Tim x biet,\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}\chi}{0,0(3)+13}=\frac{50}{85}\)
\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}=\frac{50}{85}\)
0,(3) = 1/3
0,0(3) = 1/30
0,(384615) = 5/13
Tìm x biết:\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}.x}{0,0\left(3\right)+13=\frac{50}{85}}\)
Tìm x, biết
\(\frac{0.\left(3\right)+0.\left(384615\right)+\frac{3}{13}.x}{0.0\left(3\right)+13}=\frac{50}{85}\)
Tìm x, biết:
\(\dfrac{0,3+0,\left(384615\right)+\dfrac{3}{13}x}{0,0\left(3\right)+13}=\dfrac{50}{85}\)
\(\Leftrightarrow\dfrac{\dfrac{3}{10}+\dfrac{5}{13}+\dfrac{3}{13}x}{\dfrac{1}{30}+13}=\dfrac{50}{85}\)
\(\Leftrightarrow x\cdot\dfrac{3}{13}+\dfrac{89}{130}=\dfrac{23}{3}\)
=>3/13x=2723/390
hay x=2723/90
\(\dfrac{0,\left(3\right)+0,\left(384615\right)+\dfrac{3}{13}x}{0.0\left(3\right)+13}\dfrac{50}{85}\) tìm x
\(\dfrac{0.\left(3\right)+0.\left(384615\right)+\dfrac{3}{13}x}{0.0\left(3\right)+13}=\dfrac{50}{85}\)
\(\Leftrightarrow\dfrac{\dfrac{28}{39}+\dfrac{3}{13}x}{\dfrac{391}{30}}=\dfrac{10}{17}\)
\(\Leftrightarrow x\cdot\dfrac{3}{13}+\dfrac{28}{39}=\dfrac{23}{3}\)
\(\Leftrightarrow x\cdot\dfrac{3}{13}=\dfrac{271}{39}\)
\(\Leftrightarrow x=\dfrac{271}{9}\)
\(\frac{0.\left(3\right)+0.\left(384615\right)+\frac{3}{13}x}{0.0\left(3\right)+13}\)
Giups mik nha
Đề bài là gì vậy bạn ??? Tính hay tìm x ?
\(\frac{0,\left(3\right)+0,\left(384615\right)+\frac{3}{13}x}{0,0\left(3\right)+13}\)
\(=\frac{\frac{1}{3}+\frac{5}{13}+\frac{3}{13}x}{\frac{1}{30}+13}=\frac{\frac{1}{3}+\frac{5+3x}{13}}{\frac{391}{30}}=\frac{\frac{13+3\left(5+3x\right)}{39}}{\frac{391}{30}}\)
\(=\frac{\frac{13+15+9x}{39}}{\frac{391}{90}}=\frac{\frac{28+9x}{39}}{\frac{391}{90}}=\frac{28+9x}{39}\cdot\frac{90}{391}\)
P/S : Sai đề trầm trọng
P/S : Tìm x vậy kết quả nó bao nhiêu mới tìm được chớ ?
Đề còn thiếu không vậy?
0.(3)+0,(384615)+3/13.x
0,0(3)+13=50/85
thuc hien phep tinh
\(\left[6-3.\left(-\frac{1}{3}^2\right)+\sqrt{0,25}\right]:\sqrt{0,\left(9\right)}\)
\(\left(\frac{1}{2}\right)^2.\sqrt{16}-3^2.\sqrt{0,01}+\left(2^2\right)^2-\left(0,0\left(6\right)\right)+\frac{13}{30}\)
\(\frac{19}{13}-\left(\frac{5}{42}-x\right)=-\left(\frac{15}{28}-\frac{19}{13}\right)\)
b)\(\left[\frac{1}{3}x^3\left(3x-1\right)^m-\frac{1}{3}x^{m+3}\right]:\frac{1}{3}x^3=0\left(m\in N\right)\)
Tìm x nha