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a, x:0,5+x:0,125 đáp án đâu baaa
b,(3,5x10)x(53x11-5300x0,1-53)
(3,5x10)x(53x11-53x10-53x1)
(3,5x10)x[53x(11-10-1)]
(3,5x10)x(53x0)
35x0
=0
tick hộ anh vs

phần a vs anh ey

a) Tìm x:

Xem lại đề.

b) Tính thuận tiện:

(31,5 x 10) x (53 x 11 - 5300 x 0,1 - 53)

= 315 x (53 x 11 - 53 x 10 - 53 x 1)

= 315 x [53 x (11 - 10 - 1)]

= 315 x [53 x 0]

= 315 x 0

=0

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\(5300x=340\left(x+\frac{1}{15}\right)\)

\(\Leftrightarrow5300x=340x+\frac{68}{3}\)

\(\Leftrightarrow5300x-340x=\frac{68}{3}\)

\(\Leftrightarrow4960x=\frac{68}{3}\)

\(\Leftrightarrow x=4960:\frac{68}{3}\)

\(\Leftrightarrow x=....\)(tự tính)

5300x=340x +\(\frac{68}{3}\)

4960x=\(\frac{68}{3}\)

x=\(\frac{34}{7440}\)

=>2/13x-95/26x=-1/3-1/4

=>-91/26x=-7/12

=>-7/2x=-7/12

hay x=1/6

`2/13 x+1/4 = 95/26 x-1/3`

`<=>95/26x-2/13x=1/4+1/3`

`<=>91/26x=7/12`

`<=>7/2x=7/2`

`x=7/12:7/2`

`x=7/12xx2/7`

`x=1/6`

Vậy pt có nghiệm duy nhất `x=1/6.`

`2/13x+1/4=95/26x-1/3`

`<=>2/13x-95/26x=-1/3-1/4`

`<=>(2/13-95/26)x=-7/12`

`<=>-7/2x=-7/12`

`<=>x=1/6`

\(\frac{x-11}{95}+\frac{x-13}{93}=\frac{x-15}{91}+\frac{x-17}{89}\) => \(\frac{x-11}{95}-1+\frac{x-13}{93}-1=\frac{x-15}{91}-1+\frac{x-17}{89}-1\)

=>\(\frac{x-106}{95}+\frac{x-106}{93}=\frac{x-106}{91}+\frac{x-106}{89}\)

=>\(\left(\frac{1}{95}+\frac{1}{93}\right)\left(x-106\right)-\left(\frac{1}{91}+\frac{1}{89}\right)\left(x-106\right)=0\)

<=>\(\left[\left(\frac{1}{95}+\frac{1}{93}\right)-\left(\frac{1}{91}+\frac{1}{89}\right)\right]\left(x-106\right)=0\).Vì\(\frac{1}{95}< \frac{1}{91};\frac{1}{93}< \frac{1}{89}\) nên\(\frac{1}{95}+\frac{1}{93}< \frac{1}{91}+\frac{1}{89}\)

=>\(\left(\frac{1}{95}+\frac{1}{93}\right)-\left(\frac{1}{91}+\frac{1}{89}\right)< 0\) hay khác 0.Vậy x - 106 = 0, tìm được x = 106

1) PT \(\Leftrightarrow\left(\dfrac{x+1}{35}+1\right)+\left(\dfrac{x+3}{33}+1\right)=\left(\dfrac{x+5}{31}+1\right)+\left(\dfrac{x+7}{29}+1\right)\)

\(\Leftrightarrow\dfrac{x+36}{35}+\dfrac{x+36}{33}=\dfrac{x+36}{31}+\dfrac{x+36}{29}\)

\(\Leftrightarrow\left(x+36\right)\left(\dfrac{1}{29}+\dfrac{1}{31}-\dfrac{1}{33}-\dfrac{1}{35}\right)=0\)

\(\Leftrightarrow x+36=0\) (Do \(\dfrac{1}{29}+\dfrac{1}{31}-\dfrac{1}{33}-\dfrac{1}{35}>0\))

\(\Leftrightarrow x=-36\).

Vậy nghiệm của pt là x = -36.

2) x(x+1)(x+2)(x+3)= 24

⇔ x.(x+3)  .   (x+2).(x+1)  = 24

⇔(\(x^2\) + 3x) . (\(x^2\) + 3x + 2) = 24

Đặt \(x^2\)+ 3x = b

⇒ b . (b+2)= 24

Hay: \(b^2\) +2b = 24

⇔\(b^2\) + 2b + 1 = 25

⇔\(\left(b+1\right)^2\)= 25

+ Xét b+1 = 5 ⇒ b=4 ⇒  \(x^2\)+ 3x = 4 ⇒ \(x^2\)+4x-x-4=0 ⇒x(x+4)-(x+4)=0

⇒(x-1)(x+4)=0⇒x=1 và x=-4

+ Xét b+1 = -5 ⇒ b=-6 ⇒ \(x^2\)+3x=-6 ⇒\(x^2\) + 3x + 6=0

⇒\(x^2\) + 2.x.\(\dfrac{3}{2}\) + (\(\dfrac{3}{2}\))² = - \(\dfrac{15}{4}\)  Hay ( \(x^2\) +\(\dfrac{3}{2}\) )²= -\(\dfrac{15}{4}\) (vô lí)

⇒x= 1 và x= 4

a) 95 + 11 x 206

= 95 + 2266 = 2361

b) 95 x 11 + 206

= 1045 + 206 = 1251

c) 95 x 11 x 206

= 1045 x 206 = 215270