5 . 4² - 18 : 3 + 3² . 3

= 5 . 16 - 18 : 3 + 9 . 3

= 80 - 6 + 27

= 74 + 27

= 101

\(5\text{.}4^2-18:3+3^2.3\)

= 5. 16 - 6 + 27

= 80+ 21

= 101

\(B=\frac{2^{10}\cdot55-2^{10}}{2^8\cdot27}=\frac{2^{10}\left(55-1\right)}{2^8\cdot3^3}=\frac{2^{10}\cdot2\cdot3^3}{2^8\cdot3^3}=\frac{2^{11}\cdot3^3}{2^8\cdot3^3}=2^3=8.\)

\(C=\frac{\left(3\cdot4\cdot24\right)^2}{5\cdot2^5\cdot4^2-16^2}=\frac{288^2}{5\cdot16\cdot2^3.16-16^2}=\frac{2^5\cdot3^2}{16^2\left(5\cdot2^3-1\right)}=\frac{16\cdot2\cdot9}{16\cdot16\left(5\cdot8-1\right)}\)

\(=\frac{16\cdot2\cdot9}{16\cdot16\cdot39}=\frac{16\cdot2\cdot9}{16\cdot2^4\cdot13\cdot3}=\frac{1\cdot3}{2^3\cdot13\cdot1}=\frac{3}{8\cdot13\cdot1}=\frac{3}{104}\)

\(D=\frac{11\cdot3^{22}\cdot3^7-9^{14}}{\left(2\cdot3^{14}\right)^2}=\frac{11\cdot3^{30}-3^{28}}{2^2\cdot3^{28}}=\frac{3^{28}\left(11\cdot3^2-1\right)}{4\cdot3^{38}}=\frac{3^{28}\left(11\cdot9-1\right)}{4\cdot3^{28}}=\frac{99-1}{4}=\frac{98}{4}=24,5\)

cho cách là phân số đấy

ban oi phan B la phep cong

\(a\left(x\right)=5x^4-3x^2-2x^3+4-5x^4+5x^2-x+2x^3+1\)

\(=2x^2+4-x\)

Bậc : 2 

\(a\left(x\right)=5x^4-3x^2-2x^3+4-5x^4+5x^2-x+2x^3+1\)

\(a\left(x\right)=\left(5x^4-5x^4\right)+\left(2x^3-2x^3\right)+\left(5x^2-3x^2\right)-x+\left(4+1\right)\)

\(a\left(x\right)=2x^2-x+5\). Bậc của \(a\left(x\right)\) là 2

em nhầm, em xin lỗi : \(=2x^2+5-x\)

`@` `\text {Ans}`

`\downarrow`

`a)`

Thu gọn:

`P(x)=`\(5x^4 + 3x^2 - 3x^5 + 2x - x^2 - 4 +2x^5\)

`= (-3x^5 + 2x^5) + 5x^4 + (3x^2 - x^2) + 2x - 4`

`= -x^5 + 5x^4 + 2x^2 + 2x - 4`

`Q(x) =`\(x^5 - 4x^4 + 7x - 2 + x^2 - x^3 + 3x^4 - 2x^2\)

`= x^5 + (-4x^4 + 3x^4) - x^3 + (x^2 - 2x^2) + 7x - 2`

`= x^5 - x^4 - x^3 - x^2 + 7x - 2`

`@` Tổng:

`P(x)+Q(x)=`\((-x^5 + 5x^4 + 2x^2 + 2x - 4) + (x^5 - x^4 - x^3 - x^2 + 7x - 2)\)

`= -x^5 + 5x^4 + 2x^2 + 2x - 4 + x^5 - x^4 - x^3 - x^2 + 7x - 2`

`= (-x^5 + x^5) - x^3 + (5x^4 - x^4) + (2x^2 - x^2) + (2x + 7x) + (-4-2)`

`= 4x^4 - x^3 + x^2 + 9x - 6`

`@` Hiệu:

`P(x) - Q(x) =`\((-x^5 + 5x^4 + 2x^2 + 2x - 4) - (x^5 - x^4 - x^3 - x^2 + 7x - 2)\)

`= -x^5 + 5x^4 + 2x^2 + 2x - 4 - x^5 + x^4 + x^3 + x^2 - 7x + 2`

`= (-x^5 - x^5) + (5x^4 + x^4) + x^3 + (2x^2 + x^2) + (2x - 7x) + (-4+2)`

`= -2x^5 + 6x^4 + x^3 + 3x^2 - 5x - 2`

`b)`

`@` Thu gọn:

\(H (x) = ( 3x^5 - 2x^3 + 8x + 9) - ( 3x^5 - x^4 + 1 - x^2 + 7x)\)

`= 3x^5 - 2x^3 + 8x + 9 - 3x^5 + x^4 - 1 + x^2 - 7x`

`= (3x^5 - 3x^5) + x^4 - 2x^3 - x^2 + (8x + 7x) + (9+1)`

`= x^4 - 2x^3 - x^2 + 15x + 10`

\(R( x) = x^4 + 7x^3 - 4 - 4x ( x^2 + 1) + 6x\)

`= x^4 + 7x^3 - 4 - 4x^3 - 4x + 6x`

`= x^4 + (7x^3 - 4x^3) + (-4x + 6x) - 4`

`= x^4 + 3x^3 + 2x - 4`

`@` Tổng:

`H(x)+R(x)=` \((x^4 - 2x^3 - x^2 + 15x + 10)+(x^4 + 3x^3 + 2x - 4)\)

`= x^4 - 2x^3 - x^2 + 15x + 10+x^4 + 3x^3 + 2x - 4`

`= (x^4 + x^4) + (-2x^3 + 3x^3) - x^2 + (15x + 2x) + (10-4)`

`= 2x^4 + x^3 - x^2 + 17x + 6`

`@` Hiệu: 

`H(x) - R(x) =`\((x^4 - 2x^3 - x^2 + 15x + 10)-(x^4 + 3x^3 + 2x - 4)\)

`=x^4 - 2x^3 - x^2 + 15x + 10-x^4 - 3x^3 - 2x + 4`

`= (x^4 - x^4) + (-2x^3 - 3x^3) - x^2 + (15x - 2x) + (10+4)`

`= -5x^3 - x^2 + 13x + 14`

`@` `\text {# Kaizuu lv u.}`

\(a,\dfrac{9}{5}+\dfrac{2}{5}\times\dfrac{4}{6}=\dfrac{9}{5}+\dfrac{4}{15}=\dfrac{27}{15}+\dfrac{4}{15}=\dfrac{31}{15}\\ b,\dfrac{3}{8}\times2-\dfrac{6}{7}\times\dfrac{1}{3}=\dfrac{3}{4}-\dfrac{2}{7}=\dfrac{21}{28}-\dfrac{8}{28}=\dfrac{13}{28}\)

A)=9/5 + 4/15

=27/15+4/15

=31/15

B)=3/4-2/14

=36/28-4/28

=32/28=?

a) (-x⁶ + 5x⁴ – 2x³) : (0,5x²)

= (-x⁶ : 0,5x²) + (5x⁴ : 0,5x²) + (-2x³ : 0,5x²)

= -2x⁴ + 10x² – 4x

b)

Lời giải:

\(\frac{4}{9}\times \frac{3}{7}\times \frac{7}{4}=\frac{1}{3}\)

\(\frac{6}{5}\times \frac{4}{5}\times \frac{25}{16}=\frac{3}{2}\)

\(\frac{7}{8}\times \frac{16}{9}\times \frac{3}{14}=\frac{1}{3}\)

Rút gọn

M(x)= 2x2 - 7 + 2x3 - 4x4 + 5x4 + 2

= x4 + 2x3 + 2x2 - 5.

Chọn D

8/9:3/2<2/3x10/9

2/5x3>1/5x4

8/9:3/2 < 2/3x10/9

2/5x3 > 1/5x4