Gải pt❤❤
giải pt
a) -3x\(^2\)+15x=0 b)2x\(^2\)-32=0 c)2x\(^2\)-5x+1=0
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\(a.-3x^2+15x=0\)
\(\Leftrightarrow3x\left(-x+5\right)=0\)
\(\Leftrightarrow\left[{}\begin{matrix}3x=0\\-x+5=0\end{matrix}\right.\)
\(\Leftrightarrow\left[{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
\(b.2x^2-32=0\)
\(\Leftrightarrow2x^2=32\)
\(\Leftrightarrow x^2=16\)
\(\Leftrightarrow\left|x\right|=4\)
\(\Leftrightarrow\left[{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(c.2x^2-5x+1=0\)
\(a=2;b=-5;c=1\)
\(\Delta=\left(-5\right)^2-4.2.1=17>0\)
Do \(\Delta>0\) nên phương trình có 2 nghiệm phân biệt:
\(x_1=\dfrac{5+\sqrt{17}}{4}\)
\(x_2=\dfrac{5-\sqrt{17}}{4}\)
\(a,-3x^2+15x=0\\ -3x\left(x-5\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x=0\\x-5=0\end{matrix}\right.\Leftrightarrow\left\{{}\begin{matrix}x=0\\x=5\end{matrix}\right.\)
\(b,\\ 2\left(x^2-16\right)=0\\ \Leftrightarrow x^2-16=0\\ \Leftrightarrow\left(x-4\right)\left(x+4\right)=0\\ \Rightarrow\left\{{}\begin{matrix}x=4\\x=-4\end{matrix}\right.\)
\(c,\\ \Delta=5^2-4.2=17\\ \Rightarrow x_1,x_2=\dfrac{\Delta\pm b}{2ac}\\ =\dfrac{5\pm\sqrt{17}}{4}\)
TRẢ LỜI CÂU HỎI GIÚP MK VS MN ƠI. THANKS MN NHÌU
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What is your zodiac sign ?
what grade are you in ?
are you bored?
trả lời câu hỏi nhé
What is your zodiac sign ?
My zodiac sign is scorpio.
What grade are you in ?
I'm in 9 grade.
Are you bored?
No, I'm not.
What is your zodiac sign ?
my zodiac sign is scorpio
what grade are you in ?
I'm in 9 grade
are you bored?
no, I'm not
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Cho A= 2000/2001 + 2001/2002
B= 2000+2001/2001+2002
Không quy đồng mà hãy so sánh A và B
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