14}\div\frac{17}{33}\)

\(x=\frac{9}{14}\cdot\frac{33}{17}=\frac{297}{238}\)

a)\(\frac{3}{5}\times x=1\)                                        

\(x=1\div\frac{3}{5}\)

\(x=\frac{5}{3}\)

Mình chỉ làm duoc câu a thôi