[ 2314 - ( 346 + 2x ) ] + 124 = 2036

[ 2314 - ( 346 + 2x ) ] = 2036 - 124

[ 2314 - ( 346 + 2x ) ] = 1912

346 + 2x = 2314 - 1912

316 + 2x = 402

2x = 402 - 316

2x = 86

x = 86 : 2 

x = 43

[2314-(346+2x)]+124=2036

[2314-(346+2x)]=2036-134

[2314-(346+2x)]=1902

346+2x=2314-1902

346+2x=412

2x=412-346

2x=66

x=66/2

x=33

hok tốt

\(\left[2314-\left(346+2x\right)\right]+124=2036\)

\(2314-\left(346+2x\right)=2036-124\)

\(2314-\left(346+2x\right)=1912\)

\(346+2x=2314-1912\)

\(246+2x=402\)

\(2x=402-246\)

\(2x=156\)

\(x=156:2\)

\(x=78\)

11: Ta có: \(\left(x+3\right)^3=125\)

\(\Leftrightarrow x+3=5\)

hay x=2

12: Ta có: \(\left(2x\right)^4=16\)

\(\Leftrightarrow x^4=1\)

hay \(x\in\left\{1;-1\right\}\)

11: Ta có: \left(x+3\right)^3=125(x+3)3=125

$\iff x+3=5$

hay x=2

12: Ta có: \left(2x\right)^4=16(2x)4=16

\Leftrightarrow x^4=1(2x)   = 2   =2  4

           4      

⇔2x=2⇔ x=1

13) 32:(3x-2)=2^3

32:(3x-2)=8

3x-2=32:8=4

3x=4+2=6

x=6:3=2

⇔x=2

\(a,\left|2x-5\right|=1\)

\(\Rightarrow\orbr{\begin{cases}2x-5=1\\2x-5=-1\end{cases}\Rightarrow\orbr{\begin{cases}2x=6\\2x=4\end{cases}\Rightarrow}\orbr{\begin{cases}x=3\\x=2\end{cases}}}\)

b, đề thiếu 

À ý b, thiếu : [124-920-4x)]:30+7=11 như này là đề đúng

bn sửa hình như sai sai 

\(\left[124-\left(20-4x\right)\right]:30+7=11\)

\(\left[124-20+4x\right]:30=4\)

\(124-20+4x=120\)

\(104+4x=120\)

\(4x=16\)

\(x=4\)

  124 : 0,25 + 6 x 124 

= 124 : \(\frac{25}{100}\)+ 6 x 124

= 124 x \(\frac{100}{25}\)+ 6 x 124

= 124 x 4 + 6 x 124

= 124 x ( 4 + 6 )

= 124 x 10 

= 1240

124x4+6x124

124x(6+4)

124x10

1240

124 : 0,25 + 6 x 124

= 124 x 4 + 6 x 124

= 124 x ( 4 + 6 )

= 124 x 10

= 1240

\(\left(124-x\right)\times354=354\times28\)

\(\left(124-x\right)=354\times28\div354\)

\(124-x=28\)

\(x=124-28\)

\(x=96\)

cám ơn

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\left(\frac{x-152}{2011}-1\right)+\left(\frac{x-2135}{28}-1\right)+\left(\frac{x-2039}{124}-1\right)=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

<=> \(x-2163=0\)(vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

<=> \(x=2163\)

\(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}=3\)

<=> \(\frac{x-28-124}{2011}+\frac{x-124-2011}{28}+\frac{x-2011-28}{124}-3=0\)

<=> \(\left(\frac{x-28-124}{2011}-1\right)+\left(\frac{x-124-2011}{28}-1\right)+\left(\frac{x-2011-28}{124}-1\right)=0\)

<=> \(\frac{x-28-124-2011}{2011}+\frac{x-124-2011-28}{28}+\frac{x-2011-28-124}{124}=0\)

<=> \(\frac{x-2163}{2011}+\frac{x-2163}{28}+\frac{x-2163}{124}=0\)

<=> \(\left(x-2163\right)\left(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\right)=0\)

Vì \(\frac{1}{2011}+\frac{1}{28}+\frac{1}{124}\ne0\)

=> \(x-2163=0\)

=> \(x=2163\)

thanks!

Cảm ơn mọi người nhiều nhé!

124 x 25 + 24 x 124 + 50 + 124

= 124 x 25 + 50 ( 24 + 1 )

= 124 x ( 25 + 50 + 25 )

= 124 x 100

= 124000

Nhìn mà mún lòi cả con mắt hà

 câu này bó quá ... ko thể giải được

Bài làm

(4x - 124) - 316 = 144

 4x - 124            = 144 + 316

 4x - 124            = 460

 4x                     = 460 - 124 

 4x                     = 336

   x                     = 336 : 4

   x                     = 84

Vậy x = 84

(4x - 124) - 316 = 144

=> 4x - 124 = 460

=> 4x = 584

=> x = 146

a, Xét : \(\left(2x-1\right)^4=1\Leftrightarrow\orbr{\begin{cases}2x-1=1\\2x-1=-1\end{cases}\Leftrightarrow\orbr{\begin{cases}x=1\\x=0\end{cases}}}\)

Xét : \(\left(81.2\right)\left(x-2\right)^2=1\Leftrightarrow162\left(x-2\right)^2=1\Leftrightarrow\left(x-2\right)^2=\frac{1}{162}\)

\(\orbr{\begin{cases}x-2=\sqrt{\frac{1}{162}}\\x-2=-\sqrt{\frac{1}{162}}\end{cases}}\Leftrightarrow\orbr{\begin{cases}x=\frac{36+\sqrt{2}}{18}\\x=\frac{36-\sqrt{2}}{18}\end{cases}}\)